Integrand size = 14, antiderivative size = 58 \[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\frac {a x^2}{2}+\frac {b \left (c+d x^2\right ) \sec ^{-1}\left (c+d x^2\right )}{2 d}-\frac {b \text {arctanh}\left (\sqrt {1-\frac {1}{\left (c+d x^2\right )^2}}\right )}{2 d} \]
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Time = 0.06 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {6847, 5358, 379, 272, 65, 212} \[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\frac {a x^2}{2}-\frac {b \text {arctanh}\left (\sqrt {1-\frac {1}{\left (c+d x^2\right )^2}}\right )}{2 d}+\frac {b \left (c+d x^2\right ) \sec ^{-1}\left (c+d x^2\right )}{2 d} \]
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Rule 65
Rule 212
Rule 272
Rule 379
Rule 5358
Rule 6847
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \left (a+b \sec ^{-1}(c+d x)\right ) \, dx,x,x^2\right ) \\ & = \frac {a x^2}{2}+\frac {1}{2} b \text {Subst}\left (\int \sec ^{-1}(c+d x) \, dx,x,x^2\right ) \\ & = \frac {a x^2}{2}+\frac {b \left (c+d x^2\right ) \sec ^{-1}\left (c+d x^2\right )}{2 d}-\frac {1}{2} b \text {Subst}\left (\int \frac {1}{(c+d x) \sqrt {1-\frac {1}{(c+d x)^2}}} \, dx,x,x^2\right ) \\ & = \frac {a x^2}{2}+\frac {b \left (c+d x^2\right ) \sec ^{-1}\left (c+d x^2\right )}{2 d}-\frac {b \text {Subst}\left (\int \frac {1}{\sqrt {1-\frac {1}{x^2}} x} \, dx,x,c+d x^2\right )}{2 d} \\ & = \frac {a x^2}{2}+\frac {b \left (c+d x^2\right ) \sec ^{-1}\left (c+d x^2\right )}{2 d}+\frac {b \text {Subst}\left (\int \frac {1}{\sqrt {1-x} x} \, dx,x,\frac {1}{\left (c+d x^2\right )^2}\right )}{4 d} \\ & = \frac {a x^2}{2}+\frac {b \left (c+d x^2\right ) \sec ^{-1}\left (c+d x^2\right )}{2 d}-\frac {b \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sqrt {1-\frac {1}{\left (c+d x^2\right )^2}}\right )}{2 d} \\ & = \frac {a x^2}{2}+\frac {b \left (c+d x^2\right ) \sec ^{-1}\left (c+d x^2\right )}{2 d}-\frac {b \text {arctanh}\left (\sqrt {1-\frac {1}{\left (c+d x^2\right )^2}}\right )}{2 d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 2.31 (sec) , antiderivative size = 516, normalized size of antiderivative = 8.90 \[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\frac {a x^2}{2}+\frac {1}{2} b x^2 \sec ^{-1}\left (c+d x^2\right )+\frac {b \left (c+d x^2\right ) \sqrt {\frac {-1+c^2+2 c d x^2+d^2 x^4}{\left (c+d x^2\right )^2}} \left (\sqrt [4]{-1} \left (-i+\sqrt {-1+c^2}\right ) \sqrt {2 i-i c^2+2 \sqrt {-1+c^2}} \arctan \left (\frac {(-1)^{3/4} \sqrt {2 i-i c^2+2 \sqrt {-1+c^2}} d x^2}{c \sqrt {-1+c^2}-c \sqrt {-1+c^2+2 c d x^2+d^2 x^4}}\right )+(-1)^{3/4} \left (i+\sqrt {-1+c^2}\right ) \sqrt {-2 i+i c^2+2 \sqrt {-1+c^2}} \arctan \left (\frac {\sqrt [4]{-1} \sqrt {-2 i+i c^2+2 \sqrt {-1+c^2}} d x^2}{c \sqrt {-1+c^2}-c \sqrt {-1+c^2+2 c d x^2+d^2 x^4}}\right )+c \left (c \arctan \left (\frac {\sqrt {-1+c^2} d^2 x^4}{c^4+c^3 d x^2+d^2 x^4-c^2 \left (1+\sqrt {-1+c^2} \sqrt {-1+c^2+2 c d x^2+d^2 x^4}\right )}\right )-\log \left (\sqrt {-1+c^2}-d x^2-\sqrt {-1+c^2+2 c d x^2+d^2 x^4}\right )+\log \left (d^2 \left (\sqrt {-1+c^2}+d x^2-\sqrt {-1+c^2+2 c d x^2+d^2 x^4}\right )\right )\right )\right )}{2 c d \sqrt {-1+c^2+2 c d x^2+d^2 x^4}} \]
