Integrand size = 11, antiderivative size = 45 \[ \int x^2 \coth (a+2 \log (x)) \, dx=\frac {x^3}{3}+e^{-3 a/2} \arctan \left (e^{a/2} x\right )-e^{-3 a/2} \text {arctanh}\left (e^{a/2} x\right ) \]
[Out]
Time = 0.03 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.455, Rules used = {5657, 470, 304, 209, 212} \[ \int x^2 \coth (a+2 \log (x)) \, dx=e^{-3 a/2} \arctan \left (e^{a/2} x\right )-e^{-3 a/2} \text {arctanh}\left (e^{a/2} x\right )+\frac {x^3}{3} \]
[In]
[Out]
Rule 209
Rule 212
Rule 304
Rule 470
Rule 5657
Rubi steps \begin{align*} \text {integral}& = \int \frac {x^2 \left (-1-e^{2 a} x^4\right )}{1-e^{2 a} x^4} \, dx \\ & = \frac {x^3}{3}-2 \int \frac {x^2}{1-e^{2 a} x^4} \, dx \\ & = \frac {x^3}{3}-e^{-a} \int \frac {1}{1-e^a x^2} \, dx+e^{-a} \int \frac {1}{1+e^a x^2} \, dx \\ & = \frac {x^3}{3}+e^{-3 a/2} \arctan \left (e^{a/2} x\right )-e^{-3 a/2} \text {arctanh}\left (e^{a/2} x\right ) \\ \end{align*}
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 0.27 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.42 \[ \int x^2 \coth (a+2 \log (x)) \, dx=\frac {1}{6} \left (2 x^3+3 \text {RootSum}\left [-\cosh (a)+\sinh (a)+\cosh (a) \text {$\#$1}^4+\sinh (a) \text {$\#$1}^4\&,\frac {\log (x)-\log (x-\text {$\#$1})}{\text {$\#$1}}\&\right ] (-\cosh (2 a)+\sinh (2 a))\right ) \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. \(82\) vs. \(2(35)=70\).
Time = 0.11 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.84
method | result | size |
risch | \(\frac {x^{3}}{3}+\frac {\ln \left (\left (-{\mathrm e}^{a}\right )^{\frac {3}{2}}-{\mathrm e}^{2 a} x \right )}{2 \left (-{\mathrm e}^{a}\right )^{\frac {3}{2}}}-\frac {\ln \left (\left (-{\mathrm e}^{a}\right )^{\frac {3}{2}}+{\mathrm e}^{2 a} x \right )}{2 \left (-{\mathrm e}^{a}\right )^{\frac {3}{2}}}+\frac {\ln \left (-\sqrt {{\mathrm e}^{a}}\, x +1\right )}{2 \left ({\mathrm e}^{a}\right )^{\frac {3}{2}}}-\frac {\ln \left (\sqrt {{\mathrm e}^{a}}\, x +1\right )}{2 \left ({\mathrm e}^{a}\right )^{\frac {3}{2}}}\) | \(83\) |
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.38 \[ \int x^2 \coth (a+2 \log (x)) \, dx=\frac {1}{6} \, {\left (2 \, x^{3} e^{\left (2 \, a\right )} + 6 \, \arctan \left (x e^{\left (\frac {1}{2} \, a\right )}\right ) e^{\left (\frac {1}{2} \, a\right )} + 3 \, e^{\left (\frac {1}{2} \, a\right )} \log \left (\frac {x^{2} e^{a} - 2 \, x e^{\left (\frac {1}{2} \, a\right )} + 1}{x^{2} e^{a} - 1}\right )\right )} e^{\left (-2 \, a\right )} \]
[In]
[Out]
\[ \int x^2 \coth (a+2 \log (x)) \, dx=\int x^{2} \coth {\left (a + 2 \log {\left (x \right )} \right )}\, dx \]
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.07 \[ \int x^2 \coth (a+2 \log (x)) \, dx=\frac {1}{3} \, x^{3} + \arctan \left (x e^{\left (\frac {1}{2} \, a\right )}\right ) e^{\left (-\frac {3}{2} \, a\right )} + \frac {1}{2} \, e^{\left (-\frac {3}{2} \, a\right )} \log \left (\frac {x e^{a} - e^{\left (\frac {1}{2} \, a\right )}}{x e^{a} + e^{\left (\frac {1}{2} \, a\right )}}\right ) \]
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.20 \[ \int x^2 \coth (a+2 \log (x)) \, dx=\frac {1}{3} \, x^{3} + \arctan \left (x e^{\left (\frac {1}{2} \, a\right )}\right ) e^{\left (-\frac {3}{2} \, a\right )} + \frac {1}{2} \, e^{\left (-\frac {3}{2} \, a\right )} \log \left (\frac {{\left | 2 \, x e^{a} - 2 \, e^{\left (\frac {1}{2} \, a\right )} \right |}}{{\left | 2 \, x e^{a} + 2 \, e^{\left (\frac {1}{2} \, a\right )} \right |}}\right ) \]
[In]
[Out]
Time = 1.96 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.87 \[ \int x^2 \coth (a+2 \log (x)) \, dx=\frac {\mathrm {atan}\left (x\,{\left ({\mathrm {e}}^{2\,a}\right )}^{1/4}\right )}{{\left ({\mathrm {e}}^{2\,a}\right )}^{3/4}}-\frac {\mathrm {atanh}\left (x\,{\left ({\mathrm {e}}^{2\,a}\right )}^{1/4}\right )}{{\left ({\mathrm {e}}^{2\,a}\right )}^{3/4}}+\frac {x^3}{3} \]
[In]
[Out]