Integrand size = 12, antiderivative size = 84 \[ \int (b \text {csch}(c+d x))^{3/2} \, dx=-\frac {2 b \cosh (c+d x) \sqrt {b \text {csch}(c+d x)}}{d}-\frac {2 i b^2 E\left (\left .\frac {1}{2} \left (i c-\frac {\pi }{2}+i d x\right )\right |2\right )}{d \sqrt {b \text {csch}(c+d x)} \sqrt {i \sinh (c+d x)}} \]
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Time = 0.03 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3853, 3856, 2719} \[ \int (b \text {csch}(c+d x))^{3/2} \, dx=-\frac {2 b \cosh (c+d x) \sqrt {b \text {csch}(c+d x)}}{d}-\frac {2 i b^2 E\left (\left .\frac {1}{2} \left (i c+i d x-\frac {\pi }{2}\right )\right |2\right )}{d \sqrt {i \sinh (c+d x)} \sqrt {b \text {csch}(c+d x)}} \]
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Rule 2719
Rule 3853
Rule 3856
Rubi steps \begin{align*} \text {integral}& = -\frac {2 b \cosh (c+d x) \sqrt {b \text {csch}(c+d x)}}{d}+b^2 \int \frac {1}{\sqrt {b \text {csch}(c+d x)}} \, dx \\ & = -\frac {2 b \cosh (c+d x) \sqrt {b \text {csch}(c+d x)}}{d}+\frac {b^2 \int \sqrt {i \sinh (c+d x)} \, dx}{\sqrt {b \text {csch}(c+d x)} \sqrt {i \sinh (c+d x)}} \\ & = -\frac {2 b \cosh (c+d x) \sqrt {b \text {csch}(c+d x)}}{d}-\frac {2 i b^2 E\left (\left .\frac {1}{2} \left (i c-\frac {\pi }{2}+i d x\right )\right |2\right )}{d \sqrt {b \text {csch}(c+d x)} \sqrt {i \sinh (c+d x)}} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.71 \[ \int (b \text {csch}(c+d x))^{3/2} \, dx=-\frac {2 b \sqrt {b \text {csch}(c+d x)} \left (\cosh (c+d x)-E\left (\left .\frac {1}{4} (-2 i c+\pi -2 i d x)\right |2\right ) \sqrt {i \sinh (c+d x)}\right )}{d} \]
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\[\int \left (b \,\operatorname {csch}\left (d x +c \right )\right )^{\frac {3}{2}}d x\]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.08 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.27 \[ \int (b \text {csch}(c+d x))^{3/2} \, dx=-\frac {2 \, {\left (\sqrt {2} b^{\frac {3}{2}} {\rm weierstrassZeta}\left (4, 0, {\rm weierstrassPInverse}\left (4, 0, \cosh \left (d x + c\right ) + \sinh \left (d x + c\right )\right )\right ) + \sqrt {2} {\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt {\frac {b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )}{\cosh \left (d x + c\right )^{2} + 2 \, \cosh \left (d x + c\right ) \sinh \left (d x + c\right ) + \sinh \left (d x + c\right )^{2} - 1}}\right )}}{d} \]
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\[ \int (b \text {csch}(c+d x))^{3/2} \, dx=\int \left (b \operatorname {csch}{\left (c + d x \right )}\right )^{\frac {3}{2}}\, dx \]
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\[ \int (b \text {csch}(c+d x))^{3/2} \, dx=\int { \left (b \operatorname {csch}\left (d x + c\right )\right )^{\frac {3}{2}} \,d x } \]
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\[ \int (b \text {csch}(c+d x))^{3/2} \, dx=\int { \left (b \operatorname {csch}\left (d x + c\right )\right )^{\frac {3}{2}} \,d x } \]
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Timed out. \[ \int (b \text {csch}(c+d x))^{3/2} \, dx=\int {\left (\frac {b}{\mathrm {sinh}\left (c+d\,x\right )}\right )}^{3/2} \,d x \]
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