\(\int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx\) [192]

Optimal result

Integrand size = 25, antiderivative size = 701 \[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=\frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}+\frac {15 b^{5/2} e^4 e^{a/b} \sqrt {\pi } \text {erf}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{128 d}-\frac {b^{5/2} e^4 e^{\frac {3 a}{b}} \sqrt {\frac {\pi }{3}} \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{240 d}-\frac {b^{5/2} e^4 e^{\frac {3 a}{b}} \sqrt {3 \pi } \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}+\frac {3 b^{5/2} e^4 e^{\frac {5 a}{b}} \sqrt {\frac {\pi }{5}} \text {erf}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d}-\frac {15 b^{5/2} e^4 e^{-\frac {a}{b}} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{128 d}+\frac {b^{5/2} e^4 e^{-\frac {3 a}{b}} \sqrt {\frac {\pi }{3}} \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{240 d}+\frac {b^{5/2} e^4 e^{-\frac {3 a}{b}} \sqrt {3 \pi } \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}-\frac {3 b^{5/2} e^4 e^{-\frac {5 a}{b}} \sqrt {\frac {\pi }{5}} \text {erfi}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d} \]

[Out]

1/5*e^4*(d*x+c)^5*(a+b*arcsinh(d*x+c))^(5/2)/d+3/32000*b^(5/2)*e^4*exp(5*a/b)*erf(5^(1/2)*(a+b*arcsinh(d*x+c))
^(1/2)/b^(1/2))*5^(1/2)*Pi^(1/2)/d-3/32000*b^(5/2)*e^4*erfi(5^(1/2)*(a+b*arcsinh(d*x+c))^(1/2)/b^(1/2))*5^(1/2
)*Pi^(1/2)/d/exp(5*a/b)-5/2304*b^(5/2)*e^4*exp(3*a/b)*erf(3^(1/2)*(a+b*arcsinh(d*x+c))^(1/2)/b^(1/2))*3^(1/2)*
Pi^(1/2)/d+5/2304*b^(5/2)*e^4*erfi(3^(1/2)*(a+b*arcsinh(d*x+c))^(1/2)/b^(1/2))*3^(1/2)*Pi^(1/2)/d/exp(3*a/b)+1
5/128*b^(5/2)*e^4*exp(a/b)*erf((a+b*arcsinh(d*x+c))^(1/2)/b^(1/2))*Pi^(1/2)/d-15/128*b^(5/2)*e^4*erfi((a+b*arc
sinh(d*x+c))^(1/2)/b^(1/2))*Pi^(1/2)/d/exp(a/b)-4/15*b*e^4*(a+b*arcsinh(d*x+c))^(3/2)*(1+(d*x+c)^2)^(1/2)/d+2/
15*b*e^4*(d*x+c)^2*(a+b*arcsinh(d*x+c))^(3/2)*(1+(d*x+c)^2)^(1/2)/d-1/10*b*e^4*(d*x+c)^4*(a+b*arcsinh(d*x+c))^
(3/2)*(1+(d*x+c)^2)^(1/2)/d+2/5*b^2*e^4*(d*x+c)*(a+b*arcsinh(d*x+c))^(1/2)/d-1/15*b^2*e^4*(d*x+c)^3*(a+b*arcsi
nh(d*x+c))^(1/2)/d+3/100*b^2*e^4*(d*x+c)^5*(a+b*arcsinh(d*x+c))^(1/2)/d

Rubi [A] (verified)

Time = 1.45 (sec) , antiderivative size = 701, normalized size of antiderivative = 1.00, number of steps used = 46, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.480, Rules used = {5859, 12, 5777, 5812, 5798, 5772, 5819, 3389, 2211, 2236, 2235, 3393} \[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=\frac {15 \sqrt {\pi } b^{5/2} e^4 e^{a/b} \text {erf}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{128 d}-\frac {\sqrt {3 \pi } b^{5/2} e^4 e^{\frac {3 a}{b}} \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}-\frac {\sqrt {\frac {\pi }{3}} b^{5/2} e^4 e^{\frac {3 a}{b}} \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{240 d}+\frac {3 \sqrt {\frac {\pi }{5}} b^{5/2} e^4 e^{\frac {5 a}{b}} \text {erf}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d}-\frac {15 \sqrt {\pi } b^{5/2} e^4 e^{-\frac {a}{b}} \text {erfi}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{128 d}+\frac {\sqrt {3 \pi } b^{5/2} e^4 e^{-\frac {3 a}{b}} \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}+\frac {\sqrt {\frac {\pi }{3}} b^{5/2} e^4 e^{-\frac {3 a}{b}} \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{240 d}-\frac {3 \sqrt {\frac {\pi }{5}} b^{5/2} e^4 e^{-\frac {5 a}{b}} \text {erfi}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}-\frac {b e^4 \sqrt {(c+d x)^2+1} (c+d x)^4 (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {2 b e^4 \sqrt {(c+d x)^2+1} (c+d x)^2 (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {4 b e^4 \sqrt {(c+d x)^2+1} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d} \]

