\(\int x \cot ^{-1}(a+b f^{c+d x}) \, dx\) [225]

Optimal result

Integrand size = 14, antiderivative size = 250 \[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=-\frac {1}{4} i x^2 \log \left (1-\frac {b f^{c+d x}}{i-a}\right )+\frac {1}{4} i x^2 \log \left (1+\frac {b f^{c+d x}}{i+a}\right )+\frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )-\frac {i x \operatorname {PolyLog}\left (2,\frac {b f^{c+d x}}{i-a}\right )}{2 d \log (f)}+\frac {i x \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{i+a}\right )}{2 d \log (f)}+\frac {i \operatorname {PolyLog}\left (3,\frac {b f^{c+d x}}{i-a}\right )}{2 d^2 \log ^2(f)}-\frac {i \operatorname {PolyLog}\left (3,-\frac {b f^{c+d x}}{i+a}\right )}{2 d^2 \log ^2(f)} \]

[Out]

-1/4*I*x^2*ln(1-b*f^(d*x+c)/(I-a))+1/4*I*x^2*ln(1+b*f^(d*x+c)/(I+a))+1/4*I*x^2*ln(1-I/(a+b*f^(d*x+c)))-1/4*I*x
^2*ln(1+I/(a+b*f^(d*x+c)))-1/2*I*x*polylog(2,b*f^(d*x+c)/(I-a))/d/ln(f)+1/2*I*x*polylog(2,-b*f^(d*x+c)/(I+a))/
d/ln(f)+1/2*I*polylog(3,b*f^(d*x+c)/(I-a))/d^2/ln(f)^2-1/2*I*polylog(3,-b*f^(d*x+c)/(I+a))/d^2/ln(f)^2

Rubi [A] (verified)

Time = 1.93 (sec) , antiderivative size = 250, normalized size of antiderivative = 1.00, number of steps used = 25, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.571, Rules used = {5252, 2631, 12, 6874, 2221, 2611, 2320, 6724} \[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=\frac {i \operatorname {PolyLog}\left (3,\frac {b f^{c+d x}}{i-a}\right )}{2 d^2 \log ^2(f)}-\frac {i \operatorname {PolyLog}\left (3,-\frac {b f^{c+d x}}{a+i}\right )}{2 d^2 \log ^2(f)}-\frac {i x \operatorname {PolyLog}\left (2,\frac {b f^{c+d x}}{i-a}\right )}{2 d \log (f)}+\frac {i x \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{a+i}\right )}{2 d \log (f)}-\frac {1}{4} i x^2 \log \left (1-\frac {b f^{c+d x}}{-a+i}\right )+\frac {1}{4} i x^2 \log \left (1+\frac {b f^{c+d x}}{a+i}\right )+\frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right ) \]

[In]

Int[x*ArcCot[a + b*f^(c + d*x)],x]

[Out]

(-1/4*I)*x^2*Log[1 - (b*f^(c + d*x))/(I - a)] + (I/4)*x^2*Log[1 + (b*f^(c + d*x))/(I + a)] + (I/4)*x^2*Log[1 -
I/(a + b*f^(c + d*x))] - (I/4)*x^2*Log[1 + I/(a + b*f^(c + d*x))] - ((I/2)*x*PolyLog[2, (b*f^(c + d*x))/(I -
a)])/(d*Log[f]) + ((I/2)*x*PolyLog[2, -((b*f^(c + d*x))/(I + a))])/(d*Log[f]) + ((I/2)*PolyLog[3, (b*f^(c + d*
x))/(I - a)])/(d^2*Log[f]^2) - ((I/2)*PolyLog[3, -((b*f^(c + d*x))/(I + a))])/(d^2*Log[f]^2)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2221

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
(f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x]
- Dist[d*(m/(b*f*g*n*Log[F])), Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2320

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rule 2611

Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(-(
f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Dist[g*(m/(b*c*n*Log[F])), Int[(f + g*
x)^(m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e, f, g, n}, x] && GtQ[m, 0]

Rule 2631

Int[Log[u_]*((a_.) + (b_.)*(x_))^(m_.), x_Symbol] :> Simp[(a + b*x)^(m + 1)*(Log[u]/(b*(m + 1))), x] - Dist[1/
(b*(m + 1)), Int[SimplifyIntegrand[(a + b*x)^(m + 1)*(D[u, x]/u), x], x], x] /; FreeQ[{a, b, m}, x] && Inverse
FunctionFreeQ[u, x] && NeQ[m, -1]

