Integrand size = 23, antiderivative size = 410 \[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=-\frac {e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {25 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{6 b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {e^4 \text {Chi}\left (\frac {a+b \text {arcsinh}(c+d x)}{b}\right ) \sinh \left (\frac {a}{b}\right )}{48 b^4 d}+\frac {27 e^4 \text {Chi}\left (\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right ) \sinh \left (\frac {3 a}{b}\right )}{32 b^4 d}-\frac {125 e^4 \text {Chi}\left (\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right ) \sinh \left (\frac {5 a}{b}\right )}{96 b^4 d}+\frac {e^4 \cosh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a+b \text {arcsinh}(c+d x)}{b}\right )}{48 b^4 d}-\frac {27 e^4 \cosh \left (\frac {3 a}{b}\right ) \text {Shi}\left (\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right )}{32 b^4 d}+\frac {125 e^4 \cosh \left (\frac {5 a}{b}\right ) \text {Shi}\left (\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right )}{96 b^4 d} \]
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Time = 0.57 (sec) , antiderivative size = 410, normalized size of antiderivative = 1.00, number of steps used = 24, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {5859, 12, 5779, 5818, 5778, 3384, 3379, 3382} \[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=-\frac {e^4 \sinh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a+b \text {arcsinh}(c+d x)}{b}\right )}{48 b^4 d}+\frac {27 e^4 \sinh \left (\frac {3 a}{b}\right ) \text {Chi}\left (\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right )}{32 b^4 d}-\frac {125 e^4 \sinh \left (\frac {5 a}{b}\right ) \text {Chi}\left (\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right )}{96 b^4 d}+\frac {e^4 \cosh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a+b \text {arcsinh}(c+d x)}{b}\right )}{48 b^4 d}-\frac {27 e^4 \cosh \left (\frac {3 a}{b}\right ) \text {Shi}\left (\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right )}{32 b^4 d}+\frac {125 e^4 \cosh \left (\frac {5 a}{b}\right ) \text {Shi}\left (\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right )}{96 b^4 d}-\frac {25 e^4 \sqrt {(c+d x)^2+1} (c+d x)^4}{6 b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {2 e^4 \sqrt {(c+d x)^2+1} (c+d x)^2}{b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {e^4 \sqrt {(c+d x)^2+1} (c+d x)^4}{3 b d (a+b \text {arcsinh}(c+d x))^3} \]
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Rule 12
Rule 3379
Rule 3382
Rule 3384
Rule 5778
Rule 5779
Rule 5818
Rule 5859
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {e^4 x^4}{(a+b \text {arcsinh}(x))^4} \, dx,x,c+d x\right )}{d} \\ & = \frac {e^4 \text {Subst}\left (\int \frac {x^4}{(a+b \text {arcsinh}(x))^4} \, dx,x,c+d x\right )}{d} \\ & = -\frac {e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^3}+\frac {\left (4 e^4\right ) \text {Subst}\left (\int \frac {x^3}{\sqrt {1+x^2} (a+b \text {arcsinh}(x))^3} \, dx,x,c+d x\right )}{3 b d}+\frac {\left (5 e^4\right ) \text {Subst}\left (\int \frac {x^5}{\sqrt {1+x^2} (a+b \text {arcsinh}(x))^3} \, dx,x,c+d x\right )}{3 b d} \\ & = -\frac {e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {arcsinh}(c+d x))^2}+\frac {\left (2 e^4\right ) \text {Subst}\left (\int \frac {x^2}{(a+b \text {arcsinh}(x))^2} \, dx,x,c+d x\right )}{b^2 d}+\frac {\left (25 e^4\right ) \text {Subst}\left (\int \frac {x^4}{(a+b \text {arcsinh}(x))^2} \, dx,x,c+d x\right )}{6 b^2 d} \\ & = -\frac {e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {25 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{6 b^3 d (a+b \text {arcsinh}(c+d x))}+\frac {\left (2 e^4\right ) \text {Subst}\left (\int \left (-\frac {3 \sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{4 x}+\frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{4 x}\right ) \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{b^4 d}+\frac {\left (25 e^4\right ) \text {Subst}\left (\int \left (-\frac {5 \sinh \left (\frac {5 a}{b}-\frac {5 x}{b}\right )}{16 x}+\frac {9 \sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{16 x}-\frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{8 x}\right ) \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{6 b^4 d} \\ & = -\frac {e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {25 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{6 b^3 d (a+b \text {arcsinh}(c+d x))}+\frac {e^4 \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{2 b^4 d}-\frac {\left (25 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{48 b^4 d}-\frac {\left (125 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {5 a}{b}-\frac {5 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{96 b^4 d}-\frac {\left (3 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{2 b^4 d}+\frac {\left (75 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{32 b^4 d} \\ & = -\frac {e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {25 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{6 b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {\left (e^4 \cosh \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{2 b^4 d}+\frac {\left (25 e^4 \cosh \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{48 b^4 d}+\frac {\left (3 e^4 \cosh \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {3 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{2 b^4 d}-\frac {\left (75 e^4 \cosh \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {3 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{32 b^4 d}+\frac {\left (125 e^4 \cosh \left (\frac {5 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {5 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{96 b^4 d}+\frac {\left (e^4 \sinh \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cosh \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{2 b^4 d}-\frac {\left (25 e^4 \sinh \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cosh \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{48 b^4 d}-\frac {\left (3 e^4 \sinh \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cosh \left (\frac {3 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{2 b^4 d}+\frac {\left (75 e^4 \sinh \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cosh \left (\frac {3 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{32 b^4 d}-\frac {\left (125 e^4 \sinh \left (\frac {5 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cosh \left (\frac {5 x}{b}\right )}{x} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{96 b^4 d} \\ & = -\frac {e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {arcsinh}(c+d x))^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {25 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{6 b^3 d (a+b \text {arcsinh}(c+d x))}-\frac {e^4 \text {Chi}\left (\frac {a+b \text {arcsinh}(c+d x)}{b}\right ) \sinh \left (\frac {a}{b}\right )}{48 b^4 d}+\frac {27 e^4 \text {Chi}\left (\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right ) \sinh \left (\frac {3 a}{b}\right )}{32 b^4 d}-\frac {125 e^4 \text {Chi}\left (\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right ) \sinh \left (\frac {5 a}{b}\right )}{96 b^4 d}+\frac {e^4 \cosh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a+b \text {arcsinh}(c+d x)}{b}\right )}{48 b^4 d}-\frac {27 e^4 \cosh \left (\frac {3 a}{b}\right ) \text {Shi}\left (\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right )}{32 b^4 d}+\frac {125 e^4 \cosh \left (\frac {5 a}{b}\right ) \text {Shi}\left (\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right )}{96 b^4 d} \\ \end{align*}
Time = 1.83 (sec) , antiderivative size = 410, normalized size of antiderivative = 1.00 \[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=-\frac {e^4 \left (\frac {32 b^3 (c+d x)^4 \sqrt {1+(c+d x)^2}}{(a+b \text {arcsinh}(c+d x))^3}-\frac {16 b^2 \left (-4 (c+d x)^3-5 (c+d x)^5\right )}{(a+b \text {arcsinh}(c+d x))^2}+\frac {16 b \sqrt {1+(c+d x)^2} \left (12 (c+d x)^2+25 (c+d x)^4\right )}{a+b \text {arcsinh}(c+d x)}+384 \left (\text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c+d x)\right ) \sinh \left (\frac {a}{b}\right )-\cosh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )\right )+544 \left (-3 \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c+d x)\right ) \sinh \left (\frac {a}{b}\right )+\text {Chi}\left (3 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )\right ) \sinh \left (\frac {3 a}{b}\right )+3 \cosh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )-\cosh \left (\frac {3 a}{b}\right ) \text {Shi}\left (3 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )\right )\right )+125 \left (10 \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c+d x)\right ) \sinh \left (\frac {a}{b}\right )-5 \text {Chi}\left (3 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )\right ) \sinh \left (\frac {3 a}{b}\right )+\text {Chi}\left (5 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )\right ) \sinh \left (\frac {5 a}{b}\right )-10 \cosh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )+5 \cosh \left (\frac {3 a}{b}\right ) \text {Shi}\left (3 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )\right )-\cosh \left (\frac {5 a}{b}\right ) \text {Shi}\left (5 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )\right )\right )\right )}{96 b^4 d} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(1243\) vs. \(2(384)=768\).
Time = 0.90 (sec) , antiderivative size = 1244, normalized size of antiderivative = 3.03
method | result | size |
derivativedivides | \(\text {Expression too large to display}\) | \(1244\) |
default | \(\text {Expression too large to display}\) | \(1244\) |
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\[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=\int { \frac {{\left (d e x + c e\right )}^{4}}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{4}} \,d x } \]
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\[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=e^{4} \left (\int \frac {c^{4}}{a^{4} + 4 a^{3} b \operatorname {asinh}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asinh}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asinh}^{4}{\left (c + d x \right )}}\, dx + \int \frac {d^{4} x^{4}}{a^{4} + 4 a^{3} b \operatorname {asinh}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asinh}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asinh}^{4}{\left (c + d x \right )}}\, dx + \int \frac {4 c d^{3} x^{3}}{a^{4} + 4 a^{3} b \operatorname {asinh}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asinh}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asinh}^{4}{\left (c + d x \right )}}\, dx + \int \frac {6 c^{2} d^{2} x^{2}}{a^{4} + 4 a^{3} b \operatorname {asinh}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asinh}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asinh}^{4}{\left (c + d x \right )}}\, dx + \int \frac {4 c^{3} d x}{a^{4} + 4 a^{3} b \operatorname {asinh}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asinh}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asinh}^{4}{\left (c + d x \right )}}\, dx\right ) \]
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Timed out. \[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=\text {Timed out} \]
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\[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=\int { \frac {{\left (d e x + c e\right )}^{4}}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{4}} \,d x } \]
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Timed out. \[ \int \frac {(c e+d e x)^4}{(a+b \text {arcsinh}(c+d x))^4} \, dx=\int \frac {{\left (c\,e+d\,e\,x\right )}^4}{{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^4} \,d x \]
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