Integrand size = 12, antiderivative size = 102 \[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=\frac {i \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}+\frac {(c+d x) \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}-\frac {2 b \left (a+b \cot ^{-1}(c+d x)\right ) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}+\frac {i b^2 \operatorname {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{d} \]
[Out]
Time = 0.08 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5148, 4931, 5041, 4965, 2449, 2352} \[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=\frac {(c+d x) \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}+\frac {i \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}-\frac {2 b \log \left (\frac {2}{1+i (c+d x)}\right ) \left (a+b \cot ^{-1}(c+d x)\right )}{d}+\frac {i b^2 \operatorname {PolyLog}\left (2,1-\frac {2}{i (c+d x)+1}\right )}{d} \]
[In]
[Out]
Rule 2352
Rule 2449
Rule 4931
Rule 4965
Rule 5041
Rule 5148
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \left (a+b \cot ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d} \\ & = \frac {(c+d x) \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}+\frac {(2 b) \text {Subst}\left (\int \frac {x \left (a+b \cot ^{-1}(x)\right )}{1+x^2} \, dx,x,c+d x\right )}{d} \\ & = \frac {i \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}+\frac {(c+d x) \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}-\frac {(2 b) \text {Subst}\left (\int \frac {a+b \cot ^{-1}(x)}{i-x} \, dx,x,c+d x\right )}{d} \\ & = \frac {i \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}+\frac {(c+d x) \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}-\frac {2 b \left (a+b \cot ^{-1}(c+d x)\right ) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}-\frac {\left (2 b^2\right ) \text {Subst}\left (\int \frac {\log \left (\frac {2}{1+i x}\right )}{1+x^2} \, dx,x,c+d x\right )}{d} \\ & = \frac {i \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}+\frac {(c+d x) \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}-\frac {2 b \left (a+b \cot ^{-1}(c+d x)\right ) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}+\frac {\left (2 i b^2\right ) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+i (c+d x)}\right )}{d} \\ & = \frac {i \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}+\frac {(c+d x) \left (a+b \cot ^{-1}(c+d x)\right )^2}{d}-\frac {2 b \left (a+b \cot ^{-1}(c+d x)\right ) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}+\frac {i b^2 \operatorname {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{d} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 118, normalized size of antiderivative = 1.16 \[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=\frac {b^2 (i+c+d x) \cot ^{-1}(c+d x)^2+2 b \cot ^{-1}(c+d x) \left (a c+a d x-b \log \left (1-e^{2 i \cot ^{-1}(c+d x)}\right )\right )+a \left (a c+a d x-2 b \log \left (\frac {1}{(c+d x) \sqrt {1+\frac {1}{(c+d x)^2}}}\right )\right )+i b^2 \operatorname {PolyLog}\left (2,e^{2 i \cot ^{-1}(c+d x)}\right )}{d} \]
[In]
[Out]
Time = 0.84 (sec) , antiderivative size = 184, normalized size of antiderivative = 1.80
method | result | size |
parts | \(a^{2} x +\frac {b^{2} \left (\operatorname {arccot}\left (d x +c \right )^{2} \left (d x +c -i\right )-2 \,\operatorname {arccot}\left (d x +c \right ) \ln \left (1+\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )-2 \,\operatorname {arccot}\left (d x +c \right ) \ln \left (1-\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )+2 i \operatorname {arccot}\left (d x +c \right )^{2}+2 i \operatorname {polylog}\left (2, -\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )+2 i \operatorname {polylog}\left (2, \frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )\right )}{d}+\frac {2 a b \left (\operatorname {arccot}\left (d x +c \right ) \left (d x +c \right )+\frac {\ln \left (1+\left (d x +c \right )^{2}\right )}{2}\right )}{d}\) | \(184\) |
derivativedivides | \(\frac {\left (d x +c \right ) a^{2}+b^{2} \left (\operatorname {arccot}\left (d x +c \right )^{2} \left (d x +c -i\right )-2 \,\operatorname {arccot}\left (d x +c \right ) \ln \left (1+\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )-2 \,\operatorname {arccot}\left (d x +c \right ) \ln \left (1-\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )+2 i \operatorname {arccot}\left (d x +c \right )^{2}+2 i \operatorname {polylog}\left (2, -\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )+2 i \operatorname {polylog}\left (2, \frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )\right )+2 a b \,\operatorname {arccot}\left (d x +c \right ) \left (d x +c \right )+a b \ln \left (1+\left (d x +c \right )^{2}\right )}{d}\) | \(185\) |