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Time = 0.33 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.10
method | result | size |
parts | \(\frac {a \,x^{2}}{2}+\frac {b \left (\left (d \,x^{2}+c \right ) \operatorname {arcsec}\left (d \,x^{2}+c \right )-\ln \left (d \,x^{2}+c +\left (d \,x^{2}+c \right ) \sqrt {1-\frac {1}{\left (d \,x^{2}+c \right )^{2}}}\right )\right )}{2 d}\) | \(64\) |
derivativedivides | \(\frac {\left (d \,x^{2}+c \right ) a +b \left (\left (d \,x^{2}+c \right ) \operatorname {arcsec}\left (d \,x^{2}+c \right )-\ln \left (d \,x^{2}+c +\left (d \,x^{2}+c \right ) \sqrt {1-\frac {1}{\left (d \,x^{2}+c \right )^{2}}}\right )\right )}{2 d}\) | \(68\) |
default | \(\frac {\left (d \,x^{2}+c \right ) a +b \left (\left (d \,x^{2}+c \right ) \operatorname {arcsec}\left (d \,x^{2}+c \right )-\ln \left (d \,x^{2}+c +\left (d \,x^{2}+c \right ) \sqrt {1-\frac {1}{\left (d \,x^{2}+c \right )^{2}}}\right )\right )}{2 d}\) | \(68\) |
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Time = 0.30 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.66 \[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\frac {b d x^{2} \operatorname {arcsec}\left (d x^{2} + c\right ) + a d x^{2} + 2 \, b c \arctan \left (-d x^{2} - c + \sqrt {d^{2} x^{4} + 2 \, c d x^{2} + c^{2} - 1}\right ) + b \log \left (-d x^{2} - c + \sqrt {d^{2} x^{4} + 2 \, c d x^{2} + c^{2} - 1}\right )}{2 \, d} \]
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\[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\int x \left (a + b \operatorname {asec}{\left (c + d x^{2} \right )}\right )\, dx \]
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Time = 0.18 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.22 \[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\frac {1}{2} \, a x^{2} + \frac {{\left (2 \, {\left (d x^{2} + c\right )} \operatorname {arcsec}\left (d x^{2} + c\right ) - \log \left (\sqrt {-\frac {1}{{\left (d x^{2} + c\right )}^{2}} + 1} + 1\right ) + \log \left (-\sqrt {-\frac {1}{{\left (d x^{2} + c\right )}^{2}} + 1} + 1\right )\right )} b}{4 \, d} \]
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Time = 0.39 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.72 \[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\frac {1}{2} \, a x^{2} + \frac {1}{4} \, b d {\left (\frac {2 \, {\left (d x^{2} + c\right )} \arccos \left (-\frac {1}{{\left (d x^{2} + c\right )} {\left (\frac {c}{d x^{2} + c} - 1\right )} - c}\right )}{d^{2}} - \frac {\log \left (\sqrt {-\frac {1}{{\left (d x^{2} + c\right )}^{2}} + 1} + 1\right ) - \log \left (-\sqrt {-\frac {1}{{\left (d x^{2} + c\right )}^{2}} + 1} + 1\right )}{d^{2}}\right )} \]
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Time = 1.21 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.90 \[ \int x \left (a+b \sec ^{-1}\left (c+d x^2\right )\right ) \, dx=\frac {a\,x^2}{2}-\frac {b\,\mathrm {atanh}\left (\frac {1}{\sqrt {1-\frac {1}{{\left (d\,x^2+c\right )}^2}}}\right )}{2\,d}+\frac {b\,\mathrm {acos}\left (\frac {1}{d\,x^2+c}\right )\,\left (d\,x^2+c\right )}{2\,d} \]
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