Integrand size = 8, antiderivative size = 39 \[ \int x^2 \cot ^{-1}(a x) \, dx=\frac {x^2}{6 a}+\frac {1}{3} x^3 \cot ^{-1}(a x)-\frac {\log \left (1+a^2 x^2\right )}{6 a^3} \]
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Time = 0.02 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {4947, 272, 45} \[ \int x^2 \cot ^{-1}(a x) \, dx=-\frac {\log \left (a^2 x^2+1\right )}{6 a^3}+\frac {1}{3} x^3 \cot ^{-1}(a x)+\frac {x^2}{6 a} \]
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Rule 45
Rule 272
Rule 4947
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} x^3 \cot ^{-1}(a x)+\frac {1}{3} a \int \frac {x^3}{1+a^2 x^2} \, dx \\ & = \frac {1}{3} x^3 \cot ^{-1}(a x)+\frac {1}{6} a \text {Subst}\left (\int \frac {x}{1+a^2 x} \, dx,x,x^2\right ) \\ & = \frac {1}{3} x^3 \cot ^{-1}(a x)+\frac {1}{6} a \text {Subst}\left (\int \left (\frac {1}{a^2}-\frac {1}{a^2 \left (1+a^2 x\right )}\right ) \, dx,x,x^2\right ) \\ & = \frac {x^2}{6 a}+\frac {1}{3} x^3 \cot ^{-1}(a x)-\frac {\log \left (1+a^2 x^2\right )}{6 a^3} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.00 \[ \int x^2 \cot ^{-1}(a x) \, dx=\frac {x^2}{6 a}+\frac {1}{3} x^3 \cot ^{-1}(a x)-\frac {\log \left (1+a^2 x^2\right )}{6 a^3} \]
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Time = 0.11 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.95
method | result | size |
parallelrisch | \(-\frac {-2 a^{3} x^{3} \operatorname {arccot}\left (a x \right )-a^{2} x^{2}+\ln \left (a^{2} x^{2}+1\right )}{6 a^{3}}\) | \(37\) |
derivativedivides | \(\frac {\frac {a^{3} x^{3} \operatorname {arccot}\left (a x \right )}{3}+\frac {a^{2} x^{2}}{6}-\frac {\ln \left (a^{2} x^{2}+1\right )}{6}}{a^{3}}\) | \(38\) |
default | \(\frac {\frac {a^{3} x^{3} \operatorname {arccot}\left (a x \right )}{3}+\frac {a^{2} x^{2}}{6}-\frac {\ln \left (a^{2} x^{2}+1\right )}{6}}{a^{3}}\) | \(38\) |
parts | \(\frac {x^{3} \operatorname {arccot}\left (a x \right )}{3}+\frac {a \left (\frac {x^{2}}{2 a^{2}}-\frac {\ln \left (a^{2} x^{2}+1\right )}{2 a^{4}}\right )}{3}\) | \(38\) |
risch | \(\frac {i x^{3} \ln \left (i a x +1\right )}{6}-\frac {i x^{3} \ln \left (-i a x +1\right )}{6}+\frac {\pi \,x^{3}}{6}+\frac {x^{2}}{6 a}-\frac {\ln \left (-a^{2} x^{2}-1\right )}{6 a^{3}}\) | \(60\) |
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Time = 0.29 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.95 \[ \int x^2 \cot ^{-1}(a x) \, dx=\frac {2 \, a^{3} x^{3} \operatorname {arccot}\left (a x\right ) + a^{2} x^{2} - \log \left (a^{2} x^{2} + 1\right )}{6 \, a^{3}} \]
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Time = 0.19 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.95 \[ \int x^2 \cot ^{-1}(a x) \, dx=\begin {cases} \frac {x^{3} \operatorname {acot}{\left (a x \right )}}{3} + \frac {x^{2}}{6 a} - \frac {\log {\left (a^{2} x^{2} + 1 \right )}}{6 a^{3}} & \text {for}\: a \neq 0 \\\frac {\pi x^{3}}{6} & \text {otherwise} \end {cases} \]
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Time = 0.18 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.92 \[ \int x^2 \cot ^{-1}(a x) \, dx=\frac {1}{3} \, x^{3} \operatorname {arccot}\left (a x\right ) + \frac {1}{6} \, a {\left (\frac {x^{2}}{a^{2}} - \frac {\log \left (a^{2} x^{2} + 1\right )}{a^{4}}\right )} \]
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Time = 0.27 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.64 \[ \int x^2 \cot ^{-1}(a x) \, dx=\frac {1}{6} \, {\left (\frac {2 \, x^{3} \arctan \left (\frac {1}{a x}\right )}{a} - \frac {x^{2} {\left (\frac {1}{a^{2} x^{2}} - 1\right )}}{a^{2}} - \frac {\log \left (\frac {1}{a^{2} x^{2}} + 1\right )}{a^{4}} + \frac {\log \left (\frac {1}{a^{2} x^{2}}\right )}{a^{4}}\right )} a \]
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Time = 0.81 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.26 \[ \int x^2 \cot ^{-1}(a x) \, dx=\left \{\begin {array}{cl} \frac {\pi \,x^3}{6} & \text {\ if\ \ }a=0\\ \frac {\frac {x^2}{2}-\frac {\ln \left (a^2\,x^2+1\right )}{2\,a^2}}{3\,a}+\frac {x^3\,\mathrm {acot}\left (a\,x\right )}{3} & \text {\ if\ \ }a\neq 0 \end {array}\right . \]
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