Integrand size = 12, antiderivative size = 12 \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\text {Int}\left (\frac {1}{x \text {arcsinh}(a+b x)},x\right ) \]
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Not integrable
Time = 0.04 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\int \frac {1}{x \text {arcsinh}(a+b x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{\left (-\frac {a}{b}+\frac {x}{b}\right ) \text {arcsinh}(x)} \, dx,x,a+b x\right )}{b} \\ \end{align*}
Not integrable
Time = 0.23 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\int \frac {1}{x \text {arcsinh}(a+b x)} \, dx \]
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Not integrable
Time = 0.98 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00
\[\int \frac {1}{x \,\operatorname {arcsinh}\left (b x +a \right )}d x\]
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Not integrable
Time = 0.24 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\int { \frac {1}{x \operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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Not integrable
Time = 0.32 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.83 \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\int \frac {1}{x \operatorname {asinh}{\left (a + b x \right )}}\, dx \]
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Not integrable
Time = 0.25 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\int { \frac {1}{x \operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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Not integrable
Time = 0.34 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\int { \frac {1}{x \operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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Not integrable
Time = 2.73 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {1}{x \text {arcsinh}(a+b x)} \, dx=\int \frac {1}{x\,\mathrm {asinh}\left (a+b\,x\right )} \,d x \]
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