Integrand size = 13, antiderivative size = 87 \[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\frac {x^2}{3 \sqrt {\text {sech}(2 \log (c x))}}-\frac {\sqrt {\frac {c^4+\frac {1}{x^4}}{\left (c^2+\frac {1}{x^2}\right )^2}} \left (c^2+\frac {1}{x^2}\right ) \operatorname {EllipticF}\left (2 \cot ^{-1}(c x),\frac {1}{2}\right )}{3 c \left (c^4+\frac {1}{x^4}\right ) x \sqrt {\text {sech}(2 \log (c x))}} \]
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Time = 0.04 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {5670, 5668, 342, 283, 226} \[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\frac {x^2}{3 \sqrt {\text {sech}(2 \log (c x))}}-\frac {\sqrt {\frac {c^4+\frac {1}{x^4}}{\left (c^2+\frac {1}{x^2}\right )^2}} \left (c^2+\frac {1}{x^2}\right ) \operatorname {EllipticF}\left (2 \cot ^{-1}(c x),\frac {1}{2}\right )}{3 c x \left (c^4+\frac {1}{x^4}\right ) \sqrt {\text {sech}(2 \log (c x))}} \]
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Rule 226
Rule 283
Rule 342
Rule 5668
Rule 5670
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x}{\sqrt {\text {sech}(2 \log (x))}} \, dx,x,c x\right )}{c^2} \\ & = \frac {\text {Subst}\left (\int \sqrt {1+\frac {1}{x^4}} x^2 \, dx,x,c x\right )}{c^3 \sqrt {1+\frac {1}{c^4 x^4}} x \sqrt {\text {sech}(2 \log (c x))}} \\ & = -\frac {\text {Subst}\left (\int \frac {\sqrt {1+x^4}}{x^4} \, dx,x,\frac {1}{c x}\right )}{c^3 \sqrt {1+\frac {1}{c^4 x^4}} x \sqrt {\text {sech}(2 \log (c x))}} \\ & = \frac {x^2}{3 \sqrt {\text {sech}(2 \log (c x))}}-\frac {2 \text {Subst}\left (\int \frac {1}{\sqrt {1+x^4}} \, dx,x,\frac {1}{c x}\right )}{3 c^3 \sqrt {1+\frac {1}{c^4 x^4}} x \sqrt {\text {sech}(2 \log (c x))}} \\ & = \frac {x^2}{3 \sqrt {\text {sech}(2 \log (c x))}}-\frac {\sqrt {\frac {c^4+\frac {1}{x^4}}{\left (c^2+\frac {1}{x^2}\right )^2}} \left (c^2+\frac {1}{x^2}\right ) \operatorname {EllipticF}\left (2 \cot ^{-1}(c x),\frac {1}{2}\right )}{3 c \left (c^4+\frac {1}{x^4}\right ) x \sqrt {\text {sech}(2 \log (c x))}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.19 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.67 \[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\frac {\sqrt {1+c^4 x^4} \sqrt {\frac {c^2 x^2}{2+2 c^4 x^4}} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1}{4},\frac {5}{4},-c^4 x^4\right )}{c^2} \]
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Result contains complex when optimal does not.
Time = 0.57 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.31
method | result | size |
risch | \(\frac {\sqrt {2}\, x^{2}}{6 \sqrt {\frac {c^{2} x^{2}}{c^{4} x^{4}+1}}}+\frac {\sqrt {-i c^{2} x^{2}+1}\, \sqrt {i c^{2} x^{2}+1}\, \operatorname {EllipticF}\left (x \sqrt {i c^{2}}, i\right ) \sqrt {2}\, x}{3 \sqrt {i c^{2}}\, \left (c^{4} x^{4}+1\right ) \sqrt {\frac {c^{2} x^{2}}{c^{4} x^{4}+1}}}\) | \(114\) |
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none
Time = 0.08 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.82 \[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\frac {2 \, \sqrt {2} \sqrt {c^{4}} c \left (-\frac {1}{c^{4}}\right )^{\frac {3}{4}} F(\arcsin \left (\frac {\left (-\frac {1}{c^{4}}\right )^{\frac {1}{4}}}{x}\right )\,|\,-1) + \sqrt {2} {\left (c^{4} x^{4} + 1\right )} \sqrt {\frac {c^{2} x^{2}}{c^{4} x^{4} + 1}}}{6 \, c^{2}} \]
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\[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\int \frac {x}{\sqrt {\operatorname {sech}{\left (2 \log {\left (c x \right )} \right )}}}\, dx \]
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\[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\int { \frac {x}{\sqrt {\operatorname {sech}\left (2 \, \log \left (c x\right )\right )}} \,d x } \]
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Exception generated. \[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {x}{\sqrt {\text {sech}(2 \log (c x))}} \, dx=\int \frac {x}{\sqrt {\frac {1}{\mathrm {cosh}\left (2\,\ln \left (c\,x\right )\right )}}} \,d x \]
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