Integrand size = 11, antiderivative size = 85 \[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=\frac {2 a b \arctan (\sinh (x))}{\left (a^2+b^2\right )^2}+\frac {\left (a^2-b^2\right ) \log (\cosh (x))}{\left (a^2+b^2\right )^2}-\frac {\left (a^2-b^2\right ) \log (a+b \sinh (x))}{\left (a^2+b^2\right )^2}+\frac {a}{\left (a^2+b^2\right ) (a+b \sinh (x))} \]
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Time = 0.07 (sec) , antiderivative size = 85, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.455, Rules used = {2800, 815, 649, 209, 266} \[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=\frac {2 a b \arctan (\sinh (x))}{\left (a^2+b^2\right )^2}+\frac {a}{\left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {\left (a^2-b^2\right ) \log (a+b \sinh (x))}{\left (a^2+b^2\right )^2}+\frac {\left (a^2-b^2\right ) \log (\cosh (x))}{\left (a^2+b^2\right )^2} \]
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Rule 209
Rule 266
Rule 649
Rule 815
Rule 2800
Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {x}{(a+x)^2 \left (-b^2-x^2\right )} \, dx,x,b \sinh (x)\right ) \\ & = -\text {Subst}\left (\int \left (\frac {a}{\left (a^2+b^2\right ) (a+x)^2}+\frac {a^2-b^2}{\left (a^2+b^2\right )^2 (a+x)}+\frac {-2 a b^2-\left (a^2-b^2\right ) x}{\left (a^2+b^2\right )^2 \left (b^2+x^2\right )}\right ) \, dx,x,b \sinh (x)\right ) \\ & = -\frac {\left (a^2-b^2\right ) \log (a+b \sinh (x))}{\left (a^2+b^2\right )^2}+\frac {a}{\left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {\text {Subst}\left (\int \frac {-2 a b^2-\left (a^2-b^2\right ) x}{b^2+x^2} \, dx,x,b \sinh (x)\right )}{\left (a^2+b^2\right )^2} \\ & = -\frac {\left (a^2-b^2\right ) \log (a+b \sinh (x))}{\left (a^2+b^2\right )^2}+\frac {a}{\left (a^2+b^2\right ) (a+b \sinh (x))}+\frac {\left (2 a b^2\right ) \text {Subst}\left (\int \frac {1}{b^2+x^2} \, dx,x,b \sinh (x)\right )}{\left (a^2+b^2\right )^2}+\frac {\left (a^2-b^2\right ) \text {Subst}\left (\int \frac {x}{b^2+x^2} \, dx,x,b \sinh (x)\right )}{\left (a^2+b^2\right )^2} \\ & = \frac {2 a b \arctan (\sinh (x))}{\left (a^2+b^2\right )^2}+\frac {\left (a^2-b^2\right ) \log (\cosh (x))}{\left (a^2+b^2\right )^2}-\frac {\left (a^2-b^2\right ) \log (a+b \sinh (x))}{\left (a^2+b^2\right )^2}+\frac {a}{\left (a^2+b^2\right ) (a+b \sinh (x))} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.18 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.72 \[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=\frac {a \left ((a-i b)^2 \log (i-\sinh (x))+(a+i b)^2 \log (i+\sinh (x))+2 \left (a^2+b^2+\left (-a^2+b^2\right ) \log (a+b \sinh (x))\right )\right )+b \left ((a-i b)^2 \log (i-\sinh (x))+(a+i b)^2 \log (i+\sinh (x))+2 \left (-a^2+b^2\right ) \log (a+b \sinh (x))\right ) \sinh (x)}{2 \left (a^2+b^2\right )^2 (a+b \sinh (x))} \]
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Time = 0.68 (sec) , antiderivative size = 136, normalized size of antiderivative = 1.60
method | result | size |
