Integrand size = 18, antiderivative size = 68 \[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=\frac {4 e^{2 (d+e x)} F^{c (a+b x)} \operatorname {Hypergeometric2F1}\left (2,1+\frac {b c \log (F)}{2 e},2+\frac {b c \log (F)}{2 e},e^{2 (d+e x)}\right )}{2 e+b c \log (F)} \]
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Time = 0.02 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {5601} \[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=\frac {4 e^{2 (d+e x)} F^{c (a+b x)} \operatorname {Hypergeometric2F1}\left (2,\frac {b c \log (F)}{2 e}+1,\frac {b c \log (F)}{2 e}+2,e^{2 (d+e x)}\right )}{b c \log (F)+2 e} \]
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Rule 5601
Rubi steps \begin{align*} \text {integral}& = \frac {4 e^{2 (d+e x)} F^{c (a+b x)} \operatorname {Hypergeometric2F1}\left (2,1+\frac {b c \log (F)}{2 e},2+\frac {b c \log (F)}{2 e},e^{2 (d+e x)}\right )}{2 e+b c \log (F)} \\ \end{align*}
Time = 0.91 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.28 \[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=-\frac {2 F^{c (a+b x)} \left (\left (-1+e^{2 d}\right ) \operatorname {Hypergeometric2F1}\left (1,\frac {b c \log (F)}{2 e},1+\frac {b c \log (F)}{2 e},e^{2 (d+e x)}\right )+\text {csch}(d+e x) \sinh (d) (\cosh (e x)-\sinh (e x))\right )}{e \left (-1+e^{2 d}\right )} \]
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\[\int F^{c \left (b x +a \right )} \operatorname {csch}\left (e x +d \right )^{2}d x\]
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\[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=\int { F^{{\left (b x + a\right )} c} \operatorname {csch}\left (e x + d\right )^{2} \,d x } \]
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\[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=\int F^{c \left (a + b x\right )} \operatorname {csch}^{2}{\left (d + e x \right )}\, dx \]
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\[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=\int { F^{{\left (b x + a\right )} c} \operatorname {csch}\left (e x + d\right )^{2} \,d x } \]
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\[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=\int { F^{{\left (b x + a\right )} c} \operatorname {csch}\left (e x + d\right )^{2} \,d x } \]
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Timed out. \[ \int F^{c (a+b x)} \text {csch}^2(d+e x) \, dx=\int \frac {F^{c\,\left (a+b\,x\right )}}{{\mathrm {sinh}\left (d+e\,x\right )}^2} \,d x \]
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