Integrand size = 10, antiderivative size = 116 \[ \int x^2 \csc ^{-1}(a+b x) \, dx=-\frac {5 a (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^3}+\frac {x (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^2}+\frac {a^3 \csc ^{-1}(a+b x)}{3 b^3}+\frac {1}{3} x^3 \csc ^{-1}(a+b x)+\frac {\left (1+6 a^2\right ) \text {arctanh}\left (\sqrt {1-\frac {1}{(a+b x)^2}}\right )}{6 b^3} \]
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Time = 0.07 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {5367, 4512, 3867, 3855, 3852, 8} \[ \int x^2 \csc ^{-1}(a+b x) \, dx=\frac {a^3 \csc ^{-1}(a+b x)}{3 b^3}+\frac {\left (6 a^2+1\right ) \text {arctanh}\left (\sqrt {1-\frac {1}{(a+b x)^2}}\right )}{6 b^3}-\frac {5 a (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^3}+\frac {x (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^2}+\frac {1}{3} x^3 \csc ^{-1}(a+b x) \]
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Rule 8
Rule 3852
Rule 3855
Rule 3867
Rule 4512
Rule 5367
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int x \cot (x) \csc (x) (-a+\csc (x))^2 \, dx,x,\csc ^{-1}(a+b x)\right )}{b^3} \\ & = \frac {1}{3} x^3 \csc ^{-1}(a+b x)-\frac {\text {Subst}\left (\int (-a+\csc (x))^3 \, dx,x,\csc ^{-1}(a+b x)\right )}{3 b^3} \\ & = \frac {x (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^2}+\frac {1}{3} x^3 \csc ^{-1}(a+b x)-\frac {\text {Subst}\left (\int \left (-2 a^3+\left (1+6 a^2\right ) \csc (x)-5 a \csc ^2(x)\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{6 b^3} \\ & = \frac {x (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^2}+\frac {a^3 \csc ^{-1}(a+b x)}{3 b^3}+\frac {1}{3} x^3 \csc ^{-1}(a+b x)+\frac {(5 a) \text {Subst}\left (\int \csc ^2(x) \, dx,x,\csc ^{-1}(a+b x)\right )}{6 b^3}-\frac {\left (1+6 a^2\right ) \text {Subst}\left (\int \csc (x) \, dx,x,\csc ^{-1}(a+b x)\right )}{6 b^3} \\ & = \frac {x (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^2}+\frac {a^3 \csc ^{-1}(a+b x)}{3 b^3}+\frac {1}{3} x^3 \csc ^{-1}(a+b x)+\frac {\left (1+6 a^2\right ) \text {arctanh}\left (\sqrt {1-\frac {1}{(a+b x)^2}}\right )}{6 b^3}-\frac {(5 a) \text {Subst}\left (\int 1 \, dx,x,(a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}\right )}{6 b^3} \\ & = -\frac {5 a (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^3}+\frac {x (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}}}{6 b^2}+\frac {a^3 \csc ^{-1}(a+b x)}{3 b^3}+\frac {1}{3} x^3 \csc ^{-1}(a+b x)+\frac {\left (1+6 a^2\right ) \text {arctanh}\left (\sqrt {1-\frac {1}{(a+b x)^2}}\right )}{6 b^3} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.11 \[ \int x^2 \csc ^{-1}(a+b x) \, dx=\frac {\left (-5 a^2-4 a b x+b^2 x^2\right ) \sqrt {\frac {-1+a^2+2 a b x+b^2 x^2}{(a+b x)^2}}+2 b^3 x^3 \csc ^{-1}(a+b x)+2 a^3 \arcsin \left (\frac {1}{a+b x}\right )+\left (1+6 a^2\right ) \log \left ((a+b x) \left (1+\sqrt {\frac {-1+a^2+2 a b x+b^2 x^2}{(a+b x)^2}}\right )\right )}{6 b^3} \]
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Time = 0.31 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.66
method | result | size |
derivativedivides | \(\frac {-\frac {\operatorname {arccsc}\left (b x +a \right ) a^{3}}{3}+\operatorname {arccsc}\left (b x +a \right ) a^{2} \left (b x +a \right )-\operatorname {arccsc}\left (b x +a \right ) a \left (b x +a \right )^{2}+\frac {\operatorname {arccsc}\left (b x +a \right ) \left (b x +a \right )^{3}}{3}-\frac {\sqrt {\left (b x +a \right )^{2}-1}\, \left (-2 a^{3} \arctan \left (\frac {1}{\sqrt {\left (b x +a \right )^{2}-1}}\right )-6 a^{2} \ln \left (b x +a +\sqrt {\left (b x +a \right )^{2}-1}\right )+6 a \sqrt {\left (b x +a \right )^{2}-1}-\left (b x +a \right ) \sqrt {\left (b x +a \right )^{2}-1}-\ln \left (b x +a +\sqrt {\left (b x +a \right )^{2}-1}\right )\right )}{6 \sqrt {\frac {\left (b x +a \right )^{2}-1}{\left (b x +a \right )^{2}}}\, \left (b x +a \right )}}{b^{3}}\) | \(193\) |
