Integrand size = 15, antiderivative size = 62 \[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\frac {B \arctan (\sinh (x))}{a}+\frac {2 (a A-b B) \text {arctanh}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a \sqrt {a-b} \sqrt {a+b}} \]
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Time = 0.10 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2907, 3080, 3855, 2738, 214} \[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\frac {2 (a A-b B) \text {arctanh}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a \sqrt {a-b} \sqrt {a+b}}+\frac {B \arctan (\sinh (x))}{a} \]
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Rule 214
Rule 2738
Rule 2907
Rule 3080
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \frac {(B+A \cosh (x)) \text {sech}(x)}{a+b \cosh (x)} \, dx \\ & = \frac {B \int \text {sech}(x) \, dx}{a}+\frac {(a A-b B) \int \frac {1}{a+b \cosh (x)} \, dx}{a} \\ & = \frac {B \arctan (\sinh (x))}{a}+\frac {(2 (a A-b B)) \text {Subst}\left (\int \frac {1}{a+b-(a-b) x^2} \, dx,x,\tanh \left (\frac {x}{2}\right )\right )}{a} \\ & = \frac {B \arctan (\sinh (x))}{a}+\frac {2 (a A-b B) \text {arctanh}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a \sqrt {a-b} \sqrt {a+b}} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.02 \[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\frac {2 \left (B \arctan \left (\tanh \left (\frac {x}{2}\right )\right )+\frac {(-a A+b B) \arctan \left (\frac {(a-b) \tanh \left (\frac {x}{2}\right )}{\sqrt {-a^2+b^2}}\right )}{\sqrt {-a^2+b^2}}\right )}{a} \]
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Time = 0.26 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.95
method | result | size |
default | \(\frac {2 B \arctan \left (\tanh \left (\frac {x}{2}\right )\right )}{a}-\frac {2 \left (-A a +B b \right ) \operatorname {arctanh}\left (\frac {\left (a -b \right ) \tanh \left (\frac {x}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{a \sqrt {\left (a +b \right ) \left (a -b \right )}}\) | \(59\) |
risch | \(\frac {i B \ln \left ({\mathrm e}^{x}+i\right )}{a}-\frac {i B \ln \left ({\mathrm e}^{x}-i\right )}{a}+\frac {\ln \left ({\mathrm e}^{x}+\frac {a \sqrt {a^{2}-b^{2}}-a^{2}+b^{2}}{b \sqrt {a^{2}-b^{2}}}\right ) A}{\sqrt {a^{2}-b^{2}}}-\frac {\ln \left ({\mathrm e}^{x}+\frac {a \sqrt {a^{2}-b^{2}}-a^{2}+b^{2}}{b \sqrt {a^{2}-b^{2}}}\right ) B b}{\sqrt {a^{2}-b^{2}}\, a}-\frac {\ln \left ({\mathrm e}^{x}+\frac {a \sqrt {a^{2}-b^{2}}+a^{2}-b^{2}}{b \sqrt {a^{2}-b^{2}}}\right ) A}{\sqrt {a^{2}-b^{2}}}+\frac {\ln \left ({\mathrm e}^{x}+\frac {a \sqrt {a^{2}-b^{2}}+a^{2}-b^{2}}{b \sqrt {a^{2}-b^{2}}}\right ) B b}{\sqrt {a^{2}-b^{2}}\, a}\) | \(254\) |
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Time = 0.48 (sec) , antiderivative size = 249, normalized size of antiderivative = 4.02 \[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\left [-\frac {{\left (A a - B b\right )} \sqrt {a^{2} - b^{2}} \log \left (\frac {b^{2} \cosh \left (x\right )^{2} + b^{2} \sinh \left (x\right )^{2} + 2 \, a b \cosh \left (x\right ) + 2 \, a^{2} - b^{2} + 2 \, {\left (b^{2} \cosh \left (x\right ) + a b\right )} \sinh \left (x\right ) + 2 \, \sqrt {a^{2} - b^{2}} {\left (b \cosh \left (x\right ) + b \sinh \left (x\right ) + a\right )}}{b \cosh \left (x\right )^{2} + b \sinh \left (x\right )^{2} + 2 \, a \cosh \left (x\right ) + 2 \, {\left (b \cosh \left (x\right ) + a\right )} \sinh \left (x\right ) + b}\right ) - 2 \, {\left (B a^{2} - B b^{2}\right )} \arctan \left (\cosh \left (x\right ) + \sinh \left (x\right )\right )}{a^{3} - a b^{2}}, -\frac {2 \, {\left ({\left (A a - B b\right )} \sqrt {-a^{2} + b^{2}} \arctan \left (-\frac {\sqrt {-a^{2} + b^{2}} {\left (b \cosh \left (x\right ) + b \sinh \left (x\right ) + a\right )}}{a^{2} - b^{2}}\right ) - {\left (B a^{2} - B b^{2}\right )} \arctan \left (\cosh \left (x\right ) + \sinh \left (x\right )\right )\right )}}{a^{3} - a b^{2}}\right ] \]
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\[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\int \frac {A + B \operatorname {sech}{\left (x \right )}}{a + b \cosh {\left (x \right )}}\, dx \]
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Exception generated. \[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.26 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.85 \[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\frac {2 \, B \arctan \left (e^{x}\right )}{a} + \frac {2 \, {\left (A a - B b\right )} \arctan \left (\frac {b e^{x} + a}{\sqrt {-a^{2} + b^{2}}}\right )}{\sqrt {-a^{2} + b^{2}} a} \]
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Time = 7.26 (sec) , antiderivative size = 636, normalized size of antiderivative = 10.26 \[ \int \frac {A+B \text {sech}(x)}{a+b \cosh (x)} \, dx=\frac {\ln \left (\frac {\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )\,\left (\frac {32\,\left (A^2\,a^2\,b-2\,A\,B\,a\,b^2-4\,{\mathrm {e}}^x\,B^2\,a^3-2\,B^2\,a^2\,b+3\,{\mathrm {e}}^x\,B^2\,a\,b^2+2\,B^2\,b^3\right )}{b^5}+\frac {\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )\,\left (\frac {32\,a^2\,\left (2\,B\,b^2-4\,A\,a^2\,{\mathrm {e}}^x+A\,b^2\,{\mathrm {e}}^x-2\,A\,a\,b+3\,B\,a\,b\,{\mathrm {e}}^x\right )}{b^5}-\frac {32\,a^2\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )\,\left (4\,{\mathrm {e}}^x\,a^3+3\,a^2\,b-3\,{\mathrm {e}}^x\,a\,b^2-2\,b^3\right )}{b^5\,\left (a\,b^2-a^3\right )}\right )}{a\,b^2-a^3}\right )}{a\,b^2-a^3}-\frac {32\,B\,\left (A\,a-B\,b\right )\,\left (2\,B\,b-A\,b\,{\mathrm {e}}^x+4\,B\,a\,{\mathrm {e}}^x\right )}{b^5}\right )\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )}{a\,b^2-a^3}-\frac {\ln \left (-\frac {\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )\,\left (\frac {32\,\left (A^2\,a^2\,b-2\,A\,B\,a\,b^2-4\,{\mathrm {e}}^x\,B^2\,a^3-2\,B^2\,a^2\,b+3\,{\mathrm {e}}^x\,B^2\,a\,b^2+2\,B^2\,b^3\right )}{b^5}-\frac {\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )\,\left (\frac {32\,a^2\,\left (2\,B\,b^2-4\,A\,a^2\,{\mathrm {e}}^x+A\,b^2\,{\mathrm {e}}^x-2\,A\,a\,b+3\,B\,a\,b\,{\mathrm {e}}^x\right )}{b^5}+\frac {32\,a^2\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )\,\left (4\,{\mathrm {e}}^x\,a^3+3\,a^2\,b-3\,{\mathrm {e}}^x\,a\,b^2-2\,b^3\right )}{b^5\,\left (a\,b^2-a^3\right )}\right )}{a\,b^2-a^3}\right )}{a\,b^2-a^3}-\frac {32\,B\,\left (A\,a-B\,b\right )\,\left (2\,B\,b-A\,b\,{\mathrm {e}}^x+4\,B\,a\,{\mathrm {e}}^x\right )}{b^5}\right )\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\,\left (A\,a-B\,b\right )}{a\,b^2-a^3}-\frac {B\,\ln \left ({\mathrm {e}}^x-\mathrm {i}\right )\,1{}\mathrm {i}}{a}+\frac {B\,\ln \left ({\mathrm {e}}^x+1{}\mathrm {i}\right )\,1{}\mathrm {i}}{a} \]
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