default | \(\frac {\left (d x +c \right ) a^{2}+b^{2} \left (\operatorname {arccot}\left (d x +c \right )^{2} \left (d x +c -i\right )-2 \,\operatorname {arccot}\left (d x +c \right ) \ln \left (1+\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )-2 \,\operatorname {arccot}\left (d x +c \right ) \ln \left (1-\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )+2 i \operatorname {arccot}\left (d x +c \right )^{2}+2 i \operatorname {polylog}\left (2, -\frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )+2 i \operatorname {polylog}\left (2, \frac {d x +c +i}{\sqrt {1+\left (d x +c \right )^{2}}}\right )\right )+2 a b \,\operatorname {arccot}\left (d x +c \right ) \left (d x +c \right )+a b \ln \left (1+\left (d x +c \right )^{2}\right )}{d}\) | \(185\) |
risch | \(-\frac {\ln \left (-i d x -i c +1\right )^{2} b^{2} x}{4}+\frac {i a^{2}}{d}-\frac {b^{2} \arctan \left (d x +c \right ) \pi c}{2 d}-\frac {b \arctan \left (d x +c \right ) a c}{d}+\frac {\pi a b c}{d}+\frac {\pi ^{2} b^{2} x}{4}+\frac {b^{2} \ln \left (d^{2} x^{2}+2 c d x +c^{2}+1\right ) \pi }{4 d}+\frac {b \ln \left (d^{2} x^{2}+2 c d x +c^{2}+1\right ) a}{2 d}+a^{2} x +\frac {a^{2} c}{d}+\pi a b x +\left (\frac {b^{2} x \ln \left (1-i \left (d x +c \right )\right )}{2}+\frac {i b \left (\pi b d x +2 a x d +b \ln \left (1-i \left (d x +c \right )\right )-i \ln \left (1-i \left (d x +c \right )\right ) b c \right )}{2 d}\right ) \ln \left (1+i \left (d x +c \right )\right )-\frac {i \ln \left (-i d x -i c +1\right ) \pi \,b^{2} c}{2 d}-\frac {i \ln \left (-i d x -i c +1\right ) a b c}{d}+\frac {i b^{2} \ln \left (d^{2} x^{2}+2 c d x +c^{2}+1\right ) \pi c}{4 d}+\frac {i b \ln \left (d^{2} x^{2}+2 c d x +c^{2}+1\right ) a c}{2 d}+\frac {\pi ^{2} b^{2} c}{4 d}+\frac {i b^{2} \arctan \left (d x +c \right ) \pi }{2 d}+\frac {i b \arctan \left (d x +c \right ) a}{d}+\frac {i \pi a b}{d}-i \ln \left (-i d x -i c +1\right ) a b x -\frac {i \ln \left (-i d x -i c +1\right ) \pi \,b^{2} x}{2}+\frac {i b^{2} \ln \left (\frac {1}{2} i d x +\frac {1}{2} i c +\frac {1}{2}\right ) \ln \left (\frac {1}{2}-\frac {1}{2} i d x -\frac {1}{2} i c \right )}{d}-\frac {i b^{2} \ln \left (\frac {1}{2} i d x +\frac {1}{2} i c +\frac {1}{2}\right ) \ln \left (-i d x -i c +1\right )}{d}-\frac {b^{2} \left (d x +c -i\right ) \ln \left (1+i \left (d x +c \right )\right )^{2}}{4 d}+\frac {i b^{2} \operatorname {dilog}\left (\frac {1}{2}-\frac {1}{2} i d x -\frac {1}{2} i c \right )}{d}-\frac {\ln \left (-i d x -i c +1\right )^{2} b^{2} c}{4 d}+\frac {\ln \left (-i d x -i c +1\right ) \pi \,b^{2}}{2 d}+\frac {\ln \left (-i d x -i c +1\right ) a b}{d}-\frac {i \ln \left (-i d x -i c +1\right )^{2} b^{2}}{4 d}+\frac {i \pi ^{2} b^{2}}{4 d}\) | \(626\) |
[In]
[Out]
\[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=\int { {\left (b \operatorname {arccot}\left (d x + c\right ) + a\right )}^{2} \,d x } \]
[In]
[Out]
\[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=\int \left (a + b \operatorname {acot}{\left (c + d x \right )}\right )^{2}\, dx \]
[In]
[Out]
\[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=\int { {\left (b \operatorname {arccot}\left (d x + c\right ) + a\right )}^{2} \,d x } \]
[In]
[Out]
\[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=\int { {\left (b \operatorname {arccot}\left (d x + c\right ) + a\right )}^{2} \,d x } \]
[In]
[Out]
Time = 1.17 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.21 \[ \int \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx=a^2\,x+\frac {a\,b\,\left (\ln \left ({\left (c+d\,x\right )}^2+1\right )+2\,\mathrm {acot}\left (c+d\,x\right )\,\left (c+d\,x\right )\right )}{d}-\frac {2\,b^2\,\ln \left (1-{\mathrm {e}}^{\mathrm {acot}\left (c+d\,x\right )\,2{}\mathrm {i}}\right )\,\mathrm {acot}\left (c+d\,x\right )}{d}+\frac {b^2\,{\mathrm {acot}\left (c+d\,x\right )}^2\,\left (c+d\,x\right )}{d}+\frac {b^2\,\mathrm {polylog}\left (2,{\mathrm {e}}^{\mathrm {acot}\left (c+d\,x\right )\,2{}\mathrm {i}}\right )\,1{}\mathrm {i}}{d}+\frac {b^2\,{\mathrm {acot}\left (c+d\,x\right )}^2\,1{}\mathrm {i}}{d} \]
[In]
[Out]