Integrand size = 8, antiderivative size = 49 \[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {1+\tanh (x)}}{\sqrt {2}}\right )}{2 \sqrt {2}}-\frac {1}{3 (1+\tanh (x))^{3/2}}-\frac {1}{2 \sqrt {1+\tanh (x)}} \]
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Time = 0.03 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {3560, 3561, 212} \[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {\tanh (x)+1}}{\sqrt {2}}\right )}{2 \sqrt {2}}-\frac {1}{2 \sqrt {\tanh (x)+1}}-\frac {1}{3 (\tanh (x)+1)^{3/2}} \]
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Rule 212
Rule 3560
Rule 3561
Rubi steps \begin{align*} \text {integral}& = -\frac {1}{3 (1+\tanh (x))^{3/2}}+\frac {1}{2} \int \frac {1}{\sqrt {1+\tanh (x)}} \, dx \\ & = -\frac {1}{3 (1+\tanh (x))^{3/2}}-\frac {1}{2 \sqrt {1+\tanh (x)}}+\frac {1}{4} \int \sqrt {1+\tanh (x)} \, dx \\ & = -\frac {1}{3 (1+\tanh (x))^{3/2}}-\frac {1}{2 \sqrt {1+\tanh (x)}}+\frac {1}{2} \text {Subst}\left (\int \frac {1}{2-x^2} \, dx,x,\sqrt {1+\tanh (x)}\right ) \\ & = \frac {\text {arctanh}\left (\frac {\sqrt {1+\tanh (x)}}{\sqrt {2}}\right )}{2 \sqrt {2}}-\frac {1}{3 (1+\tanh (x))^{3/2}}-\frac {1}{2 \sqrt {1+\tanh (x)}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.23 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.57 \[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=-\frac {\operatorname {Hypergeometric2F1}\left (-\frac {3}{2},1,-\frac {1}{2},\frac {1}{2} (1+\tanh (x))\right )}{3 (1+\tanh (x))^{3/2}} \]
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Time = 0.04 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.71
method | result | size |
derivativedivides | \(\frac {\operatorname {arctanh}\left (\frac {\sqrt {1+\tanh \left (x \right )}\, \sqrt {2}}{2}\right ) \sqrt {2}}{4}-\frac {1}{2 \sqrt {1+\tanh \left (x \right )}}-\frac {1}{3 \left (1+\tanh \left (x \right )\right )^{\frac {3}{2}}}\) | \(35\) |
default | \(\frac {\operatorname {arctanh}\left (\frac {\sqrt {1+\tanh \left (x \right )}\, \sqrt {2}}{2}\right ) \sqrt {2}}{4}-\frac {1}{2 \sqrt {1+\tanh \left (x \right )}}-\frac {1}{3 \left (1+\tanh \left (x \right )\right )^{\frac {3}{2}}}\) | \(35\) |
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Leaf count of result is larger than twice the leaf count of optimal. 166 vs. \(2 (34) = 68\).
Time = 0.25 (sec) , antiderivative size = 166, normalized size of antiderivative = 3.39 \[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=-\frac {2 \, \sqrt {2} {\left (4 \, \sqrt {2} \cosh \left (x\right )^{2} + 8 \, \sqrt {2} \cosh \left (x\right ) \sinh \left (x\right ) + 4 \, \sqrt {2} \sinh \left (x\right )^{2} + \sqrt {2}\right )} \sqrt {\frac {\cosh \left (x\right )}{\cosh \left (x\right ) - \sinh \left (x\right )}} - 3 \, {\left (\sqrt {2} \cosh \left (x\right )^{3} + 3 \, \sqrt {2} \cosh \left (x\right )^{2} \sinh \left (x\right ) + 3 \, \sqrt {2} \cosh \left (x\right ) \sinh \left (x\right )^{2} + \sqrt {2} \sinh \left (x\right )^{3}\right )} \log \left (-2 \, \sqrt {2} \sqrt {\frac {\cosh \left (x\right )}{\cosh \left (x\right ) - \sinh \left (x\right )}} {\left (\cosh \left (x\right ) + \sinh \left (x\right )\right )} - 2 \, \cosh \left (x\right )^{2} - 4 \, \cosh \left (x\right ) \sinh \left (x\right ) - 2 \, \sinh \left (x\right )^{2} - 1\right )}{24 \, {\left (\cosh \left (x\right )^{3} + 3 \, \cosh \left (x\right )^{2} \sinh \left (x\right ) + 3 \, \cosh \left (x\right ) \sinh \left (x\right )^{2} + \sinh \left (x\right )^{3}\right )}} \]
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\[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=\int \frac {1}{\left (\tanh {\left (x \right )} + 1\right )^{\frac {3}{2}}}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 69 vs. \(2 (34) = 68\).
Time = 0.28 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.41 \[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=-\frac {1}{12} \, \sqrt {2} {\left (\frac {3}{e^{\left (-2 \, x\right )} + 1} + 1\right )} {\left (e^{\left (-2 \, x\right )} + 1\right )}^{\frac {3}{2}} - \frac {1}{8} \, \sqrt {2} \log \left (-\frac {\sqrt {2} - \frac {\sqrt {2}}{\sqrt {e^{\left (-2 \, x\right )} + 1}}}{\sqrt {2} + \frac {\sqrt {2}}{\sqrt {e^{\left (-2 \, x\right )} + 1}}}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 95 vs. \(2 (34) = 68\).
Time = 0.28 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.94 \[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=-\frac {1}{24} \, \sqrt {2} {\left (\frac {2 \, {\left (6 \, {\left (\sqrt {e^{\left (4 \, x\right )} + e^{\left (2 \, x\right )}} - e^{\left (2 \, x\right )}\right )}^{2} - 3 \, \sqrt {e^{\left (4 \, x\right )} + e^{\left (2 \, x\right )}} + 3 \, e^{\left (2 \, x\right )} + 1\right )}}{{\left (\sqrt {e^{\left (4 \, x\right )} + e^{\left (2 \, x\right )}} - e^{\left (2 \, x\right )}\right )}^{3}} + 3 \, \log \left (-2 \, \sqrt {e^{\left (4 \, x\right )} + e^{\left (2 \, x\right )}} + 2 \, e^{\left (2 \, x\right )} + 1\right )\right )} \]
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Time = 0.11 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.65 \[ \int \frac {1}{(1+\tanh (x))^{3/2}} \, dx=\frac {\sqrt {2}\,\mathrm {atanh}\left (\frac {\sqrt {2}\,\sqrt {\mathrm {tanh}\left (x\right )+1}}{2}\right )}{4}-\frac {\frac {\mathrm {tanh}\left (x\right )}{2}+\frac {5}{6}}{{\left (\mathrm {tanh}\left (x\right )+1\right )}^{3/2}} \]
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