Integrand size = 8, antiderivative size = 57 \[ \int x^m \cot ^{-1}(a x) \, dx=\frac {x^{1+m} \cot ^{-1}(a x)}{1+m}+\frac {a x^{2+m} \operatorname {Hypergeometric2F1}\left (1,\frac {2+m}{2},\frac {4+m}{2},-a^2 x^2\right )}{2+3 m+m^2} \]
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Time = 0.02 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {4947, 371} \[ \int x^m \cot ^{-1}(a x) \, dx=\frac {a x^{m+2} \operatorname {Hypergeometric2F1}\left (1,\frac {m+2}{2},\frac {m+4}{2},-a^2 x^2\right )}{m^2+3 m+2}+\frac {x^{m+1} \cot ^{-1}(a x)}{m+1} \]
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Rule 371
Rule 4947
Rubi steps \begin{align*} \text {integral}& = \frac {x^{1+m} \cot ^{-1}(a x)}{1+m}+\frac {a \int \frac {x^{1+m}}{1+a^2 x^2} \, dx}{1+m} \\ & = \frac {x^{1+m} \cot ^{-1}(a x)}{1+m}+\frac {a x^{2+m} \operatorname {Hypergeometric2F1}\left (1,\frac {2+m}{2},\frac {4+m}{2},-a^2 x^2\right )}{2+3 m+m^2} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.91 \[ \int x^m \cot ^{-1}(a x) \, dx=\frac {x^{1+m} \left ((2+m) \cot ^{-1}(a x)+a x \operatorname {Hypergeometric2F1}\left (1,1+\frac {m}{2},2+\frac {m}{2},-a^2 x^2\right )\right )}{(1+m) (2+m)} \]
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\[\int x^{m} \operatorname {arccot}\left (a x \right )d x\]
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\[ \int x^m \cot ^{-1}(a x) \, dx=\int { x^{m} \operatorname {arccot}\left (a x\right ) \,d x } \]
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\[ \int x^m \cot ^{-1}(a x) \, dx=\int x^{m} \operatorname {acot}{\left (a x \right )}\, dx \]
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\[ \int x^m \cot ^{-1}(a x) \, dx=\int { x^{m} \operatorname {arccot}\left (a x\right ) \,d x } \]
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\[ \int x^m \cot ^{-1}(a x) \, dx=\int { x^{m} \operatorname {arccot}\left (a x\right ) \,d x } \]
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Timed out. \[ \int x^m \cot ^{-1}(a x) \, dx=\int x^m\,\mathrm {acot}\left (a\,x\right ) \,d x \]
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