Integrand size = 16, antiderivative size = 101 \[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=\frac {8 e^{3 a+3 b x}}{3 b \left (1-e^{2 a+2 b x}\right )^3}-\frac {2 e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )^2}+\frac {e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )}+\frac {\text {arctanh}\left (e^{a+b x}\right )}{b} \]
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Time = 0.04 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.312, Rules used = {2320, 12, 294, 205, 212} \[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=\frac {\text {arctanh}\left (e^{a+b x}\right )}{b}+\frac {e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )}-\frac {2 e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )^2}+\frac {8 e^{3 a+3 b x}}{3 b \left (1-e^{2 a+2 b x}\right )^3} \]
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Rule 12
Rule 205
Rule 212
Rule 294
Rule 2320
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {16 x^4}{\left (1-x^2\right )^4} \, dx,x,e^{a+b x}\right )}{b} \\ & = \frac {16 \text {Subst}\left (\int \frac {x^4}{\left (1-x^2\right )^4} \, dx,x,e^{a+b x}\right )}{b} \\ & = \frac {8 e^{3 a+3 b x}}{3 b \left (1-e^{2 a+2 b x}\right )^3}-\frac {8 \text {Subst}\left (\int \frac {x^2}{\left (1-x^2\right )^3} \, dx,x,e^{a+b x}\right )}{b} \\ & = \frac {8 e^{3 a+3 b x}}{3 b \left (1-e^{2 a+2 b x}\right )^3}-\frac {2 e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )^2}+\frac {2 \text {Subst}\left (\int \frac {1}{\left (1-x^2\right )^2} \, dx,x,e^{a+b x}\right )}{b} \\ & = \frac {8 e^{3 a+3 b x}}{3 b \left (1-e^{2 a+2 b x}\right )^3}-\frac {2 e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )^2}+\frac {e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )}+\frac {\text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,e^{a+b x}\right )}{b} \\ & = \frac {8 e^{3 a+3 b x}}{3 b \left (1-e^{2 a+2 b x}\right )^3}-\frac {2 e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )^2}+\frac {e^{a+b x}}{b \left (1-e^{2 a+2 b x}\right )}+\frac {\text {arctanh}\left (e^{a+b x}\right )}{b} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.74 \[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=\frac {3 e^{a+b x}-8 e^{3 (a+b x)}-3 e^{5 (a+b x)}+3 \left (-1+e^{2 (a+b x)}\right )^3 \text {arctanh}\left (e^{a+b x}\right )}{3 b \left (-1+e^{2 (a+b x)}\right )^3} \]
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Time = 2.31 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.37
method | result | size |
derivativedivides | \(\frac {-\frac {\operatorname {csch}\left (b x +a \right ) \coth \left (b x +a \right )}{2}+\operatorname {arctanh}\left ({\mathrm e}^{b x +a}\right )-\frac {1}{3 \sinh \left (b x +a \right )^{3}}}{b}\) | \(37\) |
default | \(\frac {-\frac {\operatorname {csch}\left (b x +a \right ) \coth \left (b x +a \right )}{2}+\operatorname {arctanh}\left ({\mathrm e}^{b x +a}\right )-\frac {1}{3 \sinh \left (b x +a \right )^{3}}}{b}\) | \(37\) |
risch | \(-\frac {{\mathrm e}^{b x +a} \left (3 \,{\mathrm e}^{4 b x +4 a}+8 \,{\mathrm e}^{2 b x +2 a}-3\right )}{3 b \left ({\mathrm e}^{2 b x +2 a}-1\right )^{3}}+\frac {\ln \left ({\mathrm e}^{b x +a}+1\right )}{2 b}-\frac {\ln \left ({\mathrm e}^{b x +a}-1\right )}{2 b}\) | \(78\) |
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Leaf count of result is larger than twice the leaf count of optimal. 705 vs. \(2 (87) = 174\).
