Integrand size = 13, antiderivative size = 55 \[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=\frac {x}{a}-\frac {\coth (x) (15-8 \text {sech}(x))}{15 a}-\frac {\coth ^3(x) (5-4 \text {sech}(x))}{15 a}-\frac {\coth ^5(x) (1-\text {sech}(x))}{5 a} \]
[Out]
Time = 0.09 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {3973, 3967, 8} \[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=\frac {x}{a}-\frac {\coth ^5(x) (1-\text {sech}(x))}{5 a}-\frac {\coth ^3(x) (5-4 \text {sech}(x))}{15 a}-\frac {\coth (x) (15-8 \text {sech}(x))}{15 a} \]
[In]
[Out]
Rule 8
Rule 3967
Rule 3973
Rubi steps \begin{align*} \text {integral}& = -\frac {\int \coth ^6(x) (-a+a \text {sech}(x)) \, dx}{a^2} \\ & = -\frac {\coth ^5(x) (1-\text {sech}(x))}{5 a}+\frac {\int \coth ^4(x) (5 a-4 a \text {sech}(x)) \, dx}{5 a^2} \\ & = -\frac {\coth ^3(x) (5-4 \text {sech}(x))}{15 a}-\frac {\coth ^5(x) (1-\text {sech}(x))}{5 a}-\frac {\int \coth ^2(x) (-15 a+8 a \text {sech}(x)) \, dx}{15 a^2} \\ & = -\frac {\coth (x) (15-8 \text {sech}(x))}{15 a}-\frac {\coth ^3(x) (5-4 \text {sech}(x))}{15 a}-\frac {\coth ^5(x) (1-\text {sech}(x))}{5 a}+\frac {\int 15 a \, dx}{15 a^2} \\ & = \frac {x}{a}-\frac {\coth (x) (15-8 \text {sech}(x))}{15 a}-\frac {\coth ^3(x) (5-4 \text {sech}(x))}{15 a}-\frac {\coth ^5(x) (1-\text {sech}(x))}{5 a} \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.25 \[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=\frac {\text {csch}^3(x) \text {sech}(x) (-25+8 \cosh (x)+16 \cosh (2 x)-16 \cosh (3 x)-23 \cosh (4 x)-90 x \sinh (x)-30 x \sinh (2 x)+30 x \sinh (3 x)+15 x \sinh (4 x))}{120 a (1+\text {sech}(x))} \]
[In]
[Out]
Time = 0.27 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.15
method | result | size |
default | \(\frac {-\frac {\tanh \left (\frac {x}{2}\right )^{5}}{5}-2 \tanh \left (\frac {x}{2}\right )^{3}-16 \tanh \left (\frac {x}{2}\right )+16 \ln \left (\tanh \left (\frac {x}{2}\right )+1\right )-16 \ln \left (\tanh \left (\frac {x}{2}\right )-1\right )-\frac {1}{3 \tanh \left (\frac {x}{2}\right )^{3}}-\frac {6}{\tanh \left (\frac {x}{2}\right )}}{16 a}\) | \(63\) |
risch | \(\frac {x}{a}+\frac {2 \,{\mathrm e}^{7 x}-2 \,{\mathrm e}^{6 x}-\frac {26 \,{\mathrm e}^{5 x}}{3}-\frac {10 \,{\mathrm e}^{4 x}}{3}+\frac {146 \,{\mathrm e}^{3 x}}{15}+\frac {62 \,{\mathrm e}^{2 x}}{15}-\frac {62 \,{\mathrm e}^{x}}{15}-\frac {46}{15}}{a \left ({\mathrm e}^{x}-1\right )^{3} \left ({\mathrm e}^{x}+1\right )^{5}}\) | \(66\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 151 vs. \(2 (47) = 94\).
Time = 0.25 (sec) , antiderivative size = 151, normalized size of antiderivative = 2.75 \[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=-\frac {23 \, \cosh \left (x\right )^{4} - 2 \, {\left (2 \, {\left (15 \, x + 23\right )} \cosh \left (x\right ) + 15 \, x + 23\right )} \sinh \left (x\right )^{3} + 23 \, \sinh \left (x\right )^{4} + 16 \, \cosh \left (x\right )^{3} + 2 \, {\left (69 \, \cosh \left (x\right )^{2} + 24 \, \cosh \left (x\right ) - 8\right )} \sinh \left (x\right )^{2} - 16 \, \cosh \left (x\right )^{2} - 2 \, {\left (2 \, {\left (15 \, x + 23\right )} \cosh \left (x\right )^{3} + 3 \, {\left (15 \, x + 23\right )} \cosh \left (x\right )^{2} - 2 \, {\left (15 \, x + 23\right )} \cosh \left (x\right ) - 45 \, x - 69\right )} \sinh \left (x\right ) - 8 \, \cosh \left (x\right ) + 25}{30 \, {\left ({\left (2 \, a \cosh \left (x\right ) + a\right )} \sinh \left (x\right )^{3} + {\left (2 \, a \cosh \left (x\right )^{3} + 3 \, a \cosh \left (x\right )^{2} - 2 \, a \cosh \left (x\right ) - 3 \, a\right )} \sinh \left (x\right )\right )}} \]
[In]
[Out]
\[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=\frac {\int \frac {\coth ^{4}{\left (x \right )}}{\operatorname {sech}{\left (x \right )} + 1}\, dx}{a} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 105 vs. \(2 (47) = 94\).
