\(\int \frac {\coth (d (a+b \log (c x^n)))}{x^2} \, dx\) [182]

   Optimal result
   Rubi [A] (verified)
   Mathematica [B] (verified)
   Maple [F]
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 17, antiderivative size = 58 \[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=-\frac {1}{x}+\frac {2 \operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{x} \]

[Out]

-1/x+2*hypergeom([1, -1/2/b/d/n],[1-1/2/b/d/n],exp(2*a*d)*(c*x^n)^(2*b*d))/x

Rubi [A] (verified)

Time = 0.05 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {5659, 5657, 470, 371} \[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\frac {2 \operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{x}-\frac {1}{x} \]

[In]

Int[Coth[d*(a + b*Log[c*x^n])]/x^2,x]

[Out]

-x^(-1) + (2*Hypergeometric2F1[1, -1/2*1/(b*d*n), 1 - 1/(2*b*d*n), E^(2*a*d)*(c*x^n)^(2*b*d)])/x

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
 (ILtQ[p, 0] || GtQ[a, 0])

Rule 470

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[d*(e*x)^(m +
 1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p + 1) + 1))), x] - Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m +
 n*(p + 1) + 1)), Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0]
 && NeQ[m + n*(p + 1) + 1, 0]

Rule 5657

Int[Coth[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.)*((e_.)*(x_))^(m_.), x_Symbol] :> Int[(e*x)^m*((-1 - E^(2*a*d)*x^
(2*b*d))^p/(1 - E^(2*a*d)*x^(2*b*d))^p), x] /; FreeQ[{a, b, d, e, m, p}, x]

Rule 5659

Int[Coth[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_.)*((e_.)*(x_))^(m_.), x_Symbol] :> Dist[(e*x)^(m + 1
)/(e*n*(c*x^n)^((m + 1)/n)), Subst[Int[x^((m + 1)/n - 1)*Coth[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[
{a, b, c, d, e, m, n, p}, x] && (NeQ[c, 1] || NeQ[n, 1])

Rubi steps \begin{align*} \text {integral}& = \frac {\left (c x^n\right )^{\frac {1}{n}} \text {Subst}\left (\int x^{-1-\frac {1}{n}} \coth (d (a+b \log (x))) \, dx,x,c x^n\right )}{n x} \\ & = \frac {\left (c x^n\right )^{\frac {1}{n}} \text {Subst}\left (\int \frac {x^{-1-\frac {1}{n}} \left (-1-e^{2 a d} x^{2 b d}\right )}{1-e^{2 a d} x^{2 b d}} \, dx,x,c x^n\right )}{n x} \\ & = -\frac {1}{x}-\frac {\left (2 \left (c x^n\right )^{\frac {1}{n}}\right ) \text {Subst}\left (\int \frac {x^{-1-\frac {1}{n}}}{1-e^{2 a d} x^{2 b d}} \, dx,x,c x^n\right )}{n x} \\ & = -\frac {1}{x}+\frac {2 \operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{x} \\ \end{align*}

Mathematica [B] (verified)

Leaf count is larger than twice the leaf count of optimal. \(197\) vs. \(2(58)=116\).

Time = 3.88 (sec) , antiderivative size = 197, normalized size of antiderivative = 3.40 \[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )-\coth \left (d \left (a-b n \log (x)+b \log \left (c x^n\right )\right )\right )-\frac {e^{2 d \left (a+b \log \left (c x^n\right )\right )} \operatorname {Hypergeometric2F1}\left (1,1-\frac {1}{2 b d n},2-\frac {1}{2 b d n},e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )}{-1+2 b d n}+\operatorname {Hypergeometric2F1}\left (1,-\frac {1}{2 b d n},1-\frac {1}{2 b d n},e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )+\text {csch}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \text {csch}\left (d \left (a-b n \log (x)+b \log \left (c x^n\right )\right )\right ) \sinh (b d n \log (x))}{x} \]

[In]

Integrate[Coth[d*(a + b*Log[c*x^n])]/x^2,x]

[Out]

(Coth[d*(a + b*Log[c*x^n])] - Coth[d*(a - b*n*Log[x] + b*Log[c*x^n])] - (E^(2*d*(a + b*Log[c*x^n]))*Hypergeome
tric2F1[1, 1 - 1/(2*b*d*n), 2 - 1/(2*b*d*n), E^(2*d*(a + b*Log[c*x^n]))])/(-1 + 2*b*d*n) + Hypergeometric2F1[1
, -1/2*1/(b*d*n), 1 - 1/(2*b*d*n), E^(2*d*(a + b*Log[c*x^n]))] + Csch[d*(a + b*Log[c*x^n])]*Csch[d*(a - b*n*Lo
g[x] + b*Log[c*x^n])]*Sinh[b*d*n*Log[x]])/x

Maple [F]

\[\int \frac {\coth \left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )}{x^{2}}d x\]

[In]

int(coth(d*(a+b*ln(c*x^n)))/x^2,x)

[Out]

int(coth(d*(a+b*ln(c*x^n)))/x^2,x)

Fricas [F]

\[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int { \frac {\coth \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{2}} \,d x } \]

[In]

integrate(coth(d*(a+b*log(c*x^n)))/x^2,x, algorithm="fricas")

[Out]

integral(coth(b*d*log(c*x^n) + a*d)/x^2, x)

Sympy [F]

\[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int \frac {\coth {\left (a d + b d \log {\left (c x^{n} \right )} \right )}}{x^{2}}\, dx \]

[In]

integrate(coth(d*(a+b*ln(c*x**n)))/x**2,x)

[Out]

Integral(coth(a*d + b*d*log(c*x**n))/x**2, x)

Maxima [F]

\[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int { \frac {\coth \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{2}} \,d x } \]

[In]

integrate(coth(d*(a+b*log(c*x^n)))/x^2,x, algorithm="maxima")

[Out]

-1/x - integrate(1/(c^(b*d)*x^2*e^(b*d*log(x^n) + a*d) + x^2), x) + integrate(1/(c^(b*d)*x^2*e^(b*d*log(x^n) +
 a*d) - x^2), x)

Giac [F]

\[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int { \frac {\coth \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{2}} \,d x } \]

[In]

integrate(coth(d*(a+b*log(c*x^n)))/x^2,x, algorithm="giac")

[Out]

integrate(coth((b*log(c*x^n) + a)*d)/x^2, x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\coth \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^2} \, dx=\int \frac {\mathrm {coth}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right )}{x^2} \,d x \]

[In]

int(coth(d*(a + b*log(c*x^n)))/x^2,x)

[Out]

int(coth(d*(a + b*log(c*x^n)))/x^2, x)