Time = 0.28 (sec) , antiderivative size = 705, normalized size of antiderivative = 6.98 \[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=-\frac {6 \, \cosh \left (b x + a\right )^{5} + 30 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{4} + 6 \, \sinh \left (b x + a\right )^{5} + 4 \, {\left (15 \, \cosh \left (b x + a\right )^{2} + 4\right )} \sinh \left (b x + a\right )^{3} + 16 \, \cosh \left (b x + a\right )^{3} + 12 \, {\left (5 \, \cosh \left (b x + a\right )^{3} + 4 \, \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{2} - 3 \, {\left (\cosh \left (b x + a\right )^{6} + 6 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{5} + \sinh \left (b x + a\right )^{6} + 3 \, {\left (5 \, \cosh \left (b x + a\right )^{2} - 1\right )} \sinh \left (b x + a\right )^{4} - 3 \, \cosh \left (b x + a\right )^{4} + 4 \, {\left (5 \, \cosh \left (b x + a\right )^{3} - 3 \, \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{3} + 3 \, {\left (5 \, \cosh \left (b x + a\right )^{4} - 6 \, \cosh \left (b x + a\right )^{2} + 1\right )} \sinh \left (b x + a\right )^{2} + 3 \, \cosh \left (b x + a\right )^{2} + 6 \, {\left (\cosh \left (b x + a\right )^{5} - 2 \, \cosh \left (b x + a\right )^{3} + \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right ) - 1\right )} \log \left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right ) + 1\right ) + 3 \, {\left (\cosh \left (b x + a\right )^{6} + 6 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{5} + \sinh \left (b x + a\right )^{6} + 3 \, {\left (5 \, \cosh \left (b x + a\right )^{2} - 1\right )} \sinh \left (b x + a\right )^{4} - 3 \, \cosh \left (b x + a\right )^{4} + 4 \, {\left (5 \, \cosh \left (b x + a\right )^{3} - 3 \, \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{3} + 3 \, {\left (5 \, \cosh \left (b x + a\right )^{4} - 6 \, \cosh \left (b x + a\right )^{2} + 1\right )} \sinh \left (b x + a\right )^{2} + 3 \, \cosh \left (b x + a\right )^{2} + 6 \, {\left (\cosh \left (b x + a\right )^{5} - 2 \, \cosh \left (b x + a\right )^{3} + \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right ) - 1\right )} \log \left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right ) - 1\right ) + 6 \, {\left (5 \, \cosh \left (b x + a\right )^{4} + 8 \, \cosh \left (b x + a\right )^{2} - 1\right )} \sinh \left (b x + a\right ) - 6 \, \cosh \left (b x + a\right )}{6 \, {\left (b \cosh \left (b x + a\right )^{6} + 6 \, b \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{5} + b \sinh \left (b x + a\right )^{6} - 3 \, b \cosh \left (b x + a\right )^{4} + 3 \, {\left (5 \, b \cosh \left (b x + a\right )^{2} - b\right )} \sinh \left (b x + a\right )^{4} + 4 \, {\left (5 \, b \cosh \left (b x + a\right )^{3} - 3 \, b \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{3} + 3 \, b \cosh \left (b x + a\right )^{2} + 3 \, {\left (5 \, b \cosh \left (b x + a\right )^{4} - 6 \, b \cosh \left (b x + a\right )^{2} + b\right )} \sinh \left (b x + a\right )^{2} + 6 \, {\left (b \cosh \left (b x + a\right )^{5} - 2 \, b \cosh \left (b x + a\right )^{3} + b \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right ) - b\right )}} \]
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\[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=e^{a} \int e^{b x} \operatorname {csch}^{4}{\left (a + b x \right )}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.99 \[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=\frac {\log \left (e^{\left (b x + a\right )} + 1\right )}{2 \, b} - \frac {\log \left (e^{\left (b x + a\right )} - 1\right )}{2 \, b} - \frac {3 \, e^{\left (5 \, b x + 5 \, a\right )} + 8 \, e^{\left (3 \, b x + 3 \, a\right )} - 3 \, e^{\left (b x + a\right )}}{3 \, b {\left (e^{\left (6 \, b x + 6 \, a\right )} - 3 \, e^{\left (4 \, b x + 4 \, a\right )} + 3 \, e^{\left (2 \, b x + 2 \, a\right )} - 1\right )}} \]
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Time = 0.27 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.74 \[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=-\frac {\frac {2 \, {\left (3 \, e^{\left (5 \, b x + 5 \, a\right )} + 8 \, e^{\left (3 \, b x + 3 \, a\right )} - 3 \, e^{\left (b x + a\right )}\right )}}{{\left (e^{\left (2 \, b x + 2 \, a\right )} - 1\right )}^{3}} - 3 \, \log \left (e^{\left (b x + a\right )} + 1\right ) + 3 \, \log \left ({\left | e^{\left (b x + a\right )} - 1 \right |}\right )}{6 \, b} \]
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Time = 1.32 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.34 \[ \int e^{a+b x} \text {csch}^4(a+b x) \, dx=\frac {\mathrm {atan}\left (\frac {{\mathrm {e}}^{b\,x}\,{\mathrm {e}}^a\,\sqrt {-b^2}}{b}\right )}{\sqrt {-b^2}}-\frac {2\,{\mathrm {e}}^{a+b\,x}}{b\,\left ({\mathrm {e}}^{4\,a+4\,b\,x}-2\,{\mathrm {e}}^{2\,a+2\,b\,x}+1\right )}-\frac {8\,{\mathrm {e}}^{3\,a+3\,b\,x}}{3\,b\,\left (3\,{\mathrm {e}}^{2\,a+2\,b\,x}-3\,{\mathrm {e}}^{4\,a+4\,b\,x}+{\mathrm {e}}^{6\,a+6\,b\,x}-1\right )}-\frac {{\mathrm {e}}^{a+b\,x}}{b\,\left ({\mathrm {e}}^{2\,a+2\,b\,x}-1\right )} \]
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