Integrand size = 23, antiderivative size = 169 \[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=-\frac {b^2}{3 d e^4 (c+d x)}-\frac {b \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))}{3 d e^4 (c+d x)^2}-\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}+\frac {2 b (a+b \text {arcsinh}(c+d x)) \text {arctanh}\left (e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}+\frac {b^2 \operatorname {PolyLog}\left (2,-e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}-\frac {b^2 \operatorname {PolyLog}\left (2,e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4} \]
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Time = 0.17 (sec) , antiderivative size = 169, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.391, Rules used = {5859, 12, 5776, 5809, 5816, 4267, 2317, 2438, 30} \[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=\frac {2 b \text {arctanh}\left (e^{\text {arcsinh}(c+d x)}\right ) (a+b \text {arcsinh}(c+d x))}{3 d e^4}-\frac {b \sqrt {(c+d x)^2+1} (a+b \text {arcsinh}(c+d x))}{3 d e^4 (c+d x)^2}-\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}+\frac {b^2 \operatorname {PolyLog}\left (2,-e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}-\frac {b^2 \operatorname {PolyLog}\left (2,e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}-\frac {b^2}{3 d e^4 (c+d x)} \]
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Rule 12
Rule 30
Rule 2317
Rule 2438
Rule 4267
Rule 5776
Rule 5809
Rule 5816
Rule 5859
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {(a+b \text {arcsinh}(x))^2}{e^4 x^4} \, dx,x,c+d x\right )}{d} \\ & = \frac {\text {Subst}\left (\int \frac {(a+b \text {arcsinh}(x))^2}{x^4} \, dx,x,c+d x\right )}{d e^4} \\ & = -\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}+\frac {(2 b) \text {Subst}\left (\int \frac {a+b \text {arcsinh}(x)}{x^3 \sqrt {1+x^2}} \, dx,x,c+d x\right )}{3 d e^4} \\ & = -\frac {b \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))}{3 d e^4 (c+d x)^2}-\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}-\frac {b \text {Subst}\left (\int \frac {a+b \text {arcsinh}(x)}{x \sqrt {1+x^2}} \, dx,x,c+d x\right )}{3 d e^4}+\frac {b^2 \text {Subst}\left (\int \frac {1}{x^2} \, dx,x,c+d x\right )}{3 d e^4} \\ & = -\frac {b^2}{3 d e^4 (c+d x)}-\frac {b \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))}{3 d e^4 (c+d x)^2}-\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}-\frac {b \text {Subst}(\int (a+b x) \text {csch}(x) \, dx,x,\text {arcsinh}(c+d x))}{3 d e^4} \\ & = -\frac {b^2}{3 d e^4 (c+d x)}-\frac {b \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))}{3 d e^4 (c+d x)^2}-\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}+\frac {2 b (a+b \text {arcsinh}(c+d x)) \text {arctanh}\left (e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}+\frac {b^2 \text {Subst}\left (\int \log \left (1-e^x\right ) \, dx,x,\text {arcsinh}(c+d x)\right )}{3 d e^4}-\frac {b^2 \text {Subst}\left (\int \log \left (1+e^x\right ) \, dx,x,\text {arcsinh}(c+d x)\right )}{3 d e^4} \\ & = -\frac {b^2}{3 d e^4 (c+d x)}-\frac {b \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))}{3 d e^4 (c+d x)^2}-\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}+\frac {2 b (a+b \text {arcsinh}(c+d x)) \text {arctanh}\left (e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}+\frac {b^2 \text {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}-\frac {b^2 \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4} \\ & = -\frac {b^2}{3 d e^4 (c+d x)}-\frac {b \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))}{3 d e^4 (c+d x)^2}-\frac {(a+b \text {arcsinh}(c+d x))^2}{3 d e^4 (c+d x)^3}+\frac {2 b (a+b \text {arcsinh}(c+d x)) \text {arctanh}\left (e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}+\frac {b^2 \operatorname {PolyLog}\left (2,-e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4}-\frac {b^2 \operatorname {PolyLog}\left (2,e^{\text {arcsinh}(c+d x)}\right )}{3 d e^4} \\ \end{align*}
Time = 1.31 (sec) , antiderivative size = 229, normalized size of antiderivative = 1.36 \[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=-\frac {4 a^2+a b \left (8 \text {arcsinh}(c+d x)+2 \sinh (2 \text {arcsinh}(c+d x))+\left (\log \left (\cosh \left (\frac {1}{2} \text {arcsinh}(c+d x)\right )\right )-\log \left (\sinh \left (\frac {1}{2} \text {arcsinh}(c+d x)\right )\right )\right ) (3 c+3 d x-\sinh (3 \text {arcsinh}(c+d x)))\right )+b^2 \left (4 (c+d x)^2+4 \text {arcsinh}(c+d x)^2+4 (c+d x)^3 \operatorname {PolyLog}\left (2,-e^{-\text {arcsinh}(c+d x)}\right )-4 (c+d x)^3 \operatorname {PolyLog}\left (2,e^{-\text {arcsinh}(c+d x)}\right )+\text {arcsinh}(c+d x) \left (2 \sinh (2 \text {arcsinh}(c+d x))+\left (\log \left (1-e^{-\text {arcsinh}(c+d x)}\right )-\log \left (1+e^{-\text {arcsinh}(c+d x)}\right )\right ) (-3 (c+d x)+\sinh (3 \text {arcsinh}(c+d x)))\right )\right )}{12 d e^4 (c+d x)^3} \]