Rule 5252

Int[ArcCot[(a_.) + (b_.)*(f_)^((c_.) + (d_.)*(x_))]*(x_)^(m_.), x_Symbol] :> Dist[I/2, Int[x^m*Log[1 - I/(a +
b*f^(c + d*x))], x], x] - Dist[I/2, Int[x^m*Log[1 + I/(a + b*f^(c + d*x))], x], x] /; FreeQ[{a, b, c, d, f}, x
] && IntegerQ[m] && m > 0

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rule 6874

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v]]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} i \int x \log \left (1-\frac {i}{a+b f^{c+d x}}\right ) \, dx-\frac {1}{2} i \int x \log \left (1+\frac {i}{a+b f^{c+d x}}\right ) \, dx \\ & = \frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )+\frac {1}{4} \int \frac {b d f^{c+d x} x^2 \log (f)}{\left (i (1-i a)+b f^{c+d x}\right ) \left (a+b f^{c+d x}\right )} \, dx+\frac {1}{4} \int \frac {b d f^{c+d x} x^2 \log (f)}{\left (-i (1+i a)+b f^{c+d x}\right ) \left (a+b f^{c+d x}\right )} \, dx \\ & = \frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )+\frac {1}{4} (b d \log (f)) \int \frac {f^{c+d x} x^2}{\left (i (1-i a)+b f^{c+d x}\right ) \left (a+b f^{c+d x}\right )} \, dx+\frac {1}{4} (b d \log (f)) \int \frac {f^{c+d x} x^2}{\left (-i (1+i a)+b f^{c+d x}\right ) \left (a+b f^{c+d x}\right )} \, dx \\ & = \frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )+\frac {1}{4} (b d \log (f)) \int \left (\frac {i f^{c+d x} x^2}{a+b f^{c+d x}}-\frac {i f^{c+d x} x^2}{-i+a+b f^{c+d x}}\right ) \, dx+\frac {1}{4} (b d \log (f)) \int \left (-\frac {i f^{c+d x} x^2}{a+b f^{c+d x}}+\frac {i f^{c+d x} x^2}{i+a+b f^{c+d x}}\right ) \, dx \\ & = \frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} (i b d \log (f)) \int \frac {f^{c+d x} x^2}{-i+a+b f^{c+d x}} \, dx+\frac {1}{4} (i b d \log (f)) \int \frac {f^{c+d x} x^2}{i+a+b f^{c+d x}} \, dx \\ & = -\frac {1}{4} i x^2 \log \left (1-\frac {b f^{c+d x}}{i-a}\right )+\frac {1}{4} i x^2 \log \left (1+\frac {b f^{c+d x}}{i+a}\right )+\frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )+\frac {1}{2} i \int x \log \left (1+\frac {b f^{c+d x}}{-i+a}\right ) \, dx-\frac {1}{2} i \int x \log \left (1+\frac {b f^{c+d x}}{i+a}\right ) \, dx \\ & = -\frac {1}{4} i x^2 \log \left (1-\frac {b f^{c+d x}}{i-a}\right )+\frac {1}{4} i x^2 \log \left (1+\frac {b f^{c+d x}}{i+a}\right )+\frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )-\frac {i x \operatorname {PolyLog}\left (2,\frac {b f^{c+d x}}{i-a}\right )}{2 d \log (f)}+\frac {i x \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{i+a}\right )}{2 d \log (f)}+\frac {i \int \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{-i+a}\right ) \, dx}{2 d \log (f)}-\frac {i \int \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{i+a}\right ) \, dx}{2 d \log (f)} \\ & = -\frac {1}{4} i x^2 \log \left (1-\frac {b f^{c+d x}}{i-a}\right )+\frac {1}{4} i x^2 \log \left (1+\frac {b f^{c+d x}}{i+a}\right )+\frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )-\frac {i x \operatorname {PolyLog}\left (2,\frac {b f^{c+d x}}{i-a}\right )}{2 d \log (f)}+\frac {i x \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{i+a}\right )}{2 d \log (f)}+\frac {i \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (2,\frac {b x}{i-a}\right )}{x} \, dx,x,f^{c+d x}\right )}{2 d^2 \log ^2(f)}-\frac {i \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (2,-\frac {b x}{i+a}\right )}{x} \, dx,x,f^{c+d x}\right )}{2 d^2 \log ^2(f)} \\ & = -\frac {1}{4} i x^2 \log \left (1-\frac {b f^{c+d x}}{i-a}\right )+\frac {1}{4} i x^2 \log \left (1+\frac {b f^{c+d x}}{i+a}\right )+\frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )-\frac {i x \operatorname {PolyLog}\left (2,\frac {b f^{c+d x}}{i-a}\right )}{2 d \log (f)}+\frac {i x \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{i+a}\right )}{2 d \log (f)}+\frac {i \operatorname {PolyLog}\left (3,\frac {b f^{c+d x}}{i-a}\right )}{2 d^2 \log ^2(f)}-\frac {i \operatorname {PolyLog}\left (3,-\frac {b f^{c+d x}}{i+a}\right )}{2 d^2 \log ^2(f)} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.29 (sec) , antiderivative size = 250, normalized size of antiderivative = 1.00 \[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=-\frac {1}{4} i x^2 \log \left (1-\frac {b f^{c+d x}}{i-a}\right )+\frac {1}{4} i x^2 \log \left (1+\frac {b f^{c+d x}}{i+a}\right )+\frac {1}{4} i x^2 \log \left (1-\frac {i}{a+b f^{c+d x}}\right )-\frac {1}{4} i x^2 \log \left (1+\frac {i}{a+b f^{c+d x}}\right )-\frac {i x \operatorname {PolyLog}\left (2,\frac {b f^{c+d x}}{i-a}\right )}{2 d \log (f)}+\frac {i x \operatorname {PolyLog}\left (2,-\frac {b f^{c+d x}}{i+a}\right )}{2 d \log (f)}+\frac {i \operatorname {PolyLog}\left (3,\frac {b f^{c+d x}}{i-a}\right )}{2 d^2 \log ^2(f)}-\frac {i \operatorname {PolyLog}\left (3,-\frac {b f^{c+d x}}{i+a}\right )}{2 d^2 \log ^2(f)} \]

