Integrand size = 13, antiderivative size = 83 \[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=\frac {\left (a^2-b^2\right )^2 \log (a+b \tanh (x))}{b^5}-\frac {a \left (a^2-2 b^2\right ) \tanh (x)}{b^4}+\frac {\left (a^2-2 b^2\right ) \tanh ^2(x)}{2 b^3}-\frac {a \tanh ^3(x)}{3 b^2}+\frac {\tanh ^4(x)}{4 b} \]
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Time = 0.08 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3587, 711} \[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=\frac {\left (a^2-b^2\right )^2 \log (a+b \tanh (x))}{b^5}-\frac {a \left (a^2-2 b^2\right ) \tanh (x)}{b^4}+\frac {\left (a^2-2 b^2\right ) \tanh ^2(x)}{2 b^3}-\frac {a \tanh ^3(x)}{3 b^2}+\frac {\tanh ^4(x)}{4 b} \]
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Rule 711
Rule 3587
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\left (1-\frac {x^2}{b^2}\right )^2}{a+x} \, dx,x,b \tanh (x)\right )}{b} \\ & = \frac {\text {Subst}\left (\int \left (\frac {-a^3+2 a b^2}{b^4}-\frac {\left (-a^2+2 b^2\right ) x}{b^4}-\frac {a x^2}{b^4}+\frac {x^3}{b^4}+\frac {\left (-a^2+b^2\right )^2}{b^4 (a+x)}\right ) \, dx,x,b \tanh (x)\right )}{b} \\ & = \frac {\left (a^2-b^2\right )^2 \log (a+b \tanh (x))}{b^5}-\frac {a \left (a^2-2 b^2\right ) \tanh (x)}{b^4}+\frac {\left (a^2-2 b^2\right ) \tanh ^2(x)}{2 b^3}-\frac {a \tanh ^3(x)}{3 b^2}+\frac {\tanh ^4(x)}{4 b} \\ \end{align*}
Time = 0.24 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.96 \[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=\frac {12 \left (a^2-b^2\right )^2 \log (a+b \tanh (x))+3 b^4 \text {sech}^4(x)-12 a b \left (a^2-2 b^2\right ) \tanh (x)+6 b^2 \left (a^2-b^2\right ) \tanh ^2(x)-4 a b^3 \tanh ^3(x)}{12 b^5} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(221\) vs. \(2(77)=154\).
Time = 67.23 (sec) , antiderivative size = 222, normalized size of antiderivative = 2.67
method | result | size |
default | \(\frac {\left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \ln \left (\tanh \left (\frac {x}{2}\right )^{2} a +2 b \tanh \left (\frac {x}{2}\right )+a \right )}{b^{5}}-\frac {2 \left (\frac {\left (a^{3} b -2 a \,b^{3}\right ) \tanh \left (\frac {x}{2}\right )^{7}+\left (-a^{2} b^{2}+2 b^{4}\right ) \tanh \left (\frac {x}{2}\right )^{6}+\left (3 a^{3} b -\frac {14}{3} a \,b^{3}\right ) \tanh \left (\frac {x}{2}\right )^{5}+\left (-2 a^{2} b^{2}+2 b^{4}\right ) \tanh \left (\frac {x}{2}\right )^{4}+\left (3 a^{3} b -\frac {14}{3} a \,b^{3}\right ) \tanh \left (\frac {x}{2}\right )^{3}+\left (-a^{2} b^{2}+2 b^{4}\right ) \tanh \left (\frac {x}{2}\right )^{2}+\left (a^{3} b -2 a \,b^{3}\right ) \tanh \left (\frac {x}{2}\right )}{\left (1+\tanh \left (\frac {x}{2}\right )^{2}\right )^{4}}+\frac {\left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \ln \left (1+\tanh \left (\frac {x}{2}\right )^{2}\right )}{2}\right )}{b^{5}}\) | \(222\) |
risch | \(\frac {2 a^{3} {\mathrm e}^{6 x}-2 \,{\mathrm e}^{6 x} a^{2} b -2 \,{\mathrm e}^{6 x} a \,b^{2}+2 b^{3} {\mathrm e}^{6 x}+6 a^{3} {\mathrm e}^{4 x}-4 a^{2} b \,{\mathrm e}^{4 x}-10 a \,b^{2} {\mathrm e}^{4 x}+8 b^{3} {\mathrm e}^{4 x}+6 a^{3} {\mathrm e}^{2 x}-2 \,{\mathrm e}^{2 x} a^{2} b -\frac {34 \,{\mathrm e}^{2 x} a \,b^{2}}{3}+2 b^{3} {\mathrm e}^{2 x}+2 a^{3}-\frac {10 a \,b^{2}}{3}}{b^{4} \left (1+{\mathrm e}^{2 x}\right )^{4}}-\frac {\ln \left (1+{\mathrm e}^{2 x}\right ) a^{4}}{b^{5}}+\frac {2 \ln \left (1+{\mathrm e}^{2 x}\right ) a^{2}}{b^{3}}-\frac {\ln \left (1+{\mathrm e}^{2 x}\right )}{b}+\frac {\ln \left ({\mathrm e}^{2 x}+\frac {a -b}{a +b}\right ) a^{4}}{b^{5}}-\frac {2 \ln \left ({\mathrm e}^{2 x}+\frac {a -b}{a +b}\right ) a^{2}}{b^{3}}+\frac {\ln \left ({\mathrm e}^{2 x}+\frac {a -b}{a +b}\right )}{b}\) | \(253\) |
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Leaf count of result is larger than twice the leaf count of optimal. 1827 vs. \(2 (77) = 154\).