default | \(\frac {-\frac {\operatorname {arccsc}\left (b x +a \right ) a^{3}}{3}+\operatorname {arccsc}\left (b x +a \right ) a^{2} \left (b x +a \right )-\operatorname {arccsc}\left (b x +a \right ) a \left (b x +a \right )^{2}+\frac {\operatorname {arccsc}\left (b x +a \right ) \left (b x +a \right )^{3}}{3}-\frac {\sqrt {\left (b x +a \right )^{2}-1}\, \left (-2 a^{3} \arctan \left (\frac {1}{\sqrt {\left (b x +a \right )^{2}-1}}\right )-6 a^{2} \ln \left (b x +a +\sqrt {\left (b x +a \right )^{2}-1}\right )+6 a \sqrt {\left (b x +a \right )^{2}-1}-\left (b x +a \right ) \sqrt {\left (b x +a \right )^{2}-1}-\ln \left (b x +a +\sqrt {\left (b x +a \right )^{2}-1}\right )\right )}{6 \sqrt {\frac {\left (b x +a \right )^{2}-1}{\left (b x +a \right )^{2}}}\, \left (b x +a \right )}}{b^{3}}\) | \(193\) |
parts | \(\frac {x^{3} \operatorname {arccsc}\left (b x +a \right )}{3}-\frac {\sqrt {b^{2} x^{2}+2 a b x +a^{2}-1}\, \left (-2 a^{3} \arctan \left (\frac {1}{\sqrt {b^{2} x^{2}+2 a b x +a^{2}-1}}\right ) \sqrt {b^{2}}-x \sqrt {b^{2} x^{2}+2 a b x +a^{2}-1}\, b \sqrt {b^{2}}-6 \ln \left (\frac {b^{2} x +\sqrt {b^{2} x^{2}+2 a b x +a^{2}-1}\, \sqrt {b^{2}}+a b}{\sqrt {b^{2}}}\right ) a^{2} b +5 \sqrt {b^{2}}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}-1}\, a -\ln \left (\frac {b^{2} x +\sqrt {b^{2} x^{2}+2 a b x +a^{2}-1}\, \sqrt {b^{2}}+a b}{\sqrt {b^{2}}}\right ) b \right )}{6 b^{3} \sqrt {\frac {b^{2} x^{2}+2 a b x +a^{2}-1}{\left (b x +a \right )^{2}}}\, \left (b x +a \right ) \sqrt {b^{2}}}\) | \(253\) |
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Time = 0.28 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.01 \[ \int x^2 \csc ^{-1}(a+b x) \, dx=\frac {2 \, b^{3} x^{3} \operatorname {arccsc}\left (b x + a\right ) - 4 \, a^{3} \arctan \left (-b x - a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) - {\left (6 \, a^{2} + 1\right )} \log \left (-b x - a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} - 1} {\left (b x - 5 \, a\right )}}{6 \, b^{3}} \]
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\[ \int x^2 \csc ^{-1}(a+b x) \, dx=\int x^{2} \operatorname {acsc}{\left (a + b x \right )}\, dx \]
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\[ \int x^2 \csc ^{-1}(a+b x) \, dx=\int { x^{2} \operatorname {arccsc}\left (b x + a\right ) \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 203 vs. \(2 (100) = 200\).
Time = 0.29 (sec) , antiderivative size = 203, normalized size of antiderivative = 1.75 \[ \int x^2 \csc ^{-1}(a+b x) \, dx=-\frac {1}{24} \, b {\left (\frac {8 \, {\left (b x + a\right )}^{3} {\left (\frac {3 \, a}{b x + a} - \frac {3 \, a^{2}}{{\left (b x + a\right )}^{2}} - 1\right )} \arcsin \left (-\frac {1}{{\left (b x + a\right )} {\left (\frac {a}{b x + a} - 1\right )} - a}\right )}{b^{4}} + \frac {{\left (b x + a\right )}^{2} {\left (\sqrt {-\frac {1}{{\left (b x + a\right )}^{2}} + 1} - 1\right )}^{2} + 12 \, {\left (b x + a\right )} a {\left (\sqrt {-\frac {1}{{\left (b x + a\right )}^{2}} + 1} - 1\right )} + 4 \, {\left (6 \, a^{2} + 1\right )} \log \left (-{\left (\sqrt {-\frac {1}{{\left (b x + a\right )}^{2}} + 1} - 1\right )} {\left | b x + a \right |}\right ) - \frac {12 \, {\left (b x + a\right )} a {\left (\sqrt {-\frac {1}{{\left (b x + a\right )}^{2}} + 1} - 1\right )} + 1}{{\left (b x + a\right )}^{2} {\left (\sqrt {-\frac {1}{{\left (b x + a\right )}^{2}} + 1} - 1\right )}^{2}}}{b^{4}}\right )} \]
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Timed out. \[ \int x^2 \csc ^{-1}(a+b x) \, dx=\int x^2\,\mathrm {asin}\left (\frac {1}{a+b\,x}\right ) \,d x \]
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