Integrand size = 14, antiderivative size = 62 \[ \int (i \sinh (c+d x))^{5/2} \, dx=-\frac {6 i E\left (\left .\frac {1}{2} \left (i c-\frac {\pi }{2}+i d x\right )\right |2\right )}{5 d}+\frac {2 i \cosh (c+d x) (i \sinh (c+d x))^{3/2}}{5 d} \]
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Time = 0.02 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2715, 2719} \[ \int (i \sinh (c+d x))^{5/2} \, dx=\frac {2 i (i \sinh (c+d x))^{3/2} \cosh (c+d x)}{5 d}-\frac {6 i E\left (\left .\frac {1}{2} \left (i c+i d x-\frac {\pi }{2}\right )\right |2\right )}{5 d} \]
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Rule 2715
Rule 2719
Rubi steps \begin{align*} \text {integral}& = \frac {2 i \cosh (c+d x) (i \sinh (c+d x))^{3/2}}{5 d}+\frac {3}{5} \int \sqrt {i \sinh (c+d x)} \, dx \\ & = -\frac {6 i E\left (\left .\frac {1}{2} \left (i c-\frac {\pi }{2}+i d x\right )\right |2\right )}{5 d}+\frac {2 i \cosh (c+d x) (i \sinh (c+d x))^{3/2}}{5 d} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.89 \[ \int (i \sinh (c+d x))^{5/2} \, dx=\frac {6 i E\left (\left .\frac {1}{4} (-2 i c+\pi -2 i d x)\right |2\right )-\sqrt {i \sinh (c+d x)} \sinh (2 (c+d x))}{5 d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 168 vs. \(2 (82 ) = 164\).
Time = 0.87 (sec) , antiderivative size = 169, normalized size of antiderivative = 2.73
method | result | size |
default | \(-\frac {i \left (3 \sqrt {1-i \sinh \left (d x +c \right )}\, \sqrt {2}\, \sqrt {1+i \sinh \left (d x +c \right )}\, \sqrt {i \sinh \left (d x +c \right )}\, \operatorname {EllipticF}\left (\sqrt {1-i \sinh \left (d x +c \right )}, \frac {\sqrt {2}}{2}\right )-6 \sqrt {1-i \sinh \left (d x +c \right )}\, \sqrt {2}\, \sqrt {1+i \sinh \left (d x +c \right )}\, \sqrt {i \sinh \left (d x +c \right )}\, \operatorname {EllipticE}\left (\sqrt {1-i \sinh \left (d x +c \right )}, \frac {\sqrt {2}}{2}\right )+2 \cosh \left (d x +c \right )^{4}-2 \cosh \left (d x +c \right )^{2}\right )}{5 \cosh \left (d x +c \right ) \sqrt {i \sinh \left (d x +c \right )}\, d}\) | \(169\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.08 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.52 \[ \int (i \sinh (c+d x))^{5/2} \, dx=-\frac {{\left (\sqrt {\frac {1}{2}} {\left (e^{\left (4 \, d x + 4 \, c\right )} + 12 \, e^{\left (2 \, d x + 2 \, c\right )} - 1\right )} \sqrt {i \, e^{\left (2 \, d x + 2 \, c\right )} - i} e^{\left (-\frac {1}{2} \, d x - \frac {1}{2} \, c\right )} + 12 \, \sqrt {2} \sqrt {i} e^{\left (2 \, d x + 2 \, c\right )} {\rm weierstrassZeta}\left (4, 0, {\rm weierstrassPInverse}\left (4, 0, e^{\left (d x + c\right )}\right )\right )\right )} e^{\left (-2 \, d x - 2 \, c\right )}}{10 \, d} \]
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\[ \int (i \sinh (c+d x))^{5/2} \, dx=\int \left (i \sinh {\left (c + d x \right )}\right )^{\frac {5}{2}}\, dx \]
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\[ \int (i \sinh (c+d x))^{5/2} \, dx=\int { \left (i \, \sinh \left (d x + c\right )\right )^{\frac {5}{2}} \,d x } \]
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Timed out. \[ \int (i \sinh (c+d x))^{5/2} \, dx=\text {Timed out} \]
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Timed out. \[ \int (i \sinh (c+d x))^{5/2} \, dx=\int {\left (\mathrm {sinh}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{5/2} \,d x \]
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