default | \(-\frac {2 \left (\frac {\left (-a^{2} b -b^{3}\right ) \tanh \left (\frac {x}{2}\right )}{\tanh \left (\frac {x}{2}\right )^{2} a -2 b \tanh \left (\frac {x}{2}\right )-a}+\frac {\left (a^{2}-b^{2}\right ) \ln \left (\tanh \left (\frac {x}{2}\right )^{2} a -2 b \tanh \left (\frac {x}{2}\right )-a \right )}{2}\right )}{\left (a^{2}+b^{2}\right )^{2}}+\frac {2 \left (a^{2}-b^{2}\right ) \ln \left (1+\tanh \left (\frac {x}{2}\right )^{2}\right )+8 a b \arctan \left (\tanh \left (\frac {x}{2}\right )\right )}{2 a^{4}+4 a^{2} b^{2}+2 b^{4}}\) | \(136\) |
risch | \(\frac {2 a \,{\mathrm e}^{x}}{\left (a^{2}+b^{2}\right ) \left (b \,{\mathrm e}^{2 x}+2 \,{\mathrm e}^{x} a -b \right )}+\frac {2 i \ln \left ({\mathrm e}^{x}+i\right ) a b}{a^{4}+2 a^{2} b^{2}+b^{4}}+\frac {\ln \left ({\mathrm e}^{x}+i\right ) a^{2}}{a^{4}+2 a^{2} b^{2}+b^{4}}-\frac {\ln \left ({\mathrm e}^{x}+i\right ) b^{2}}{a^{4}+2 a^{2} b^{2}+b^{4}}-\frac {2 i \ln \left ({\mathrm e}^{x}-i\right ) a b}{a^{4}+2 a^{2} b^{2}+b^{4}}+\frac {\ln \left ({\mathrm e}^{x}-i\right ) a^{2}}{a^{4}+2 a^{2} b^{2}+b^{4}}-\frac {\ln \left ({\mathrm e}^{x}-i\right ) b^{2}}{a^{4}+2 a^{2} b^{2}+b^{4}}-\frac {\ln \left ({\mathrm e}^{2 x}+\frac {2 a \,{\mathrm e}^{x}}{b}-1\right ) a^{2}}{a^{4}+2 a^{2} b^{2}+b^{4}}+\frac {\ln \left ({\mathrm e}^{2 x}+\frac {2 a \,{\mathrm e}^{x}}{b}-1\right ) b^{2}}{a^{4}+2 a^{2} b^{2}+b^{4}}\) | \(272\) |
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Leaf count of result is larger than twice the leaf count of optimal. 423 vs. \(2 (85) = 170\).
Time = 0.29 (sec) , antiderivative size = 423, normalized size of antiderivative = 4.98 \[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=-\frac {4 \, {\left (a b^{2} \cosh \left (x\right )^{2} + a b^{2} \sinh \left (x\right )^{2} + 2 \, a^{2} b \cosh \left (x\right ) - a b^{2} + 2 \, {\left (a b^{2} \cosh \left (x\right ) + a^{2} b\right )} \sinh \left (x\right )\right )} \arctan \left (\cosh \left (x\right ) + \sinh \left (x\right )\right ) + 2 \, {\left (a^{3} + a b^{2}\right )} \cosh \left (x\right ) + {\left (a^{2} b - b^{3} - {\left (a^{2} b - b^{3}\right )} \cosh \left (x\right )^{2} - {\left (a^{2} b - b^{3}\right )} \sinh \left (x\right )^{2} - 2 \, {\left (a^{3} - a b^{2}\right )} \cosh \left (x\right ) - 2 \, {\left (a^{3} - a b^{2} + {\left (a^{2} b - b^{3}\right )} \cosh \left (x\right )\right )} \sinh \left (x\right )\right )} \log \left (\frac {2 \, {\left (b \sinh \left (x\right ) + a\right )}}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) - {\left (a^{2} b - b^{3} - {\left (a^{2} b - b^{3}\right )} \cosh \left (x\right )^{2} - {\left (a^{2} b - b^{3}\right )} \sinh \left (x\right )^{2} - 2 \, {\left (a^{3} - a b^{2}\right )} \cosh \left (x\right ) - 2 \, {\left (a^{3} - a b^{2} + {\left (a^{2} b - b^{3}\right )} \cosh \left (x\right )\right )} \sinh \left (x\right )\right )} \log \left (\frac {2 \, \cosh \left (x\right )}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) + 2 \, {\left (a^{3} + a b^{2}\right )} \sinh \left (x\right )}{a^{4} b + 2 \, a^{2} b^{3} + b^{5} - {\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} \cosh \left (x\right )^{2} - {\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} \sinh \left (x\right )^{2} - 2 \, {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4}\right )} \cosh \left (x\right ) - 2 \, {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4} + {\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} \cosh \left (x\right )\right )} \sinh \left (x\right )} \]