[In]

Integrate[x*ArcCot[a + b*f^(c + d*x)],x]

[Out]

(-1/4*I)*x^2*Log[1 - (b*f^(c + d*x))/(I - a)] + (I/4)*x^2*Log[1 + (b*f^(c + d*x))/(I + a)] + (I/4)*x^2*Log[1 -
I/(a + b*f^(c + d*x))] - (I/4)*x^2*Log[1 + I/(a + b*f^(c + d*x))] - ((I/2)*x*PolyLog[2, (b*f^(c + d*x))/(I -
a)])/(d*Log[f]) + ((I/2)*x*PolyLog[2, -((b*f^(c + d*x))/(I + a))])/(d*Log[f]) + ((I/2)*PolyLog[3, (b*f^(c + d*
x))/(I - a)])/(d^2*Log[f]^2) - ((I/2)*PolyLog[3, -((b*f^(c + d*x))/(I + a))])/(d^2*Log[f]^2)

Maple [B] (verified)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 677 vs. \(2 (218 ) = 436\).

Time = 1.04 (sec) , antiderivative size = 678, normalized size of antiderivative = 2.71

method	result	size
risch	\(-\frac {i x^{2} \ln \left (1-i \left (a +b \,f^{d x +c}\right )\right )}{4}+\frac {\pi \,x^{2}}{4}-\frac {i c \ln \left (\frac {b \,f^{d x} f^{c}+a +i}{i+a}\right ) x}{2 d}-\frac {i \operatorname {polylog}\left (2, \frac {i b \,f^{d x} f^{c}}{-i a -1}\right ) c}{2 \ln \left (f \right ) d^{2}}+\frac {i c \ln \left (\frac {b \,f^{d x} f^{c}+a -i}{a -i}\right ) x}{2 d}+\frac {i c^{2} \ln \left (1-i a -i f^{d x} f^{c} b \right )}{4 d^{2}}-\frac {i c \operatorname {dilog}\left (\frac {b \,f^{d x} f^{c}+a +i}{i+a}\right )}{2 \ln \left (f \right ) d^{2}}+\frac {i x^{2} \ln \left (1+i \left (a +b \,f^{d x +c}\right )\right )}{4}+\frac {i \operatorname {polylog}\left (2, \frac {i b \,f^{d x} f^{c}}{-i a +1}\right ) c}{2 \ln \left (f \right ) d^{2}}-\frac {i \ln \left (1-\frac {i b \,f^{d x} f^{c}}{-i a -1}\right ) x^{2}}{4}-\frac {i \ln \left (1-\frac {i b \,f^{d x} f^{c}}{-i a -1}\right ) c^{2}}{4 d^{2}}+\frac {i \ln \left (1-\frac {i b \,f^{d x} f^{c}}{-i a +1}\right ) c x}{2 d}+\frac {i \operatorname {polylog}\left (3, \frac {i b \,f^{d x} f^{c}}{-i a -1}\right )}{2 \ln \left (f \right )^{2} d^{2}}+\frac {i \operatorname {polylog}\left (2, \frac {i b \,f^{d x} f^{c}}{-i a +1}\right ) x}{2 \ln \left (f \right ) d}-\frac {i c^{2} \ln \left (i f^{d x} f^{c} b +i a +1\right )}{4 d^{2}}-\frac {i c^{2} \ln \left (\frac {b \,f^{d x} f^{c}+a +i}{i+a}\right )}{2 d^{2}}+\frac {i c^{2} \ln \left (\frac {b \,f^{d x} f^{c}+a -i}{a -i}\right )}{2 d^{2}}-\frac {i \operatorname {polylog}\left (2, \frac {i b \,f^{d x} f^{c}}{-i a -1}\right ) x}{2 \ln \left (f \right ) d}-\frac {i \operatorname {polylog}\left (3, \frac {i b \,f^{d x} f^{c}}{-i a +1}\right )}{2 \ln \left (f \right )^{2} d^{2}}-\frac {i \ln \left (1-\frac {i b \,f^{d x} f^{c}}{-i a -1}\right ) c x}{2 d}+\frac {i \ln \left (1-\frac {i b \,f^{d x} f^{c}}{-i a +1}\right ) c^{2}}{4 d^{2}}+\frac {i \ln \left (1-\frac {i b \,f^{d x} f^{c}}{-i a +1}\right ) x^{2}}{4}+\frac {i c \operatorname {dilog}\left (\frac {b \,f^{d x} f^{c}+a -i}{a -i}\right )}{2 \ln \left (f \right ) d^{2}}\)	\(678\)

[In]

int(x*arccot(a+b*f^(d*x+c)),x,method=_RETURNVERBOSE)

[Out]

-1/4*I*x^2*ln(1-I*(a+b*f^(d*x+c)))+1/4*Pi*x^2-1/2*I/d*c*ln((b*f^(d*x)*f^c+a+I)/(I+a))*x-1/2*I/ln(f)/d^2*polylo
g(2,I*b/(-I*a-1)*f^(d*x)*f^c)*c+1/2*I/d*c*ln((b*f^(d*x)*f^c+a-I)/(a-I))*x+1/4*I/d^2*c^2*ln(1-I*a-I*f^(d*x)*f^c
*b)-1/2*I/ln(f)/d^2*c*dilog((b*f^(d*x)*f^c+a+I)/(I+a))+1/4*I*x^2*ln(1+I*(a+b*f^(d*x+c)))+1/2*I/ln(f)/d^2*polyl
og(2,I*b/(1-I*a)*f^(d*x)*f^c)*c-1/4*I*ln(1-I*b/(-I*a-1)*f^(d*x)*f^c)*x^2-1/4*I/d^2*ln(1-I*b/(-I*a-1)*f^(d*x)*f
^c)*c^2+1/2*I/d*ln(1-I*b/(1-I*a)*f^(d*x)*f^c)*c*x+1/2*I/ln(f)^2/d^2*polylog(3,I*b/(-I*a-1)*f^(d*x)*f^c)+1/2*I/
ln(f)/d*polylog(2,I*b/(1-I*a)*f^(d*x)*f^c)*x-1/4*I/d^2*c^2*ln(I*f^(d*x)*f^c*b+I*a+1)-1/2*I/d^2*c^2*ln((b*f^(d*
x)*f^c+a+I)/(I+a))+1/2*I/d^2*c^2*ln((b*f^(d*x)*f^c+a-I)/(a-I))-1/2*I/ln(f)/d*polylog(2,I*b/(-I*a-1)*f^(d*x)*f^
c)*x-1/2*I/ln(f)^2/d^2*polylog(3,I*b/(1-I*a)*f^(d*x)*f^c)-1/2*I/d*ln(1-I*b/(-I*a-1)*f^(d*x)*f^c)*c*x+1/4*I/d^2
*ln(1-I*b/(1-I*a)*f^(d*x)*f^c)*c^2+1/4*I*ln(1-I*b/(1-I*a)*f^(d*x)*f^c)*x^2+1/2*I/ln(f)/d^2*c*dilog((b*f^(d*x)*
f^c+a-I)/(a-I))

