Integrand size = 23, antiderivative size = 164 \[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=\frac {e \sqrt {a+b \text {arcsinh}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}-\frac {\sqrt {b} e e^{\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{16 d}-\frac {\sqrt {b} e e^{-\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{16 d} \]
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Time = 0.28 (sec) , antiderivative size = 164, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.391, Rules used = {5859, 12, 5777, 5819, 3393, 3388, 2211, 2236, 2235} \[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=-\frac {\sqrt {\frac {\pi }{2}} \sqrt {b} e e^{\frac {2 a}{b}} \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{16 d}-\frac {\sqrt {\frac {\pi }{2}} \sqrt {b} e e^{-\frac {2 a}{b}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{16 d}+\frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}+\frac {e \sqrt {a+b \text {arcsinh}(c+d x)}}{4 d} \]
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Rule 12
Rule 2211
Rule 2235
Rule 2236
Rule 3388
Rule 3393
Rule 5777
Rule 5819
Rule 5859
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int e x \sqrt {a+b \text {arcsinh}(x)} \, dx,x,c+d x\right )}{d} \\ & = \frac {e \text {Subst}\left (\int x \sqrt {a+b \text {arcsinh}(x)} \, dx,x,c+d x\right )}{d} \\ & = \frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}-\frac {(b e) \text {Subst}\left (\int \frac {x^2}{\sqrt {1+x^2} \sqrt {a+b \text {arcsinh}(x)}} \, dx,x,c+d x\right )}{4 d} \\ & = \frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}-\frac {e \text {Subst}\left (\int \frac {\sinh ^2\left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{4 d} \\ & = \frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}+\frac {e \text {Subst}\left (\int \left (\frac {1}{2 \sqrt {x}}-\frac {\cosh \left (\frac {2 a}{b}-\frac {2 x}{b}\right )}{2 \sqrt {x}}\right ) \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{4 d} \\ & = \frac {e \sqrt {a+b \text {arcsinh}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}-\frac {e \text {Subst}\left (\int \frac {\cosh \left (\frac {2 a}{b}-\frac {2 x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{8 d} \\ & = \frac {e \sqrt {a+b \text {arcsinh}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}-\frac {e \text {Subst}\left (\int \frac {e^{-i \left (\frac {2 i a}{b}-\frac {2 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{16 d}-\frac {e \text {Subst}\left (\int \frac {e^{i \left (\frac {2 i a}{b}-\frac {2 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{16 d} \\ & = \frac {e \sqrt {a+b \text {arcsinh}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}-\frac {e \text {Subst}\left (\int e^{\frac {2 a}{b}-\frac {2 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{8 d}-\frac {e \text {Subst}\left (\int e^{-\frac {2 a}{b}+\frac {2 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{8 d} \\ & = \frac {e \sqrt {a+b \text {arcsinh}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \text {arcsinh}(c+d x)}}{2 d}-\frac {\sqrt {b} e e^{\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{16 d}-\frac {\sqrt {b} e e^{-\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{16 d} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 122, normalized size of antiderivative = 0.74 \[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=\frac {e e^{-\frac {2 a}{b}} \left (-b \sqrt {-\frac {a+b \text {arcsinh}(c+d x)}{b}} \Gamma \left (\frac {3}{2},-\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )+b e^{\frac {4 a}{b}} \sqrt {\frac {a}{b}+\text {arcsinh}(c+d x)} \Gamma \left (\frac {3}{2},\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )\right )}{8 \sqrt {2} d \sqrt {a+b \text {arcsinh}(c+d x)}} \]
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\[\int \left (d e x +c e \right ) \sqrt {a +b \,\operatorname {arcsinh}\left (d x +c \right )}d x\]
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Exception generated. \[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=\text {Exception raised: TypeError} \]
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\[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=e \left (\int c \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}}\, dx + \int d x \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}}\, dx\right ) \]
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\[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=\int { {\left (d e x + c e\right )} \sqrt {b \operatorname {arsinh}\left (d x + c\right ) + a} \,d x } \]
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\[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=\int { {\left (d e x + c e\right )} \sqrt {b \operatorname {arsinh}\left (d x + c\right ) + a} \,d x } \]
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Timed out. \[ \int (c e+d e x) \sqrt {a+b \text {arcsinh}(c+d x)} \, dx=\int \left (c\,e+d\,e\,x\right )\,\sqrt {a+b\,\mathrm {asinh}\left (c+d\,x\right )} \,d x \]
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