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\[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=\int \frac {\tanh {\left (x \right )}}{\left (a + b \sinh {\left (x \right )}\right )^{2}}\, dx \]
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Time = 0.34 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.82 \[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=-\frac {4 \, a b \arctan \left (e^{\left (-x\right )}\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} + \frac {2 \, a e^{\left (-x\right )}}{a^{2} b + b^{3} + 2 \, {\left (a^{3} + a b^{2}\right )} e^{\left (-x\right )} - {\left (a^{2} b + b^{3}\right )} e^{\left (-2 \, x\right )}} - \frac {{\left (a^{2} - b^{2}\right )} \log \left (-2 \, a e^{\left (-x\right )} + b e^{\left (-2 \, x\right )} - b\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} + \frac {{\left (a^{2} - b^{2}\right )} \log \left (e^{\left (-2 \, x\right )} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 199 vs. \(2 (85) = 170\).
Time = 0.29 (sec) , antiderivative size = 199, normalized size of antiderivative = 2.34 \[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=\frac {{\left (\pi + 2 \, \arctan \left (\frac {1}{2} \, {\left (e^{\left (2 \, x\right )} - 1\right )} e^{\left (-x\right )}\right )\right )} a b}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} + \frac {{\left (a^{2} - b^{2}\right )} \log \left ({\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 4\right )}{2 \, {\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )}} - \frac {{\left (a^{2} b - b^{3}\right )} \log \left ({\left | -b {\left (e^{\left (-x\right )} - e^{x}\right )} + 2 \, a \right |}\right )}{a^{4} b + 2 \, a^{2} b^{3} + b^{5}} + \frac {a^{2} b {\left (e^{\left (-x\right )} - e^{x}\right )} - b^{3} {\left (e^{\left (-x\right )} - e^{x}\right )} - 4 \, a^{3}}{{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} {\left (b {\left (e^{\left (-x\right )} - e^{x}\right )} - 2 \, a\right )}} \]
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Time = 2.55 (sec) , antiderivative size = 190, normalized size of antiderivative = 2.24 \[ \int \frac {\tanh (x)}{(a+b \sinh (x))^2} \, dx=\frac {\ln \left (1+{\mathrm {e}}^x\,1{}\mathrm {i}\right )}{a^2+a\,b\,2{}\mathrm {i}-b^2}-\frac {\ln \left (b^5\,{\mathrm {e}}^{2\,x}-a^4\,b-b^5+a^2\,b^3+2\,a^5\,{\mathrm {e}}^x-a^2\,b^3\,{\mathrm {e}}^{2\,x}+2\,a\,b^4\,{\mathrm {e}}^x+a^4\,b\,{\mathrm {e}}^{2\,x}-2\,a^3\,b^2\,{\mathrm {e}}^x\right )\,\left (a^2-b^2\right )}{a^4+2\,a^2\,b^2+b^4}+\frac {2\,a\,b\,{\mathrm {e}}^x}{\left (a^2\,b+b^3\right )\,\left (2\,a\,{\mathrm {e}}^x-b+b\,{\mathrm {e}}^{2\,x}\right )}+\frac {\ln \left ({\mathrm {e}}^x+1{}\mathrm {i}\right )\,1{}\mathrm {i}}{a^2\,1{}\mathrm {i}+2\,a\,b-b^2\,1{}\mathrm {i}} \]
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