Integrand size = 14, antiderivative size = 48 \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=-\frac {1}{3 x^3}-\frac {i a}{x^2}+\frac {2 a^2}{x}-2 i a^3 \log (x)+2 i a^3 \log (i+a x) \]
[Out]
Time = 0.02 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {5170, 78} \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=-2 i a^3 \log (x)+2 i a^3 \log (a x+i)+\frac {2 a^2}{x}-\frac {i a}{x^2}-\frac {1}{3 x^3} \]
[In]
[Out]
Rule 78
Rule 5170
Rubi steps \begin{align*} \text {integral}& = \int \frac {1+i a x}{x^4 (1-i a x)} \, dx \\ & = \int \left (\frac {1}{x^4}+\frac {2 i a}{x^3}-\frac {2 a^2}{x^2}-\frac {2 i a^3}{x}+\frac {2 i a^4}{i+a x}\right ) \, dx \\ & = -\frac {1}{3 x^3}-\frac {i a}{x^2}+\frac {2 a^2}{x}-2 i a^3 \log (x)+2 i a^3 \log (i+a x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00 \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=-\frac {1}{3 x^3}-\frac {i a}{x^2}+\frac {2 a^2}{x}-2 i a^3 \log (x)+2 i a^3 \log (i+a x) \]
[In]
[Out]
Time = 0.26 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00
method | result | size |
parallelrisch | \(-\frac {6 i a^{3} \ln \left (x \right ) x^{3}-6 i a^{3} \ln \left (a x +i\right ) x^{3}+1-6 a^{2} x^{2}+3 i a x}{3 x^{3}}\) | \(48\) |
risch | \(\frac {2 a^{2} x^{2}-i a x -\frac {1}{3}}{x^{3}}-2 i a^{3} \ln \left (-x \right )+2 a^{3} \arctan \left (a x \right )+i a^{3} \ln \left (a^{2} x^{2}+1\right )\) | \(56\) |
default | \(-\frac {1}{3 x^{3}}-2 i a^{3} \ln \left (x \right )-\frac {i a}{x^{2}}+\frac {2 a^{2}}{x}+2 a^{4} \left (\frac {i \ln \left (a^{2} x^{2}+1\right )}{2 a}+\frac {\arctan \left (a x \right )}{a}\right )\) | \(60\) |
meijerg | \(\frac {a^{4} \left (\frac {2 a^{2}}{x \left (a^{2}\right )^{\frac {3}{2}}}-\frac {2}{3 x^{3} \left (a^{2}\right )^{\frac {3}{2}}}+\frac {2 a^{3} \arctan \left (a x \right )}{\left (a^{2}\right )^{\frac {3}{2}}}\right )}{2 \sqrt {a^{2}}}+i a^{3} \left (\ln \left (a^{2} x^{2}+1\right )-2 \ln \left (x \right )-\ln \left (a^{2}\right )-\frac {1}{a^{2} x^{2}}\right )-\frac {a^{4} \left (-\frac {2}{x \sqrt {a^{2}}}-\frac {2 a \arctan \left (a x \right )}{\sqrt {a^{2}}}\right )}{2 \sqrt {a^{2}}}\) | \(118\) |
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.98 \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=\frac {-6 i \, a^{3} x^{3} \log \left (x\right ) + 6 i \, a^{3} x^{3} \log \left (\frac {a x + i}{a}\right ) + 6 \, a^{2} x^{2} - 3 i \, a x - 1}{3 \, x^{3}} \]
[In]
[Out]
Time = 0.13 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.12 \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=- 2 a^{3} \left (i \log {\left (4 a^{4} x \right )} - i \log {\left (4 a^{4} x + 4 i a^{3} \right )}\right ) - \frac {- 6 a^{2} x^{2} + 3 i a x + 1}{3 x^{3}} \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.06 \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=2 \, a^{3} \arctan \left (a x\right ) + i \, a^{3} \log \left (a^{2} x^{2} + 1\right ) - 2 i \, a^{3} \log \left (x\right ) + \frac {6 \, a^{2} x^{2} - 3 i \, a x - 1}{3 \, x^{3}} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.81 \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=2 i \, a^{3} \log \left (a x + i\right ) - 2 i \, a^{3} \log \left ({\left | x \right |}\right ) + \frac {6 \, a^{2} x^{2} - 3 i \, a x - 1}{3 \, x^{3}} \]
[In]
[Out]
Time = 0.08 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.71 \[ \int \frac {e^{2 i \arctan (a x)}}{x^4} \, dx=4\,a^3\,\mathrm {atan}\left (2\,a\,x+1{}\mathrm {i}\right )-\frac {-2\,a^2\,x^2+a\,x\,1{}\mathrm {i}+\frac {1}{3}}{x^3} \]
[In]
[Out]