Integrand size = 16, antiderivative size = 170 \[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=-\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2}+\frac {11 a^2 (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{24 x}+\frac {3}{8} i a^3 \arctan \left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )+\frac {3}{8} i a^3 \text {arctanh}\left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right ) \]
[Out]
Time = 0.04 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5170, 101, 156, 12, 95, 218, 212, 209} \[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=\frac {3}{8} i a^3 \arctan \left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )+\frac {3}{8} i a^3 \text {arctanh}\left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )+\frac {11 a^2 (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{24 x}-\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2} \]
[In]
[Out]
Rule 12
Rule 95
Rule 101
Rule 156
Rule 209
Rule 212
Rule 218
Rule 5170
Rubi steps \begin{align*} \text {integral}& = \int \frac {\sqrt [4]{1+i a x}}{x^4 \sqrt [4]{1-i a x}} \, dx \\ & = -\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}+\frac {1}{3} \int \frac {\frac {5 i a}{2}-2 a^2 x}{x^3 \sqrt [4]{1-i a x} (1+i a x)^{3/4}} \, dx \\ & = -\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2}-\frac {1}{6} \int \frac {\frac {11 a^2}{4}+\frac {5}{2} i a^3 x}{x^2 \sqrt [4]{1-i a x} (1+i a x)^{3/4}} \, dx \\ & = -\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2}+\frac {11 a^2 (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{24 x}+\frac {1}{6} \int -\frac {9 i a^3}{8 x \sqrt [4]{1-i a x} (1+i a x)^{3/4}} \, dx \\ & = -\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2}+\frac {11 a^2 (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{24 x}-\frac {1}{16} \left (3 i a^3\right ) \int \frac {1}{x \sqrt [4]{1-i a x} (1+i a x)^{3/4}} \, dx \\ & = -\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2}+\frac {11 a^2 (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{24 x}-\frac {1}{4} \left (3 i a^3\right ) \text {Subst}\left (\int \frac {1}{-1+x^4} \, dx,x,\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right ) \\ & = -\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2}+\frac {11 a^2 (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{24 x}+\frac {1}{8} \left (3 i a^3\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )+\frac {1}{8} \left (3 i a^3\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right ) \\ & = -\frac {(1-i a x)^{3/4} \sqrt [4]{1+i a x}}{3 x^3}-\frac {5 i a (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{12 x^2}+\frac {11 a^2 (1-i a x)^{3/4} \sqrt [4]{1+i a x}}{24 x}+\frac {3}{8} i a^3 \arctan \left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )+\frac {3}{8} i a^3 \text {arctanh}\left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right ) \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.02 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.55 \[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=\frac {(1-i a x)^{3/4} \left (-8-18 i a x+21 a^2 x^2+11 i a^3 x^3+6 i a^3 x^3 \operatorname {Hypergeometric2F1}\left (\frac {3}{4},1,\frac {7}{4},\frac {i+a x}{i-a x}\right )\right )}{24 x^3 (1+i a x)^{3/4}} \]
[In]
[Out]
\[\int \frac {\sqrt {\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}}}{x^{4}}d x\]
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 184, normalized size of antiderivative = 1.08 \[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=\frac {9 i \, a^{3} x^{3} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} + 1\right ) - 9 \, a^{3} x^{3} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} + i\right ) + 9 \, a^{3} x^{3} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} - i\right ) - 9 i \, a^{3} x^{3} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} - 1\right ) - 2 \, {\left (11 i \, a^{3} x^{3} - a^{2} x^{2} + 2 i \, a x + 8\right )} \sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}}}{48 \, x^{3}} \]
[In]
[Out]
\[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=\int \frac {\sqrt {\frac {i \left (a x - i\right )}{\sqrt {a^{2} x^{2} + 1}}}}{x^{4}}\, dx \]
[In]
[Out]
\[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=\int { \frac {\sqrt {\frac {i \, a x + 1}{\sqrt {a^{2} x^{2} + 1}}}}{x^{4}} \,d x } \]
[In]
[Out]
Exception generated. \[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=\text {Exception raised: TypeError} \]
[In]
[Out]
Timed out. \[ \int \frac {e^{\frac {1}{2} i \arctan (a x)}}{x^4} \, dx=\int \frac {\sqrt {\frac {1+a\,x\,1{}\mathrm {i}}{\sqrt {a^2\,x^2+1}}}}{x^4} \,d x \]
[In]
[Out]