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Time = 0.53 (sec) , antiderivative size = 236, normalized size of antiderivative = 1.40
method | result | size |
derivativedivides | \(\frac {-\frac {a^{2}}{3 e^{4} \left (d x +c \right )^{3}}+\frac {b^{2} \left (-\frac {\sqrt {1+\left (d x +c \right )^{2}}\, \left (d x +c \right ) \operatorname {arcsinh}\left (d x +c \right )+\operatorname {arcsinh}\left (d x +c \right )^{2}+\left (d x +c \right )^{2}}{3 \left (d x +c \right )^{3}}+\frac {\operatorname {arcsinh}\left (d x +c \right ) \ln \left (1+d x +c +\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}+\frac {\operatorname {polylog}\left (2, -d x -c -\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}-\frac {\operatorname {arcsinh}\left (d x +c \right ) \ln \left (1-d x -c -\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}-\frac {\operatorname {polylog}\left (2, d x +c +\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}\right )}{e^{4}}+\frac {2 a b \left (-\frac {\operatorname {arcsinh}\left (d x +c \right )}{3 \left (d x +c \right )^{3}}-\frac {\sqrt {1+\left (d x +c \right )^{2}}}{6 \left (d x +c \right )^{2}}+\frac {\operatorname {arctanh}\left (\frac {1}{\sqrt {1+\left (d x +c \right )^{2}}}\right )}{6}\right )}{e^{4}}}{d}\) | \(236\) |
default | \(\frac {-\frac {a^{2}}{3 e^{4} \left (d x +c \right )^{3}}+\frac {b^{2} \left (-\frac {\sqrt {1+\left (d x +c \right )^{2}}\, \left (d x +c \right ) \operatorname {arcsinh}\left (d x +c \right )+\operatorname {arcsinh}\left (d x +c \right )^{2}+\left (d x +c \right )^{2}}{3 \left (d x +c \right )^{3}}+\frac {\operatorname {arcsinh}\left (d x +c \right ) \ln \left (1+d x +c +\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}+\frac {\operatorname {polylog}\left (2, -d x -c -\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}-\frac {\operatorname {arcsinh}\left (d x +c \right ) \ln \left (1-d x -c -\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}-\frac {\operatorname {polylog}\left (2, d x +c +\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}\right )}{e^{4}}+\frac {2 a b \left (-\frac {\operatorname {arcsinh}\left (d x +c \right )}{3 \left (d x +c \right )^{3}}-\frac {\sqrt {1+\left (d x +c \right )^{2}}}{6 \left (d x +c \right )^{2}}+\frac {\operatorname {arctanh}\left (\frac {1}{\sqrt {1+\left (d x +c \right )^{2}}}\right )}{6}\right )}{e^{4}}}{d}\) | \(236\) |
parts | \(-\frac {a^{2}}{3 e^{4} \left (d x +c \right )^{3} d}+\frac {b^{2} \left (-\frac {\sqrt {1+\left (d x +c \right )^{2}}\, \left (d x +c \right ) \operatorname {arcsinh}\left (d x +c \right )+\operatorname {arcsinh}\left (d x +c \right )^{2}+\left (d x +c \right )^{2}}{3 \left (d x +c \right )^{3}}+\frac {\operatorname {arcsinh}\left (d x +c \right ) \ln \left (1+d x +c +\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}+\frac {\operatorname {polylog}\left (2, -d x -c -\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}-\frac {\operatorname {arcsinh}\left (d x +c \right ) \ln \left (1-d x -c -\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}-\frac {\operatorname {polylog}\left (2, d x +c +\sqrt {1+\left (d x +c \right )^{2}}\right )}{3}\right )}{e^{4} d}+\frac {2 a b \left (-\frac {\operatorname {arcsinh}\left (d x +c \right )}{3 \left (d x +c \right )^{3}}-\frac {\sqrt {1+\left (d x +c \right )^{2}}}{6 \left (d x +c \right )^{2}}+\frac {\operatorname {arctanh}\left (\frac {1}{\sqrt {1+\left (d x +c \right )^{2}}}\right )}{6}\right )}{e^{4} d}\) | \(241\) |
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\[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{2}}{{\left (d e x + c e\right )}^{4}} \,d x } \]
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\[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=\frac {\int \frac {a^{2}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac {b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac {2 a b \operatorname {asinh}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx}{e^{4}} \]
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\[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{2}}{{\left (d e x + c e\right )}^{4}} \,d x } \]
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\[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=\int { \frac {{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{2}}{{\left (d e x + c e\right )}^{4}} \,d x } \]
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Timed out. \[ \int \frac {(a+b \text {arcsinh}(c+d x))^2}{(c e+d e x)^4} \, dx=\int \frac {{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^2}{{\left (c\,e+d\,e\,x\right )}^4} \,d x \]
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