Time = 0.29 (sec) , antiderivative size = 1827, normalized size of antiderivative = 22.01 \[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=\text {Too large to display} \]
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\[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=\int \frac {\operatorname {sech}^{6}{\left (x \right )}}{a + b \tanh {\left (x \right )}}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 204 vs. \(2 (77) = 154\).
Time = 0.28 (sec) , antiderivative size = 204, normalized size of antiderivative = 2.46 \[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=-\frac {2 \, {\left (3 \, a^{3} - 5 \, a b^{2} + {\left (9 \, a^{3} + 3 \, a^{2} b - 17 \, a b^{2} - 3 \, b^{3}\right )} e^{\left (-2 \, x\right )} + 3 \, {\left (3 \, a^{3} + 2 \, a^{2} b - 5 \, a b^{2} - 4 \, b^{3}\right )} e^{\left (-4 \, x\right )} + 3 \, {\left (a^{3} + a^{2} b - a b^{2} - b^{3}\right )} e^{\left (-6 \, x\right )}\right )}}{3 \, {\left (4 \, b^{4} e^{\left (-2 \, x\right )} + 6 \, b^{4} e^{\left (-4 \, x\right )} + 4 \, b^{4} e^{\left (-6 \, x\right )} + b^{4} e^{\left (-8 \, x\right )} + b^{4}\right )}} + \frac {{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \log \left (-{\left (a - b\right )} e^{\left (-2 \, x\right )} - a - b\right )}{b^{5}} - \frac {{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \log \left (e^{\left (-2 \, x\right )} + 1\right )}{b^{5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 316 vs. \(2 (77) = 154\).
Time = 0.27 (sec) , antiderivative size = 316, normalized size of antiderivative = 3.81 \[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=\frac {{\left (a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}\right )} \log \left ({\left | a e^{\left (2 \, x\right )} + b e^{\left (2 \, x\right )} + a - b \right |}\right )}{a b^{5} + b^{6}} - \frac {{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \log \left (e^{\left (2 \, x\right )} + 1\right )}{b^{5}} + \frac {25 \, a^{4} e^{\left (8 \, x\right )} - 50 \, a^{2} b^{2} e^{\left (8 \, x\right )} + 25 \, b^{4} e^{\left (8 \, x\right )} + 100 \, a^{4} e^{\left (6 \, x\right )} + 24 \, a^{3} b e^{\left (6 \, x\right )} - 224 \, a^{2} b^{2} e^{\left (6 \, x\right )} - 24 \, a b^{3} e^{\left (6 \, x\right )} + 124 \, b^{4} e^{\left (6 \, x\right )} + 150 \, a^{4} e^{\left (4 \, x\right )} + 72 \, a^{3} b e^{\left (4 \, x\right )} - 348 \, a^{2} b^{2} e^{\left (4 \, x\right )} - 120 \, a b^{3} e^{\left (4 \, x\right )} + 246 \, b^{4} e^{\left (4 \, x\right )} + 100 \, a^{4} e^{\left (2 \, x\right )} + 72 \, a^{3} b e^{\left (2 \, x\right )} - 224 \, a^{2} b^{2} e^{\left (2 \, x\right )} - 136 \, a b^{3} e^{\left (2 \, x\right )} + 124 \, b^{4} e^{\left (2 \, x\right )} + 25 \, a^{4} + 24 \, a^{3} b - 50 \, a^{2} b^{2} - 40 \, a b^{3} + 25 \, b^{4}}{12 \, b^{5} {\left (e^{\left (2 \, x\right )} + 1\right )}^{4}} \]
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Time = 1.88 (sec) , antiderivative size = 169, normalized size of antiderivative = 2.04 \[ \int \frac {\text {sech}^6(x)}{a+b \tanh (x)} \, dx=\frac {4}{b\,\left (4\,{\mathrm {e}}^{2\,x}+6\,{\mathrm {e}}^{4\,x}+4\,{\mathrm {e}}^{6\,x}+{\mathrm {e}}^{8\,x}+1\right )}+\frac {2\,{\left (a-b\right )}^2}{b^3\,\left (2\,{\mathrm {e}}^{2\,x}+{\mathrm {e}}^{4\,x}+1\right )}+\frac {8\,\left (a-3\,b\right )}{3\,b^2\,\left (3\,{\mathrm {e}}^{2\,x}+3\,{\mathrm {e}}^{4\,x}+{\mathrm {e}}^{6\,x}+1\right )}+\frac {2\,\left (a+b\right )\,{\left (a-b\right )}^2}{b^4\,\left ({\mathrm {e}}^{2\,x}+1\right )}+\frac {\ln \left (a-b+a\,{\mathrm {e}}^{2\,x}+b\,{\mathrm {e}}^{2\,x}\right )\,{\left (a+b\right )}^2\,{\left (a-b\right )}^2}{b^5}-\frac {\ln \left ({\mathrm {e}}^{2\,x}+1\right )\,{\left (a+b\right )}^2\,{\left (a-b\right )}^2}{b^5} \]
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