Time = 0.21 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.91 \[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=\frac {x}{a} - \frac {2 \, {\left (31 \, e^{\left (-x\right )} - 31 \, e^{\left (-2 \, x\right )} - 73 \, e^{\left (-3 \, x\right )} + 25 \, e^{\left (-4 \, x\right )} + 65 \, e^{\left (-5 \, x\right )} + 15 \, e^{\left (-6 \, x\right )} - 15 \, e^{\left (-7 \, x\right )} + 23\right )}}{15 \, {\left (2 \, a e^{\left (-x\right )} - 2 \, a e^{\left (-2 \, x\right )} - 6 \, a e^{\left (-3 \, x\right )} + 6 \, a e^{\left (-5 \, x\right )} + 2 \, a e^{\left (-6 \, x\right )} - 2 \, a e^{\left (-7 \, x\right )} - a e^{\left (-8 \, x\right )} + a\right )}} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.16 \[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=\frac {x}{a} - \frac {21 \, e^{\left (2 \, x\right )} - 36 \, e^{x} + 19}{24 \, a {\left (e^{x} - 1\right )}^{3}} + \frac {115 \, e^{\left (4 \, x\right )} + 380 \, e^{\left (3 \, x\right )} + 530 \, e^{\left (2 \, x\right )} + 340 \, e^{x} + 91}{40 \, a {\left (e^{x} + 1\right )}^{5}} \]
[In]
[Out]
Time = 2.20 (sec) , antiderivative size = 264, normalized size of antiderivative = 4.80 \[ \int \frac {\coth ^4(x)}{a+a \text {sech}(x)} \, dx=\frac {\frac {9\,{\mathrm {e}}^{2\,x}}{4\,a}+\frac {3\,{\mathrm {e}}^{3\,x}}{2\,a}+\frac {23\,{\mathrm {e}}^{4\,x}}{40\,a}+\frac {23}{40\,a}+\frac {3\,{\mathrm {e}}^x}{2\,a}}{10\,{\mathrm {e}}^{2\,x}+10\,{\mathrm {e}}^{3\,x}+5\,{\mathrm {e}}^{4\,x}+{\mathrm {e}}^{5\,x}+5\,{\mathrm {e}}^x+1}+\frac {\frac {9\,{\mathrm {e}}^{2\,x}}{8\,a}+\frac {23\,{\mathrm {e}}^{3\,x}}{40\,a}+\frac {3}{8\,a}+\frac {9\,{\mathrm {e}}^x}{8\,a}}{6\,{\mathrm {e}}^{2\,x}+4\,{\mathrm {e}}^{3\,x}+{\mathrm {e}}^{4\,x}+4\,{\mathrm {e}}^x+1}+\frac {\frac {23\,{\mathrm {e}}^{2\,x}}{40\,a}+\frac {3}{8\,a}+\frac {3\,{\mathrm {e}}^x}{4\,a}}{3\,{\mathrm {e}}^{2\,x}+{\mathrm {e}}^{3\,x}+3\,{\mathrm {e}}^x+1}+\frac {\frac {3}{8\,a}+\frac {23\,{\mathrm {e}}^x}{40\,a}}{{\mathrm {e}}^{2\,x}+2\,{\mathrm {e}}^x+1}+\frac {1}{6\,a\,\left (3\,{\mathrm {e}}^{2\,x}-{\mathrm {e}}^{3\,x}-3\,{\mathrm {e}}^x+1\right )}-\frac {1}{4\,a\,\left ({\mathrm {e}}^{2\,x}-2\,{\mathrm {e}}^x+1\right )}+\frac {x}{a}-\frac {7}{8\,a\,\left ({\mathrm {e}}^x-1\right )}+\frac {23}{40\,a\,\left ({\mathrm {e}}^x+1\right )} \]
[In]
[Out]