Fricas [A] (verification not implemented)

none

Time = 0.30 (sec) , antiderivative size = 304, normalized size of antiderivative = 1.22 \[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=\frac {2 \, d^{2} x^{2} \operatorname {arccot}\left (b f^{d x + c} + a\right ) \log \left (f\right )^{2} + i \, c^{2} \log \left (b f^{d x + c} + a + i\right ) \log \left (f\right )^{2} - i \, c^{2} \log \left (b f^{d x + c} + a - i\right ) \log \left (f\right )^{2} - 2 i \, d x {\rm Li}_2\left (-\frac {a^{2} + {\left (a b + i \, b\right )} f^{d x + c} + 1}{a^{2} + 1} + 1\right ) \log \left (f\right ) + 2 i \, d x {\rm Li}_2\left (-\frac {a^{2} + {\left (a b - i \, b\right )} f^{d x + c} + 1}{a^{2} + 1} + 1\right ) \log \left (f\right ) + {\left (-i \, d^{2} x^{2} + i \, c^{2}\right )} \log \left (f\right )^{2} \log \left (\frac {a^{2} + {\left (a b + i \, b\right )} f^{d x + c} + 1}{a^{2} + 1}\right ) + {\left (i \, d^{2} x^{2} - i \, c^{2}\right )} \log \left (f\right )^{2} \log \left (\frac {a^{2} + {\left (a b - i \, b\right )} f^{d x + c} + 1}{a^{2} + 1}\right ) + 2 i \, {\rm polylog}\left (3, -\frac {{\left (a b + i \, b\right )} f^{d x + c}}{a^{2} + 1}\right ) - 2 i \, {\rm polylog}\left (3, -\frac {{\left (a b - i \, b\right )} f^{d x + c}}{a^{2} + 1}\right )}{4 \, d^{2} \log \left (f\right )^{2}} \]

[In]

integrate(x*arccot(a+b*f^(d*x+c)),x, algorithm="fricas")

[Out]

1/4*(2*d^2*x^2*arccot(b*f^(d*x + c) + a)*log(f)^2 + I*c^2*log(b*f^(d*x + c) + a + I)*log(f)^2 - I*c^2*log(b*f^
(d*x + c) + a - I)*log(f)^2 - 2*I*d*x*dilog(-(a^2 + (a*b + I*b)*f^(d*x + c) + 1)/(a^2 + 1) + 1)*log(f) + 2*I*d
*x*dilog(-(a^2 + (a*b - I*b)*f^(d*x + c) + 1)/(a^2 + 1) + 1)*log(f) + (-I*d^2*x^2 + I*c^2)*log(f)^2*log((a^2 +
(a*b + I*b)*f^(d*x + c) + 1)/(a^2 + 1)) + (I*d^2*x^2 - I*c^2)*log(f)^2*log((a^2 + (a*b - I*b)*f^(d*x + c) + 1
)/(a^2 + 1)) + 2*I*polylog(3, -(a*b + I*b)*f^(d*x + c)/(a^2 + 1)) - 2*I*polylog(3, -(a*b - I*b)*f^(d*x + c)/(a
^2 + 1)))/(d^2*log(f)^2)

Sympy [F]

\[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=\int x \operatorname {acot}{\left (a + b f^{c + d x} \right )}\, dx \]

[In]

integrate(x*acot(a+b*f**(d*x+c)),x)

[Out]

Integral(x*acot(a + b*f**(c + d*x)), x)

Maxima [F]

\[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=\int { x \operatorname {arccot}\left (b f^{d x + c} + a\right ) \,d x } \]

[In]

integrate(x*arccot(a+b*f^(d*x+c)),x, algorithm="maxima")

[Out]

b*d*f^c*integrate(1/2*f^(d*x)*x^2/(b^2*f^(2*d*x)*f^(2*c) + 2*a*b*f^(d*x)*f^c + a^2 + 1), x)*log(f) + 1/2*x^2*a
rctan(1/(b*f^(d*x)*f^c + a))

Giac [F]

\[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=\int { x \operatorname {arccot}\left (b f^{d x + c} + a\right ) \,d x } \]

[In]

integrate(x*arccot(a+b*f^(d*x+c)),x, algorithm="giac")

[Out]

integrate(x*arccot(b*f^(d*x + c) + a), x)

Mupad [F(-1)]

Timed out. \[ \int x \cot ^{-1}\left (a+b f^{c+d x}\right ) \, dx=\int x\,\mathrm {acot}\left (a+b\,f^{c+d\,x}\right ) \,d x \]

[In]

int(x*acot(a + b*f^(c + d*x)),x)

[Out]

int(x*acot(a + b*f^(c + d*x)), x)