Integrand size = 17, antiderivative size = 59 \[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=-\frac {1}{x}+\frac {2 \operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{x} \]
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Time = 0.04 (sec) , antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {5658, 5656, 470, 371} \[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\frac {2 \operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{x}-\frac {1}{x} \]
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Rule 371
Rule 470
Rule 5656
Rule 5658
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c x^n\right )^{\frac {1}{n}} \text {Subst}\left (\int x^{-1-\frac {1}{n}} \tanh (d (a+b \log (x))) \, dx,x,c x^n\right )}{n x} \\ & = \frac {\left (c x^n\right )^{\frac {1}{n}} \text {Subst}\left (\int \frac {x^{-1-\frac {1}{n}} \left (-1+e^{2 a d} x^{2 b d}\right )}{1+e^{2 a d} x^{2 b d}} \, dx,x,c x^n\right )}{n x} \\ & = -\frac {1}{x}-\frac {\left (2 \left (c x^n\right )^{\frac {1}{n}}\right ) \text {Subst}\left (\int \frac {x^{-1-\frac {1}{n}}}{1+e^{2 a d} x^{2 b d}} \, dx,x,c x^n\right )}{n x} \\ & = -\frac {1}{x}+\frac {2 \operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{x} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(126\) vs. \(2(59)=118\).
Time = 3.29 (sec) , antiderivative size = 126, normalized size of antiderivative = 2.14 \[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\frac {\frac {e^{2 d \left (a+b \log \left (c x^n\right )\right )} \operatorname {Hypergeometric2F1}\left (1,1-\frac {1}{2 b d n},2-\frac {1}{2 b d n},-e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )}{-1+2 b d n}+\operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},-e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )}{x} \]
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\[\int \frac {\tanh \left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )}{x^{2}}d x\]
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\[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int { \frac {\tanh \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{2}} \,d x } \]
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\[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int \frac {\tanh {\left (a d + b d \log {\left (c x^{n} \right )} \right )}}{x^{2}}\, dx \]
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\[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int { \frac {\tanh \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{2}} \,d x } \]
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\[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int { \frac {\tanh \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{2}} \,d x } \]
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Timed out. \[ \int \frac {\tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int \frac {\mathrm {tanh}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right )}{x^2} \,d x \]
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