Integrand size = 12, antiderivative size = 90 \[ \int (a+b \cosh (c+d x))^3 \, dx=\frac {1}{2} a \left (2 a^2+3 b^2\right ) x+\frac {2 b \left (4 a^2+b^2\right ) \sinh (c+d x)}{3 d}+\frac {5 a b^2 \cosh (c+d x) \sinh (c+d x)}{6 d}+\frac {b (a+b \cosh (c+d x))^2 \sinh (c+d x)}{3 d} \]
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Time = 0.05 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2735, 2813} \[ \int (a+b \cosh (c+d x))^3 \, dx=\frac {2 b \left (4 a^2+b^2\right ) \sinh (c+d x)}{3 d}+\frac {1}{2} a x \left (2 a^2+3 b^2\right )+\frac {5 a b^2 \sinh (c+d x) \cosh (c+d x)}{6 d}+\frac {b \sinh (c+d x) (a+b \cosh (c+d x))^2}{3 d} \]
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Rule 2735
Rule 2813
Rubi steps \begin{align*} \text {integral}& = \frac {b (a+b \cosh (c+d x))^2 \sinh (c+d x)}{3 d}+\frac {1}{3} \int (a+b \cosh (c+d x)) \left (3 a^2+2 b^2+5 a b \cosh (c+d x)\right ) \, dx \\ & = \frac {1}{2} a \left (2 a^2+3 b^2\right ) x+\frac {2 b \left (4 a^2+b^2\right ) \sinh (c+d x)}{3 d}+\frac {5 a b^2 \cosh (c+d x) \sinh (c+d x)}{6 d}+\frac {b (a+b \cosh (c+d x))^2 \sinh (c+d x)}{3 d} \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.89 \[ \int (a+b \cosh (c+d x))^3 \, dx=\frac {12 a^3 c+18 a b^2 c+12 a^3 d x+18 a b^2 d x+9 b \left (4 a^2+b^2\right ) \sinh (c+d x)+9 a b^2 \sinh (2 (c+d x))+b^3 \sinh (3 (c+d x))}{12 d} \]
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Time = 0.17 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.74
method | result | size |
parallelrisch | \(\frac {9 a \,b^{2} \sinh \left (2 d x +2 c \right )+b^{3} \sinh \left (3 d x +3 c \right )+9 \left (4 a^{2} b +b^{3}\right ) \sinh \left (d x +c \right )+12 d \left (a^{2}+\frac {3 b^{2}}{2}\right ) x a}{12 d}\) | \(67\) |
derivativedivides | \(\frac {b^{3} \left (\frac {2}{3}+\frac {\cosh \left (d x +c \right )^{2}}{3}\right ) \sinh \left (d x +c \right )+3 a \,b^{2} \left (\frac {\cosh \left (d x +c \right ) \sinh \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+3 a^{2} b \sinh \left (d x +c \right )+a^{3} \left (d x +c \right )}{d}\) | \(77\) |
default | \(\frac {b^{3} \left (\frac {2}{3}+\frac {\cosh \left (d x +c \right )^{2}}{3}\right ) \sinh \left (d x +c \right )+3 a \,b^{2} \left (\frac {\cosh \left (d x +c \right ) \sinh \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+3 a^{2} b \sinh \left (d x +c \right )+a^{3} \left (d x +c \right )}{d}\) | \(77\) |
parts | \(a^{3} x +\frac {b^{3} \left (\frac {2}{3}+\frac {\cosh \left (d x +c \right )^{2}}{3}\right ) \sinh \left (d x +c \right )}{d}+\frac {3 a^{2} b \sinh \left (d x +c \right )}{d}+\frac {3 a \,b^{2} \left (\frac {\cosh \left (d x +c \right ) \sinh \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )}{d}\) | \(78\) |
risch | \(a^{3} x +\frac {3 a \,b^{2} x}{2}+\frac {b^{3} {\mathrm e}^{3 d x +3 c}}{24 d}+\frac {3 a \,b^{2} {\mathrm e}^{2 d x +2 c}}{8 d}+\frac {3 b \,{\mathrm e}^{d x +c} a^{2}}{2 d}+\frac {3 b^{3} {\mathrm e}^{d x +c}}{8 d}-\frac {3 b \,{\mathrm e}^{-d x -c} a^{2}}{2 d}-\frac {3 b^{3} {\mathrm e}^{-d x -c}}{8 d}-\frac {3 a \,b^{2} {\mathrm e}^{-2 d x -2 c}}{8 d}-\frac {b^{3} {\mathrm e}^{-3 d x -3 c}}{24 d}\) | \(148\) |
