Integrand size = 15, antiderivative size = 28 \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=i \log (i-\sinh (x))+\frac {2 i}{1+i \sinh (x)} \]
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Time = 0.03 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {2746, 45} \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=\frac {2 i}{1+i \sinh (x)}+i \log (-\sinh (x)+i) \]
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Rule 45
Rule 2746
Rubi steps \begin{align*} \text {integral}& = -\left (i \text {Subst}\left (\int \frac {1-x}{(1+x)^2} \, dx,x,i \sinh (x)\right )\right ) \\ & = -\left (i \text {Subst}\left (\int \left (\frac {1}{-1-x}+\frac {2}{(1+x)^2}\right ) \, dx,x,i \sinh (x)\right )\right ) \\ & = i \log (i-\sinh (x))+\frac {2 i}{1+i \sinh (x)} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.68 \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=\frac {\cosh ^4(x) (2+\log (i-\sinh (x))+i \log (i-\sinh (x)) \sinh (x))}{(-i+\sinh (x))^3 (i+\sinh (x))^2} \]
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Time = 60.85 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93
method | result | size |
derivativedivides | \(\frac {i \ln \left (\sinh \left (x \right )^{2}+1\right )}{2}-\arctan \left (\sinh \left (x \right )\right )+\frac {2}{\sinh \left (x \right )-i}\) | \(26\) |
default | \(\frac {i \ln \left (\sinh \left (x \right )^{2}+1\right )}{2}-\arctan \left (\sinh \left (x \right )\right )+\frac {2}{\sinh \left (x \right )-i}\) | \(26\) |
risch | \(-i x +\frac {4 \,{\mathrm e}^{x}}{\left ({\mathrm e}^{x}-i\right )^{2}}+2 i \ln \left ({\mathrm e}^{x}-i\right )\) | \(26\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 50 vs. \(2 (20) = 40\).
Time = 0.30 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.79 \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=\frac {-i \, x e^{\left (2 \, x\right )} - 2 \, {\left (x - 2\right )} e^{x} - 2 \, {\left (-i \, e^{\left (2 \, x\right )} - 2 \, e^{x} + i\right )} \log \left (e^{x} - i\right ) + i \, x}{e^{\left (2 \, x\right )} - 2 i \, e^{x} - 1} \]
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Time = 0.09 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.11 \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=- i x + 2 i \log {\left (e^{x} - i \right )} + \frac {4 e^{x}}{e^{2 x} - 2 i e^{x} - 1} \]
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none
Time = 0.19 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.18 \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=i \, x - \frac {4 \, e^{\left (-x\right )}}{2 i \, e^{\left (-x\right )} + e^{\left (-2 \, x\right )} - 1} + 2 i \, \log \left (e^{\left (-x\right )} + i\right ) \]
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none
Time = 0.28 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.75 \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=-i \, x + \frac {4 \, e^{x}}{{\left (e^{x} - i\right )}^{2}} + 2 i \, \log \left (e^{x} - i\right ) \]
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Time = 0.19 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.46 \[ \int \frac {\cosh ^3(x)}{(1+i \sinh (x))^3} \, dx=-x\,1{}\mathrm {i}+\ln \left ({\mathrm {e}}^x-\mathrm {i}\right )\,2{}\mathrm {i}-\frac {4{}\mathrm {i}}{1-{\mathrm {e}}^{2\,x}+{\mathrm {e}}^x\,2{}\mathrm {i}}+\frac {4}{{\mathrm {e}}^x-\mathrm {i}} \]
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