Integrand size = 4, antiderivative size = 71 \[ \int e^{\cot ^{-1}(x)} \, dx=\left (\frac {4}{5}+\frac {8 i}{5}\right ) \left (\frac {-i+x}{x}\right )^{1+\frac {i}{2}} \left (\frac {i+x}{x}\right )^{-1-\frac {i}{2}} \operatorname {Hypergeometric2F1}\left (1+\frac {i}{2},2,2+\frac {i}{2},\frac {1-\frac {i}{x}}{1+\frac {i}{x}}\right ) \]
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Time = 0.01 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5210, 133} \[ \int e^{\cot ^{-1}(x)} \, dx=\left (\frac {4}{5}+\frac {8 i}{5}\right ) \left (\frac {x-i}{x}\right )^{1+\frac {i}{2}} \left (\frac {x+i}{x}\right )^{-1-\frac {i}{2}} \operatorname {Hypergeometric2F1}\left (1+\frac {i}{2},2,2+\frac {i}{2},\frac {1-\frac {i}{x}}{1+\frac {i}{x}}\right ) \]
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Rule 133
Rule 5210
Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {(1-i x)^{\frac {i}{2}} (1+i x)^{-\frac {i}{2}}}{x^2} \, dx,x,\frac {1}{x}\right ) \\ & = \left (\frac {4}{5}+\frac {8 i}{5}\right ) \left (\frac {-i+x}{x}\right )^{1+\frac {i}{2}} \left (\frac {i+x}{x}\right )^{-1-\frac {i}{2}} \operatorname {Hypergeometric2F1}\left (1+\frac {i}{2},2,2+\frac {i}{2},\frac {1-\frac {i}{x}}{1+\frac {i}{x}}\right ) \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.00 \[ \int e^{\cot ^{-1}(x)} \, dx=e^{\cot ^{-1}(x)} x+i e^{\cot ^{-1}(x)} \operatorname {Hypergeometric2F1}\left (-\frac {i}{2},1,1-\frac {i}{2},e^{2 i \cot ^{-1}(x)}\right )+\left (\frac {2}{5}+\frac {i}{5}\right ) e^{(1+2 i) \cot ^{-1}(x)} \operatorname {Hypergeometric2F1}\left (1,1-\frac {i}{2},2-\frac {i}{2},e^{2 i \cot ^{-1}(x)}\right ) \]
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\[\int {\mathrm e}^{\operatorname {arccot}\left (x \right )}d x\]
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\[ \int e^{\cot ^{-1}(x)} \, dx=\int { e^{\operatorname {arccot}\left (x\right )} \,d x } \]
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\[ \int e^{\cot ^{-1}(x)} \, dx=\int e^{\operatorname {acot}{\left (x \right )}}\, dx \]
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\[ \int e^{\cot ^{-1}(x)} \, dx=\int { e^{\operatorname {arccot}\left (x\right )} \,d x } \]
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\[ \int e^{\cot ^{-1}(x)} \, dx=\int { e^{\operatorname {arccot}\left (x\right )} \,d x } \]
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Timed out. \[ \int e^{\cot ^{-1}(x)} \, dx=\int {\mathrm {e}}^{\mathrm {acot}\left (x\right )} \,d x \]
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