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Time = 0.25 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.87 \[ \int (a+b \cosh (c+d x))^3 \, dx=\frac {b^{3} \sinh \left (d x + c\right )^{3} + 6 \, {\left (2 \, a^{3} + 3 \, a b^{2}\right )} d x + 3 \, {\left (b^{3} \cosh \left (d x + c\right )^{2} + 6 \, a b^{2} \cosh \left (d x + c\right ) + 12 \, a^{2} b + 3 \, b^{3}\right )} \sinh \left (d x + c\right )}{12 \, d} \]
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Time = 0.15 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.42 \[ \int (a+b \cosh (c+d x))^3 \, dx=\begin {cases} a^{3} x + \frac {3 a^{2} b \sinh {\left (c + d x \right )}}{d} - \frac {3 a b^{2} x \sinh ^{2}{\left (c + d x \right )}}{2} + \frac {3 a b^{2} x \cosh ^{2}{\left (c + d x \right )}}{2} + \frac {3 a b^{2} \sinh {\left (c + d x \right )} \cosh {\left (c + d x \right )}}{2 d} - \frac {2 b^{3} \sinh ^{3}{\left (c + d x \right )}}{3 d} + \frac {b^{3} \sinh {\left (c + d x \right )} \cosh ^{2}{\left (c + d x \right )}}{d} & \text {for}\: d \neq 0 \\x \left (a + b \cosh {\left (c \right )}\right )^{3} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.29 \[ \int (a+b \cosh (c+d x))^3 \, dx=\frac {3}{8} \, a b^{2} {\left (4 \, x + \frac {e^{\left (2 \, d x + 2 \, c\right )}}{d} - \frac {e^{\left (-2 \, d x - 2 \, c\right )}}{d}\right )} + a^{3} x + \frac {1}{24} \, b^{3} {\left (\frac {e^{\left (3 \, d x + 3 \, c\right )}}{d} + \frac {9 \, e^{\left (d x + c\right )}}{d} - \frac {9 \, e^{\left (-d x - c\right )}}{d} - \frac {e^{\left (-3 \, d x - 3 \, c\right )}}{d}\right )} + \frac {3 \, a^{2} b \sinh \left (d x + c\right )}{d} \]
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Time = 0.26 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.46 \[ \int (a+b \cosh (c+d x))^3 \, dx=\frac {b^{3} e^{\left (3 \, d x + 3 \, c\right )}}{24 \, d} + \frac {3 \, a b^{2} e^{\left (2 \, d x + 2 \, c\right )}}{8 \, d} - \frac {3 \, a b^{2} e^{\left (-2 \, d x - 2 \, c\right )}}{8 \, d} - \frac {b^{3} e^{\left (-3 \, d x - 3 \, c\right )}}{24 \, d} + \frac {1}{2} \, {\left (2 \, a^{3} + 3 \, a b^{2}\right )} x + \frac {3 \, {\left (4 \, a^{2} b + b^{3}\right )} e^{\left (d x + c\right )}}{8 \, d} - \frac {3 \, {\left (4 \, a^{2} b + b^{3}\right )} e^{\left (-d x - c\right )}}{8 \, d} \]
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Time = 1.77 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.81 \[ \int (a+b \cosh (c+d x))^3 \, dx=\frac {\frac {9\,b^3\,\mathrm {sinh}\left (c+d\,x\right )}{2}+\frac {b^3\,\mathrm {sinh}\left (3\,c+3\,d\,x\right )}{2}+\frac {9\,a\,b^2\,\mathrm {sinh}\left (2\,c+2\,d\,x\right )}{2}+18\,a^2\,b\,\mathrm {sinh}\left (c+d\,x\right )+6\,a^3\,d\,x+9\,a\,b^2\,d\,x}{6\,d} \]
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