Integrand size = 11, antiderivative size = 61 \[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=-\frac {b \arctan (\sinh (x))}{a^2+b^2}+\frac {b^2 \log (a+b \text {csch}(x))}{a \left (a^2+b^2\right )}+\frac {\log (\sinh (x))}{a}-\frac {a \log (\tanh (x))}{a^2+b^2} \]
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Time = 0.07 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.455, Rules used = {3970, 908, 649, 209, 266} \[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=-\frac {b \arctan (\sinh (x))}{a^2+b^2}-\frac {a \log (\tanh (x))}{a^2+b^2}+\frac {b^2 \log (a+b \text {csch}(x))}{a \left (a^2+b^2\right )}+\frac {\log (\sinh (x))}{a} \]
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Rule 209
Rule 266
Rule 649
Rule 908
Rule 3970
Rubi steps \begin{align*} \text {integral}& = b^2 \text {Subst}\left (\int \frac {1}{x (a+x) \left (-b^2-x^2\right )} \, dx,x,b \text {csch}(x)\right ) \\ & = b^2 \text {Subst}\left (\int \left (-\frac {1}{a b^2 x}+\frac {1}{a \left (a^2+b^2\right ) (a+x)}+\frac {b^2+a x}{b^2 \left (a^2+b^2\right ) \left (b^2+x^2\right )}\right ) \, dx,x,b \text {csch}(x)\right ) \\ & = \frac {b^2 \log (a+b \text {csch}(x))}{a \left (a^2+b^2\right )}+\frac {\log (\sinh (x))}{a}+\frac {\text {Subst}\left (\int \frac {b^2+a x}{b^2+x^2} \, dx,x,b \text {csch}(x)\right )}{a^2+b^2} \\ & = \frac {b^2 \log (a+b \text {csch}(x))}{a \left (a^2+b^2\right )}+\frac {\log (\sinh (x))}{a}+\frac {a \text {Subst}\left (\int \frac {x}{b^2+x^2} \, dx,x,b \text {csch}(x)\right )}{a^2+b^2}+\frac {b^2 \text {Subst}\left (\int \frac {1}{b^2+x^2} \, dx,x,b \text {csch}(x)\right )}{a^2+b^2} \\ & = -\frac {b \arctan (\sinh (x))}{a^2+b^2}+\frac {b^2 \log (a+b \text {csch}(x))}{a \left (a^2+b^2\right )}+\frac {\log (\sinh (x))}{a}-\frac {a \log (\tanh (x))}{a^2+b^2} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.04 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.03 \[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=\frac {a (a+i b) \log (i-\sinh (x))+a (a-i b) \log (i+\sinh (x))+2 b^2 \log (b+a \sinh (x))}{2 a \left (a^2+b^2\right )} \]
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Time = 0.30 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.59
method | result | size |
default | \(\frac {4 a \ln \left (1+\tanh \left (\frac {x}{2}\right )^{2}\right )-8 b \arctan \left (\tanh \left (\frac {x}{2}\right )\right )}{4 a^{2}+4 b^{2}}+\frac {b^{2} \ln \left (-\tanh \left (\frac {x}{2}\right )^{2} b +2 a \tanh \left (\frac {x}{2}\right )+b \right )}{a \left (a^{2}+b^{2}\right )}-\frac {\ln \left (\tanh \left (\frac {x}{2}\right )-1\right )}{a}-\frac {\ln \left (\tanh \left (\frac {x}{2}\right )+1\right )}{a}\) | \(97\) |
risch | \(\frac {x}{a}-\frac {2 a x}{a^{2}+b^{2}}-\frac {2 b^{2} x}{a \left (a^{2}+b^{2}\right )}+\frac {i \ln \left ({\mathrm e}^{x}-i\right ) b}{a^{2}+b^{2}}+\frac {\ln \left ({\mathrm e}^{x}-i\right ) a}{a^{2}+b^{2}}-\frac {i \ln \left ({\mathrm e}^{x}+i\right ) b}{a^{2}+b^{2}}+\frac {\ln \left ({\mathrm e}^{x}+i\right ) a}{a^{2}+b^{2}}+\frac {b^{2} \ln \left ({\mathrm e}^{2 x}+\frac {2 b \,{\mathrm e}^{x}}{a}-1\right )}{a \left (a^{2}+b^{2}\right )}\) | \(141\) |
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Time = 0.30 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.23 \[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=-\frac {2 \, a b \arctan \left (\cosh \left (x\right ) + \sinh \left (x\right )\right ) - b^{2} \log \left (\frac {2 \, {\left (a \sinh \left (x\right ) + b\right )}}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) - a^{2} \log \left (\frac {2 \, \cosh \left (x\right )}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) + {\left (a^{2} + b^{2}\right )} x}{a^{3} + a b^{2}} \]
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\[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=\int \frac {\tanh {\left (x \right )}}{a + b \operatorname {csch}{\left (x \right )}}\, dx \]
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Time = 0.28 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.21 \[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=\frac {b^{2} \log \left (-2 \, b e^{\left (-x\right )} + a e^{\left (-2 \, x\right )} - a\right )}{a^{3} + a b^{2}} + \frac {2 \, b \arctan \left (e^{\left (-x\right )}\right )}{a^{2} + b^{2}} + \frac {a \log \left (e^{\left (-2 \, x\right )} + 1\right )}{a^{2} + b^{2}} + \frac {x}{a} \]
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Time = 0.28 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.46 \[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=\frac {b^{2} \log \left ({\left | -a {\left (e^{\left (-x\right )} - e^{x}\right )} + 2 \, b \right |}\right )}{a^{3} + a b^{2}} - \frac {{\left (\pi + 2 \, \arctan \left (\frac {1}{2} \, {\left (e^{\left (2 \, x\right )} - 1\right )} e^{\left (-x\right )}\right )\right )} b}{2 \, {\left (a^{2} + b^{2}\right )}} + \frac {a \log \left ({\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 4\right )}{2 \, {\left (a^{2} + b^{2}\right )}} \]
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Time = 3.16 (sec) , antiderivative size = 132, normalized size of antiderivative = 2.16 \[ \int \frac {\tanh (x)}{a+b \text {csch}(x)} \, dx=\frac {\ln \left (1+{\mathrm {e}}^x\,1{}\mathrm {i}\right )}{a-b\,1{}\mathrm {i}}-\frac {x}{a}+\frac {b^2\,\ln \left (a^5\,{\mathrm {e}}^{2\,x}-a\,b^4-a^5+a^3\,b^2+2\,b^5\,{\mathrm {e}}^x-a^3\,b^2\,{\mathrm {e}}^{2\,x}+2\,a^4\,b\,{\mathrm {e}}^x+a\,b^4\,{\mathrm {e}}^{2\,x}-2\,a^2\,b^3\,{\mathrm {e}}^x\right )}{a^3+a\,b^2}+\frac {\ln \left ({\mathrm {e}}^x+1{}\mathrm {i}\right )\,1{}\mathrm {i}}{-b+a\,1{}\mathrm {i}} \]
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