\(\int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx\) [529]

Optimal result

Integrand size = 18, antiderivative size = 64 \[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\frac {2 x \cosh ^{\frac {5}{2}}(a+b x)}{5 b}+\frac {12 i E\left (\left .\frac {1}{2} i (a+b x)\right |2\right )}{25 b^2}-\frac {4 \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x)}{25 b^2} \]

[Out]

2/5*x*cosh(b*x+a)^(5/2)/b+12/25*I*(cosh(1/2*a+1/2*b*x)^2)^(1/2)/cosh(1/2*a+1/2*b*x)*EllipticE(I*sinh(1/2*a+1/2
*b*x),2^(1/2))/b^2-4/25*cosh(b*x+a)^(3/2)*sinh(b*x+a)/b^2

Rubi [A] (verified)

Time = 0.03 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {5481, 2715, 2719} \[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\frac {12 i E\left (\left .\frac {1}{2} i (a+b x)\right |2\right )}{25 b^2}-\frac {4 \sinh (a+b x) \cosh ^{\frac {3}{2}}(a+b x)}{25 b^2}+\frac {2 x \cosh ^{\frac {5}{2}}(a+b x)}{5 b} \]

[In]

Int[x*Cosh[a + b*x]^(3/2)*Sinh[a + b*x],x]

[Out]

(2*x*Cosh[a + b*x]^(5/2))/(5*b) + (((12*I)/25)*EllipticE[(I/2)*(a + b*x), 2])/b^2 - (4*Cosh[a + b*x]^(3/2)*Sin
h[a + b*x])/(25*b^2)

Rule 2715

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos[c + d*x]*((b*Sin[c + d*x])^(n - 1)/(d*n))
, x] + Dist[b^2*((n - 1)/n), Int[(b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && Integ
erQ[2*n]

Rule 2719

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2], x] /; FreeQ[{
c, d}, x]

Rule 5481

Int[Cosh[(a_.) + (b_.)*(x_)^(n_.)]^(p_.)*(x_)^(m_.)*Sinh[(a_.) + (b_.)*(x_)^(n_.)], x_Symbol] :> Simp[x^(m - n
+ 1)*(Cosh[a + b*x^n]^(p + 1)/(b*n*(p + 1))), x] - Dist[(m - n + 1)/(b*n*(p + 1)), Int[x^(m - n)*Cosh[a + b*x
^n]^(p + 1), x], x] /; FreeQ[{a, b, p}, x] && LtQ[0, n, m + 1] && NeQ[p, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {2 x \cosh ^{\frac {5}{2}}(a+b x)}{5 b}-\frac {2 \int \cosh ^{\frac {5}{2}}(a+b x) \, dx}{5 b} \\ & = \frac {2 x \cosh ^{\frac {5}{2}}(a+b x)}{5 b}-\frac {4 \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x)}{25 b^2}-\frac {6 \int \sqrt {\cosh (a+b x)} \, dx}{25 b} \\ & = \frac {2 x \cosh ^{\frac {5}{2}}(a+b x)}{5 b}+\frac {12 i E\left (\left .\frac {1}{2} i (a+b x)\right |2\right )}{25 b^2}-\frac {4 \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x)}{25 b^2} \\ \end{align*}

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 2.33 (sec) , antiderivative size = 142, normalized size of antiderivative = 2.22 \[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\frac {e^{-3 (a+b x)} \left (\left (1+e^{2 (a+b x)}\right ) \left (2+5 b x+2 e^{2 (a+b x)} (-12+5 b x)+e^{4 (a+b x)} (-2+5 b x)\right )+48 e^{2 (a+b x)} \sqrt {1+e^{2 (a+b x)}} \operatorname {Hypergeometric2F1}\left (-\frac {1}{4},\frac {1}{2},\frac {3}{4},-e^{2 (a+b x)}\right )\right )}{50 \sqrt {2} b^2 \sqrt {e^{-a-b x}+e^{a+b x}}} \]

[In]

Integrate[x*Cosh[a + b*x]^(3/2)*Sinh[a + b*x],x]

[Out]

((1 + E^(2*(a + b*x)))*(2 + 5*b*x + 2*E^(2*(a + b*x))*(-12 + 5*b*x) + E^(4*(a + b*x))*(-2 + 5*b*x)) + 48*E^(2*
(a + b*x))*Sqrt[1 + E^(2*(a + b*x))]*Hypergeometric2F1[-1/4, 1/2, 3/4, -E^(2*(a + b*x))])/(50*Sqrt[2]*b^2*E^(3
*(a + b*x))*Sqrt[E^(-a - b*x) + E^(a + b*x)])

Maple [F]

\[\int x \cosh \left (b x +a \right )^{\frac {3}{2}} \sinh \left (b x +a \right )d x\]

[In]

int(x*cosh(b*x+a)^(3/2)*sinh(b*x+a),x)

[Out]

int(x*cosh(b*x+a)^(3/2)*sinh(b*x+a),x)

Fricas [F(-2)]

Exception generated. \[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\text {Exception raised: TypeError} \]

[In]

integrate(x*cosh(b*x+a)^(3/2)*sinh(b*x+a),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

Sympy [F(-1)]

Timed out. \[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\text {Timed out} \]

[In]

integrate(x*cosh(b*x+a)**(3/2)*sinh(b*x+a),x)

[Out]

Timed out

Maxima [F]

\[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\int { x \cosh \left (b x + a\right )^{\frac {3}{2}} \sinh \left (b x + a\right ) \,d x } \]

[In]

integrate(x*cosh(b*x+a)^(3/2)*sinh(b*x+a),x, algorithm="maxima")

[Out]

integrate(x*cosh(b*x + a)^(3/2)*sinh(b*x + a), x)

Giac [F]

\[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\int { x \cosh \left (b x + a\right )^{\frac {3}{2}} \sinh \left (b x + a\right ) \,d x } \]

[In]

integrate(x*cosh(b*x+a)^(3/2)*sinh(b*x+a),x, algorithm="giac")

[Out]

integrate(x*cosh(b*x + a)^(3/2)*sinh(b*x + a), x)

Mupad [F(-1)]

Timed out. \[ \int x \cosh ^{\frac {3}{2}}(a+b x) \sinh (a+b x) \, dx=\int x\,{\mathrm {cosh}\left (a+b\,x\right )}^{3/2}\,\mathrm {sinh}\left (a+b\,x\right ) \,d x \]

[In]

int(x*cosh(a + b*x)^(3/2)*sinh(a + b*x),x)

[Out]

int(x*cosh(a + b*x)^(3/2)*sinh(a + b*x), x)