Integrand size = 25, antiderivative size = 83 \[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=\frac {e^{c (a+b x)} \coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}}{b c}-\frac {2 \arctan \left (e^{c (a+b x)}\right ) \coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}}{b c} \]
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Time = 0.11 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {6852, 2320, 396, 209} \[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=\frac {e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \coth (a c+b c x)}{b c}-\frac {2 \arctan \left (e^{c (a+b x)}\right ) \sqrt {\tanh ^2(a c+b c x)} \coth (a c+b c x)}{b c} \]
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Rule 209
Rule 396
Rule 2320
Rule 6852
Rubi steps \begin{align*} \text {integral}& = \left (\coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}\right ) \int e^{c (a+b x)} \tanh (a c+b c x) \, dx \\ & = \frac {\left (\coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}\right ) \text {Subst}\left (\int \frac {-1+x^2}{1+x^2} \, dx,x,e^{c (a+b x)}\right )}{b c} \\ & = \frac {e^{c (a+b x)} \coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}}{b c}-\frac {\left (2 \coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,e^{c (a+b x)}\right )}{b c} \\ & = \frac {e^{c (a+b x)} \coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}}{b c}-\frac {2 \arctan \left (e^{c (a+b x)}\right ) \coth (a c+b c x) \sqrt {\tanh ^2(a c+b c x)}}{b c} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.61 \[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=\frac {\left (e^{c (a+b x)}-2 \arctan \left (e^{c (a+b x)}\right )\right ) \coth (c (a+b x)) \sqrt {\tanh ^2(c (a+b x))}}{b c} \]
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Result contains complex when optimal does not.
Time = 0.58 (sec) , antiderivative size = 218, normalized size of antiderivative = 2.63
method | result | size |
risch | \(\frac {\left (1+{\mathrm e}^{2 c \left (b x +a \right )}\right ) \sqrt {\frac {\left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right )^{2}}{\left (1+{\mathrm e}^{2 c \left (b x +a \right )}\right )^{2}}}\, {\mathrm e}^{c \left (b x +a \right )}}{\left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right ) b c}+\frac {i \left (1+{\mathrm e}^{2 c \left (b x +a \right )}\right ) \sqrt {\frac {\left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right )^{2}}{\left (1+{\mathrm e}^{2 c \left (b x +a \right )}\right )^{2}}}\, \ln \left ({\mathrm e}^{c \left (b x +a \right )}-i\right )}{\left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right ) c b}-\frac {i \left (1+{\mathrm e}^{2 c \left (b x +a \right )}\right ) \sqrt {\frac {\left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right )^{2}}{\left (1+{\mathrm e}^{2 c \left (b x +a \right )}\right )^{2}}}\, \ln \left ({\mathrm e}^{c \left (b x +a \right )}+i\right )}{\left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right ) c b}\) | \(218\) |
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Time = 0.26 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.64 \[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=-\frac {2 \, \arctan \left (\cosh \left (b c x + a c\right ) + \sinh \left (b c x + a c\right )\right ) - \cosh \left (b c x + a c\right ) - \sinh \left (b c x + a c\right )}{b c} \]
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\[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=e^{a c} \int \sqrt {\tanh ^{2}{\left (a c + b c x \right )}} e^{b c x}\, dx \]
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Time = 0.29 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.42 \[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=-\frac {2 \, \arctan \left (e^{\left (b c x + a c\right )}\right )}{b c} + \frac {e^{\left (b c x + a c\right )}}{b c} \]
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Time = 0.29 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.72 \[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=-\frac {2 \, \arctan \left (e^{\left (b c x + a c\right )}\right ) \mathrm {sgn}\left (e^{\left (2 \, b c x + 2 \, a c\right )} - 1\right ) - e^{\left (b c x + a c\right )} \mathrm {sgn}\left (e^{\left (2 \, b c x + 2 \, a c\right )} - 1\right )}{b c} \]
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Timed out. \[ \int e^{c (a+b x)} \sqrt {\tanh ^2(a c+b c x)} \, dx=\int {\mathrm {e}}^{c\,\left (a+b\,x\right )}\,\sqrt {{\mathrm {tanh}\left (a\,c+b\,c\,x\right )}^2} \,d x \]
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