Integrand size = 10, antiderivative size = 80 \[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=-\frac {2 \cosh (a+b x) \text {csch}^{\frac {3}{2}}(a+b x)}{3 b}+\frac {2 i \sqrt {\text {csch}(a+b x)} \operatorname {EllipticF}\left (\frac {1}{2} \left (i a-\frac {\pi }{2}+i b x\right ),2\right ) \sqrt {i \sinh (a+b x)}}{3 b} \]
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Time = 0.03 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {3853, 3856, 2720} \[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=-\frac {2 \cosh (a+b x) \text {csch}^{\frac {3}{2}}(a+b x)}{3 b}+\frac {2 i \sqrt {i \sinh (a+b x)} \sqrt {\text {csch}(a+b x)} \operatorname {EllipticF}\left (\frac {1}{2} \left (i a+i b x-\frac {\pi }{2}\right ),2\right )}{3 b} \]
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Rule 2720
Rule 3853
Rule 3856
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \cosh (a+b x) \text {csch}^{\frac {3}{2}}(a+b x)}{3 b}-\frac {1}{3} \int \sqrt {\text {csch}(a+b x)} \, dx \\ & = -\frac {2 \cosh (a+b x) \text {csch}^{\frac {3}{2}}(a+b x)}{3 b}-\frac {1}{3} \left (\sqrt {\text {csch}(a+b x)} \sqrt {i \sinh (a+b x)}\right ) \int \frac {1}{\sqrt {i \sinh (a+b x)}} \, dx \\ & = -\frac {2 \cosh (a+b x) \text {csch}^{\frac {3}{2}}(a+b x)}{3 b}+\frac {2 i \sqrt {\text {csch}(a+b x)} \operatorname {EllipticF}\left (\frac {1}{2} \left (i a-\frac {\pi }{2}+i b x\right ),2\right ) \sqrt {i \sinh (a+b x)}}{3 b} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.76 \[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=-\frac {2 \sqrt {\text {csch}(a+b x)} \left (\coth (a+b x)+i \operatorname {EllipticF}\left (\frac {1}{4} (-2 i a+\pi -2 i b x),2\right ) \sqrt {i \sinh (a+b x)}\right )}{3 b} \]
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Time = 0.36 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.26
method | result | size |
default | \(-\frac {i \sqrt {1-i \sinh \left (b x +a \right )}\, \sqrt {2}\, \sqrt {1+i \sinh \left (b x +a \right )}\, \sqrt {i \sinh \left (b x +a \right )}\, \operatorname {EllipticF}\left (\sqrt {1-i \sinh \left (b x +a \right )}, \frac {\sqrt {2}}{2}\right ) \sinh \left (b x +a \right )+2 \cosh \left (b x +a \right )^{2}}{3 \sinh \left (b x +a \right )^{\frac {3}{2}} \cosh \left (b x +a \right ) b}\) | \(101\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.08 (sec) , antiderivative size = 194, normalized size of antiderivative = 2.42 \[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=-\frac {2 \, {\left (\sqrt {2} {\left (\cosh \left (b x + a\right )^{2} + 2 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + \sinh \left (b x + a\right )^{2} + 1\right )} \sqrt {\frac {\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )}{\cosh \left (b x + a\right )^{2} + 2 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + \sinh \left (b x + a\right )^{2} - 1}} + {\left (\sqrt {2} \cosh \left (b x + a\right )^{2} + 2 \, \sqrt {2} \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + \sqrt {2} \sinh \left (b x + a\right )^{2} - \sqrt {2}\right )} {\rm weierstrassPInverse}\left (4, 0, \cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right )\right )}}{3 \, {\left (b \cosh \left (b x + a\right )^{2} + 2 \, b \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + b \sinh \left (b x + a\right )^{2} - b\right )}} \]
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\[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=\int \operatorname {csch}^{\frac {5}{2}}{\left (a + b x \right )}\, dx \]
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\[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=\int { \operatorname {csch}\left (b x + a\right )^{\frac {5}{2}} \,d x } \]
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\[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=\int { \operatorname {csch}\left (b x + a\right )^{\frac {5}{2}} \,d x } \]
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Timed out. \[ \int \text {csch}^{\frac {5}{2}}(a+b x) \, dx=\int {\left (\frac {1}{\mathrm {sinh}\left (a+b\,x\right )}\right )}^{5/2} \,d x \]
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