\(\int (e x)^m \coth ^p(a+b \log (x)) \, dx\) [169]

Optimal result

Integrand size = 15, antiderivative size = 99 \[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\frac {(e x)^{1+m} \left (-1-e^{2 a} x^{2 b}\right )^p \left (1+e^{2 a} x^{2 b}\right )^{-p} \operatorname {AppellF1}\left (\frac {1+m}{2 b},p,-p,1+\frac {1+m}{2 b},e^{2 a} x^{2 b},-e^{2 a} x^{2 b}\right )}{e (1+m)} \]

[Out]

(e*x)^(1+m)*(-1-exp(2*a)*x^(2*b))^p*AppellF1(1/2*(1+m)/b,p,-p,1+1/2*(1+m)/b,exp(2*a)*x^(2*b),-exp(2*a)*x^(2*b)
)/e/(1+m)/((1+exp(2*a)*x^(2*b))^p)

Rubi [A] (verified)

Time = 0.06 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {5657, 525, 524} \[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\frac {(e x)^{m+1} \left (-e^{2 a} x^{2 b}-1\right )^p \left (e^{2 a} x^{2 b}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {m+1}{2 b},p,-p,\frac {m+1}{2 b}+1,e^{2 a} x^{2 b},-e^{2 a} x^{2 b}\right )}{e (m+1)} \]

[In]

Int[(e*x)^m*Coth[a + b*Log[x]]^p,x]

[Out]

((e*x)^(1 + m)*(-1 - E^(2*a)*x^(2*b))^p*AppellF1[(1 + m)/(2*b), p, -p, 1 + (1 + m)/(2*b), E^(2*a)*x^(2*b), -(E
^(2*a)*x^(2*b))])/(e*(1 + m)*(1 + E^(2*a)*x^(2*b))^p)

Rule 524

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[a^p*c^q*
((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; Free
Q[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a
, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 525

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[a^IntPar
t[p]*((a + b*x^n)^FracPart[p]/(1 + b*(x^n/a))^FracPart[p]), Int[(e*x)^m*(1 + b*(x^n/a))^p*(c + d*x^n)^q, x], x
] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] &&  !(IntegerQ[
p] || GtQ[a, 0])

Rule 5657

Int[Coth[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.)*((e_.)*(x_))^(m_.), x_Symbol] :> Int[(e*x)^m*((-1 - E^(2*a*d)*x^
(2*b*d))^p/(1 - E^(2*a*d)*x^(2*b*d))^p), x] /; FreeQ[{a, b, d, e, m, p}, x]

Rubi steps \begin{align*} \text {integral}& = \int (e x)^m \left (-1-e^{2 a} x^{2 b}\right )^p \left (1-e^{2 a} x^{2 b}\right )^{-p} \, dx \\ & = \left (\left (-1-e^{2 a} x^{2 b}\right )^p \left (1+e^{2 a} x^{2 b}\right )^{-p}\right ) \int (e x)^m \left (1-e^{2 a} x^{2 b}\right )^{-p} \left (1+e^{2 a} x^{2 b}\right )^p \, dx \\ & = \frac {(e x)^{1+m} \left (-1-e^{2 a} x^{2 b}\right )^p \left (1+e^{2 a} x^{2 b}\right )^{-p} \operatorname {AppellF1}\left (\frac {1+m}{2 b},p,-p,1+\frac {1+m}{2 b},e^{2 a} x^{2 b},-e^{2 a} x^{2 b}\right )}{e (1+m)} \\ \end{align*}

Mathematica [A] (warning: unable to verify)

Time = 0.78 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.27 \[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\frac {x (e x)^m \left (1-e^{2 a} x^{2 b}\right )^p \left (1+e^{2 a} x^{2 b}\right )^{-p} \left (\frac {1+e^{2 a} x^{2 b}}{-1+e^{2 a} x^{2 b}}\right )^p \operatorname {AppellF1}\left (\frac {1+m}{2 b},p,-p,1+\frac {1+m}{2 b},e^{2 a} x^{2 b},-e^{2 a} x^{2 b}\right )}{1+m} \]

[In]

Integrate[(e*x)^m*Coth[a + b*Log[x]]^p,x]

[Out]

(x*(e*x)^m*(1 - E^(2*a)*x^(2*b))^p*((1 + E^(2*a)*x^(2*b))/(-1 + E^(2*a)*x^(2*b)))^p*AppellF1[(1 + m)/(2*b), p,
-p, 1 + (1 + m)/(2*b), E^(2*a)*x^(2*b), -(E^(2*a)*x^(2*b))])/((1 + m)*(1 + E^(2*a)*x^(2*b))^p)

Maple [F]

\[\int \left (e x \right )^{m} \coth \left (a +b \ln \left (x \right )\right )^{p}d x\]

[In]

int((e*x)^m*coth(a+b*ln(x))^p,x)

[Out]

int((e*x)^m*coth(a+b*ln(x))^p,x)

Fricas [F]

\[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\int { \left (e x\right )^{m} \coth \left (b \log \left (x\right ) + a\right )^{p} \,d x } \]

[In]

integrate((e*x)^m*coth(a+b*log(x))^p,x, algorithm="fricas")

[Out]

integral((e*x)^m*coth(b*log(x) + a)^p, x)

Sympy [F]

\[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\int \left (e x\right )^{m} \coth ^{p}{\left (a + b \log {\left (x \right )} \right )}\, dx \]

[In]

integrate((e*x)**m*coth(a+b*ln(x))**p,x)

[Out]

Integral((e*x)**m*coth(a + b*log(x))**p, x)

Maxima [F]

\[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\int { \left (e x\right )^{m} \coth \left (b \log \left (x\right ) + a\right )^{p} \,d x } \]

[In]

integrate((e*x)^m*coth(a+b*log(x))^p,x, algorithm="maxima")

[Out]

integrate((e*x)^m*coth(b*log(x) + a)^p, x)

Giac [F]

\[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\int { \left (e x\right )^{m} \coth \left (b \log \left (x\right ) + a\right )^{p} \,d x } \]

[In]

integrate((e*x)^m*coth(a+b*log(x))^p,x, algorithm="giac")

[Out]

integrate((e*x)^m*coth(b*log(x) + a)^p, x)

Mupad [F(-1)]

Timed out. \[ \int (e x)^m \coth ^p(a+b \log (x)) \, dx=\int {\mathrm {coth}\left (a+b\,\ln \left (x\right )\right )}^p\,{\left (e\,x\right )}^m \,d x \]

[In]

int(coth(a + b*log(x))^p*(e*x)^m,x)

[Out]

int(coth(a + b*log(x))^p*(e*x)^m, x)