Integrand size = 8, antiderivative size = 81 \[ \int e^{n \arctan (a x)} \, dx=-\frac {2^{1-\frac {i n}{2}} (1-i a x)^{1+\frac {i n}{2}} \operatorname {Hypergeometric2F1}\left (1+\frac {i n}{2},\frac {i n}{2},2+\frac {i n}{2},\frac {1}{2} (1-i a x)\right )}{a (2 i-n)} \]
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Time = 0.01 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {5169, 71} \[ \int e^{n \arctan (a x)} \, dx=-\frac {2^{1-\frac {i n}{2}} (1-i a x)^{1+\frac {i n}{2}} \operatorname {Hypergeometric2F1}\left (\frac {i n}{2}+1,\frac {i n}{2},\frac {i n}{2}+2,\frac {1}{2} (1-i a x)\right )}{a (-n+2 i)} \]
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Rule 71
Rule 5169
Rubi steps \begin{align*} \text {integral}& = \int (1-i a x)^{\frac {i n}{2}} (1+i a x)^{-\frac {i n}{2}} \, dx \\ & = -\frac {2^{1-\frac {i n}{2}} (1-i a x)^{1+\frac {i n}{2}} \operatorname {Hypergeometric2F1}\left (1+\frac {i n}{2},\frac {i n}{2},2+\frac {i n}{2},\frac {1}{2} (1-i a x)\right )}{a (2 i-n)} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.69 \[ \int e^{n \arctan (a x)} \, dx=\frac {4 e^{(2 i+n) \arctan (a x)} \operatorname {Hypergeometric2F1}\left (2,1-\frac {i n}{2},2-\frac {i n}{2},-e^{2 i \arctan (a x)}\right )}{a (2 i+n)} \]
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\[\int {\mathrm e}^{n \arctan \left (a x \right )}d x\]
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\[ \int e^{n \arctan (a x)} \, dx=\int { e^{\left (n \arctan \left (a x\right )\right )} \,d x } \]
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\[ \int e^{n \arctan (a x)} \, dx=\int e^{n \operatorname {atan}{\left (a x \right )}}\, dx \]
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\[ \int e^{n \arctan (a x)} \, dx=\int { e^{\left (n \arctan \left (a x\right )\right )} \,d x } \]
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\[ \int e^{n \arctan (a x)} \, dx=\int { e^{\left (n \arctan \left (a x\right )\right )} \,d x } \]
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Timed out. \[ \int e^{n \arctan (a x)} \, dx=\int {\mathrm {e}}^{n\,\mathrm {atan}\left (a\,x\right )} \,d x \]
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