Integrand size = 18, antiderivative size = 98 \[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=-\frac {2 x}{3 b \sinh ^{\frac {3}{2}}(a+b x)}-\frac {4 \cosh (a+b x)}{3 b^2 \sqrt {\sinh (a+b x)}}-\frac {4 i E\left (\left .\frac {1}{2} \left (i a-\frac {\pi }{2}+i b x\right )\right |2\right ) \sqrt {\sinh (a+b x)}}{3 b^2 \sqrt {i \sinh (a+b x)}} \]
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Time = 0.04 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {5480, 2716, 2721, 2719} \[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=-\frac {4 \cosh (a+b x)}{3 b^2 \sqrt {\sinh (a+b x)}}-\frac {4 i \sqrt {\sinh (a+b x)} E\left (\left .\frac {1}{2} \left (i a+i b x-\frac {\pi }{2}\right )\right |2\right )}{3 b^2 \sqrt {i \sinh (a+b x)}}-\frac {2 x}{3 b \sinh ^{\frac {3}{2}}(a+b x)} \]
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Rule 2716
Rule 2719
Rule 2721
Rule 5480
Rubi steps \begin{align*} \text {integral}& = -\frac {2 x}{3 b \sinh ^{\frac {3}{2}}(a+b x)}+\frac {2 \int \frac {1}{\sinh ^{\frac {3}{2}}(a+b x)} \, dx}{3 b} \\ & = -\frac {2 x}{3 b \sinh ^{\frac {3}{2}}(a+b x)}-\frac {4 \cosh (a+b x)}{3 b^2 \sqrt {\sinh (a+b x)}}+\frac {2 \int \sqrt {\sinh (a+b x)} \, dx}{3 b} \\ & = -\frac {2 x}{3 b \sinh ^{\frac {3}{2}}(a+b x)}-\frac {4 \cosh (a+b x)}{3 b^2 \sqrt {\sinh (a+b x)}}+\frac {\left (2 \sqrt {\sinh (a+b x)}\right ) \int \sqrt {i \sinh (a+b x)} \, dx}{3 b \sqrt {i \sinh (a+b x)}} \\ & = -\frac {2 x}{3 b \sinh ^{\frac {3}{2}}(a+b x)}-\frac {4 \cosh (a+b x)}{3 b^2 \sqrt {\sinh (a+b x)}}-\frac {4 i E\left (\left .\frac {1}{2} \left (i a-\frac {\pi }{2}+i b x\right )\right |2\right ) \sqrt {\sinh (a+b x)}}{3 b^2 \sqrt {i \sinh (a+b x)}} \\ \end{align*}
Time = 0.30 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.67 \[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=-\frac {2 \left (b x+2 i E\left (\left .\frac {1}{4} (-2 i a+\pi -2 i b x)\right |2\right ) (i \sinh (a+b x))^{3/2}+\sinh (2 (a+b x))\right )}{3 b^2 \sinh ^{\frac {3}{2}}(a+b x)} \]
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\[\int \frac {x \cosh \left (b x +a \right )}{\sinh \left (b x +a \right )^{\frac {5}{2}}}d x\]
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Exception generated. \[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=\text {Exception raised: TypeError} \]
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\[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=\int \frac {x \cosh {\left (a + b x \right )}}{\sinh ^{\frac {5}{2}}{\left (a + b x \right )}}\, dx \]
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\[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=\int { \frac {x \cosh \left (b x + a\right )}{\sinh \left (b x + a\right )^{\frac {5}{2}}} \,d x } \]
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\[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=\int { \frac {x \cosh \left (b x + a\right )}{\sinh \left (b x + a\right )^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {x \cosh (a+b x)}{\sinh ^{\frac {5}{2}}(a+b x)} \, dx=\int \frac {x\,\mathrm {cosh}\left (a+b\,x\right )}{{\mathrm {sinh}\left (a+b\,x\right )}^{5/2}} \,d x \]
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