Integrand size = 15, antiderivative size = 79 \[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=\frac {1}{2} i b x^2+x \cot ^{-1}(c+(i+c) \tanh (a+b x))-\frac {1}{2} i x \log \left (1+i c e^{2 a+2 b x}\right )-\frac {i \operatorname {PolyLog}\left (2,-i c e^{2 a+2 b x}\right )}{4 b} \]
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Time = 0.08 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {5296, 2215, 2221, 2317, 2438} \[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=-\frac {i \operatorname {PolyLog}\left (2,-i c e^{2 a+2 b x}\right )}{4 b}-\frac {1}{2} i x \log \left (1+i c e^{2 a+2 b x}\right )+x \cot ^{-1}(c+(c+i) \tanh (a+b x))+\frac {1}{2} i b x^2 \]
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Rule 2215
Rule 2221
Rule 2317
Rule 2438
Rule 5296
Rubi steps \begin{align*} \text {integral}& = x \cot ^{-1}(c+(i+c) \tanh (a+b x))+b \int \frac {x}{-i+c e^{2 a+2 b x}} \, dx \\ & = \frac {1}{2} i b x^2+x \cot ^{-1}(c+(i+c) \tanh (a+b x))-(i b c) \int \frac {e^{2 a+2 b x} x}{-i+c e^{2 a+2 b x}} \, dx \\ & = \frac {1}{2} i b x^2+x \cot ^{-1}(c+(i+c) \tanh (a+b x))-\frac {1}{2} i x \log \left (1+i c e^{2 a+2 b x}\right )+\frac {1}{2} i \int \log \left (1+i c e^{2 a+2 b x}\right ) \, dx \\ & = \frac {1}{2} i b x^2+x \cot ^{-1}(c+(i+c) \tanh (a+b x))-\frac {1}{2} i x \log \left (1+i c e^{2 a+2 b x}\right )+\frac {i \text {Subst}\left (\int \frac {\log (1+i c x)}{x} \, dx,x,e^{2 a+2 b x}\right )}{4 b} \\ & = \frac {1}{2} i b x^2+x \cot ^{-1}(c+(i+c) \tanh (a+b x))-\frac {1}{2} i x \log \left (1+i c e^{2 a+2 b x}\right )-\frac {i \operatorname {PolyLog}\left (2,-i c e^{2 a+2 b x}\right )}{4 b} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.90 \[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=x \cot ^{-1}(c+(i+c) \tanh (a+b x))-\frac {i \left (2 b x \log \left (1-\frac {i e^{-2 (a+b x)}}{c}\right )-\operatorname {PolyLog}\left (2,\frac {i e^{-2 (a+b x)}}{c}\right )\right )}{4 b} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 543 vs. \(2 (65 ) = 130\).
