Integrand size = 13, antiderivative size = 30 \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=-\frac {\cot ^{-1}(x)}{x}+\frac {1}{2} \cot ^{-1}(x)^2-\log (x)+\frac {1}{2} \log \left (1+x^2\right ) \]
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Time = 0.04 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.538, Rules used = {5039, 4947, 272, 36, 29, 31, 5005} \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=\frac {1}{2} \log \left (x^2+1\right )-\log (x)+\frac {1}{2} \cot ^{-1}(x)^2-\frac {\cot ^{-1}(x)}{x} \]
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Rule 29
Rule 31
Rule 36
Rule 272
Rule 4947
Rule 5005
Rule 5039
Rubi steps \begin{align*} \text {integral}& = \int \frac {\cot ^{-1}(x)}{x^2} \, dx-\int \frac {\cot ^{-1}(x)}{1+x^2} \, dx \\ & = -\frac {\cot ^{-1}(x)}{x}+\frac {1}{2} \cot ^{-1}(x)^2-\int \frac {1}{x \left (1+x^2\right )} \, dx \\ & = -\frac {\cot ^{-1}(x)}{x}+\frac {1}{2} \cot ^{-1}(x)^2-\frac {1}{2} \text {Subst}\left (\int \frac {1}{x (1+x)} \, dx,x,x^2\right ) \\ & = -\frac {\cot ^{-1}(x)}{x}+\frac {1}{2} \cot ^{-1}(x)^2-\frac {1}{2} \text {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )+\frac {1}{2} \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,x^2\right ) \\ & = -\frac {\cot ^{-1}(x)}{x}+\frac {1}{2} \cot ^{-1}(x)^2-\log (x)+\frac {1}{2} \log \left (1+x^2\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=-\frac {\cot ^{-1}(x)}{x}+\frac {1}{2} \cot ^{-1}(x)^2-\log (x)+\frac {1}{2} \log \left (1+x^2\right ) \]
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Time = 0.35 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.07
method | result | size |
parallelrisch | \(-\frac {-\operatorname {arccot}\left (x \right )^{2} x +2 \ln \left (x \right ) x -\ln \left (x^{2}+1\right ) x +2 \,\operatorname {arccot}\left (x \right )}{2 x}\) | \(32\) |
default | \(-\frac {\operatorname {arccot}\left (x \right )}{x}-\operatorname {arccot}\left (x \right ) \arctan \left (x \right )-\ln \left (x \right )+\frac {\ln \left (x^{2}+1\right )}{2}-\frac {\arctan \left (x \right )^{2}}{2}\) | \(33\) |
parts | \(-\frac {\operatorname {arccot}\left (x \right )}{x}-\operatorname {arccot}\left (x \right ) \arctan \left (x \right )-\ln \left (x \right )+\frac {\ln \left (x^{2}+1\right )}{2}-\frac {\arctan \left (x \right )^{2}}{2}\) | \(33\) |
risch | \(-\frac {\ln \left (i x +1\right )^{2}}{8}+\frac {\left (\ln \left (-i x +1\right ) x -2 i\right ) \ln \left (i x +1\right )}{4 x}-\frac {-2 i \ln \left (\left (-\pi +6 i\right ) x +6+i \pi \right ) \pi x +2 i \ln \left (\left (-\pi -6 i\right ) x +6-i \pi \right ) \pi x +\ln \left (-i x +1\right )^{2} x -4 i \ln \left (-i x +1\right )-4 \ln \left (\left (-\pi +6 i\right ) x +6+i \pi \right ) x -4 \ln \left (\left (-\pi -6 i\right ) x +6-i \pi \right ) x +8 \ln \left (-x \right ) x +4 \pi }{8 x}\) | \(150\) |
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Time = 0.26 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.97 \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=\frac {x \operatorname {arccot}\left (x\right )^{2} + x \log \left (x^{2} + 1\right ) - 2 \, x \log \left (x\right ) - 2 \, \operatorname {arccot}\left (x\right )}{2 \, x} \]
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Time = 0.14 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.73 \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=- \log {\left (x \right )} + \frac {\log {\left (x^{2} + 1 \right )}}{2} + \frac {\operatorname {acot}^{2}{\left (x \right )}}{2} - \frac {\operatorname {acot}{\left (x \right )}}{x} \]
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Time = 0.27 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.97 \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=-{\left (\frac {1}{x} + \arctan \left (x\right )\right )} \operatorname {arccot}\left (x\right ) - \frac {1}{2} \, \arctan \left (x\right )^{2} + \frac {1}{2} \, \log \left (x^{2} + 1\right ) - \log \left (x\right ) \]
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Time = 0.27 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=\frac {1}{2} \, \arctan \left (\frac {1}{x}\right )^{2} - \frac {\arctan \left (\frac {1}{x}\right )}{x} + \frac {1}{2} \, \log \left (\frac {1}{x^{2}} + 1\right ) \]
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Time = 0.10 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.87 \[ \int \frac {\cot ^{-1}(x)}{x^2 \left (1+x^2\right )} \, dx=\frac {\ln \left (x^2+1\right )}{2}-\ln \left (x\right )-\frac {\mathrm {acot}\left (x\right )}{x}+\frac {{\mathrm {acot}\left (x\right )}^2}{2} \]
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