Time = 1.83 (sec) , antiderivative size = 544, normalized size of antiderivative = 6.89
method | result | size |
derivativedivides | \(\frac {-\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2 i+2 c}+\frac {2 i \operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) c}{2 i+2 c}+\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) c^{2}}{2 i+2 c}+\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right )}{2 i+2 c}-\frac {2 i \operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) c}{2 i+2 c}-\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) c^{2}}{2 i+2 c}+\left (i+c \right )^{2} \left (\frac {-\frac {i \left (\left (\ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )-\ln \left (-\frac {i \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2}\right )\right ) \ln \left (-\frac {i \left (i-c -\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2}\right )-\operatorname {dilog}\left (-\frac {i \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2}\right )\right )}{2}+\frac {i \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )^{2}}{4}}{2 i+2 c}-\frac {-\frac {i \left (\operatorname {dilog}\left (-\frac {i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{2 c}\right )+\ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) \ln \left (-\frac {i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{2 c}\right )\right )}{2}+\frac {i \left (\operatorname {dilog}\left (\frac {-i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{-2 i-2 c}\right )+\ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) \ln \left (\frac {-i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{-2 i-2 c}\right )\right )}{2}}{2 \left (i+c \right )}\right )}{b \left (i+c \right )}\) | \(544\) |
default | \(\frac {-\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2 i+2 c}+\frac {2 i \operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) c}{2 i+2 c}+\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) c^{2}}{2 i+2 c}+\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right )}{2 i+2 c}-\frac {2 i \operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) c}{2 i+2 c}-\frac {\operatorname {arccot}\left (c +\left (i+c \right ) \tanh \left (b x +a \right )\right ) \ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) c^{2}}{2 i+2 c}+\left (i+c \right )^{2} \left (\frac {-\frac {i \left (\left (\ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )-\ln \left (-\frac {i \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2}\right )\right ) \ln \left (-\frac {i \left (i-c -\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2}\right )-\operatorname {dilog}\left (-\frac {i \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )}{2}\right )\right )}{2}+\frac {i \ln \left (i+c +\left (i+c \right ) \tanh \left (b x +a \right )\right )^{2}}{4}}{2 i+2 c}-\frac {-\frac {i \left (\operatorname {dilog}\left (-\frac {i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{2 c}\right )+\ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) \ln \left (-\frac {i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{2 c}\right )\right )}{2}+\frac {i \left (\operatorname {dilog}\left (\frac {-i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{-2 i-2 c}\right )+\ln \left (c -\left (i+c \right ) \tanh \left (b x +a \right )+i\right ) \ln \left (\frac {-i-c -\left (i+c \right ) \tanh \left (b x +a \right )}{-2 i-2 c}\right )\right )}{2}}{2 \left (i+c \right )}\right )}{b \left (i+c \right )}\) | \(544\) |
risch | \(\text {Expression too large to display}\) | \(1217\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 186 vs. \(2 (58) = 116\).
Time = 0.27 (sec) , antiderivative size = 186, normalized size of antiderivative = 2.35 \[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=\frac {i \, b^{2} x^{2} + i \, b x \log \left (\frac {{\left (c e^{\left (2 \, b x + 2 \, a\right )} - i\right )} e^{\left (-2 \, b x - 2 \, a\right )}}{c + i}\right ) - i \, a^{2} + {\left (-i \, b x - i \, a\right )} \log \left (\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )} + 1\right ) + {\left (-i \, b x - i \, a\right )} \log \left (-\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )} + 1\right ) + i \, a \log \left (\frac {2 \, c e^{\left (b x + a\right )} + i \, \sqrt {-4 i \, c}}{2 \, c}\right ) + i \, a \log \left (\frac {2 \, c e^{\left (b x + a\right )} - i \, \sqrt {-4 i \, c}}{2 \, c}\right ) - i \, {\rm Li}_2\left (\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )}\right ) - i \, {\rm Li}_2\left (-\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )}\right )}{2 \, b} \]
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Exception generated. \[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=\text {Exception raised: CoercionFailed} \]
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none
Time = 1.31 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.01 \[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=-2 \, b {\left (c + i\right )} {\left (\frac {2 \, x^{2}}{2 i \, c - 2} - \frac {2 \, b x \log \left (i \, c e^{\left (2 \, b x + 2 \, a\right )} + 1\right ) + {\rm Li}_2\left (-i \, c e^{\left (2 \, b x + 2 \, a\right )}\right )}{-2 \, b^{2} {\left (-i \, c + 1\right )}}\right )} + x \operatorname {arccot}\left ({\left (c + i\right )} \tanh \left (b x + a\right ) + c\right ) \]
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\[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=\int { \operatorname {arccot}\left ({\left (c + i\right )} \tanh \left (b x + a\right ) + c\right ) \,d x } \]
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Timed out. \[ \int \cot ^{-1}(c+(i+c) \tanh (a+b x)) \, dx=\int \mathrm {acot}\left (c+\mathrm {tanh}\left (a+b\,x\right )\,\left (c+1{}\mathrm {i}\right )\right ) \,d x \]
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