[In]

Int[(c*e + d*e*x)^4*(a + b*ArcSinh[c + d*x])^(5/2),x]

[Out]

(2*b^2*e^4*(c + d*x)*Sqrt[a + b*ArcSinh[c + d*x]])/(5*d) - (b^2*e^4*(c + d*x)^3*Sqrt[a + b*ArcSinh[c + d*x]])/
(15*d) + (3*b^2*e^4*(c + d*x)^5*Sqrt[a + b*ArcSinh[c + d*x]])/(100*d) - (4*b*e^4*Sqrt[1 + (c + d*x)^2]*(a + b*
ArcSinh[c + d*x])^(3/2))/(15*d) + (2*b*e^4*(c + d*x)^2*Sqrt[1 + (c + d*x)^2]*(a + b*ArcSinh[c + d*x])^(3/2))/(
15*d) - (b*e^4*(c + d*x)^4*Sqrt[1 + (c + d*x)^2]*(a + b*ArcSinh[c + d*x])^(3/2))/(10*d) + (e^4*(c + d*x)^5*(a
+ b*ArcSinh[c + d*x])^(5/2))/(5*d) + (15*b^(5/2)*e^4*E^(a/b)*Sqrt[Pi]*Erf[Sqrt[a + b*ArcSinh[c + d*x]]/Sqrt[b]
])/(128*d) - (b^(5/2)*e^4*E^((3*a)/b)*Sqrt[Pi/3]*Erf[(Sqrt[3]*Sqrt[a + b*ArcSinh[c + d*x]])/Sqrt[b]])/(240*d)
- (b^(5/2)*e^4*E^((3*a)/b)*Sqrt[3*Pi]*Erf[(Sqrt[3]*Sqrt[a + b*ArcSinh[c + d*x]])/Sqrt[b]])/(1280*d) + (3*b^(5/
2)*e^4*E^((5*a)/b)*Sqrt[Pi/5]*Erf[(Sqrt[5]*Sqrt[a + b*ArcSinh[c + d*x]])/Sqrt[b]])/(6400*d) - (15*b^(5/2)*e^4*
Sqrt[Pi]*Erfi[Sqrt[a + b*ArcSinh[c + d*x]]/Sqrt[b]])/(128*d*E^(a/b)) + (b^(5/2)*e^4*Sqrt[Pi/3]*Erfi[(Sqrt[3]*S
qrt[a + b*ArcSinh[c + d*x]])/Sqrt[b]])/(240*d*E^((3*a)/b)) + (b^(5/2)*e^4*Sqrt[3*Pi]*Erfi[(Sqrt[3]*Sqrt[a + b*
ArcSinh[c + d*x]])/Sqrt[b]])/(1280*d*E^((3*a)/b)) - (3*b^(5/2)*e^4*Sqrt[Pi/5]*Erfi[(Sqrt[5]*Sqrt[a + b*ArcSinh
[c + d*x]])/Sqrt[b]])/(6400*d*E^((5*a)/b))

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2211

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[F^(g*(e - c*(
f/d)) + f*g*(x^2/d)), x], x, Sqrt[c + d*x]], x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !TrueQ[$UseGamma]

Rule 2235

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt[Pi]*(Erfi[(c + d*x)*Rt[b*Log[F], 2
]]/(2*d*Rt[b*Log[F], 2])), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2236

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt[Pi]*(Erf[(c + d*x)*Rt[(-b)*Log[F],
2]]/(2*d*Rt[(-b)*Log[F], 2])), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 3389

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/E^(I*(e + f*x))
, x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d, e, f, m}, x]

Rule 3393

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 5772

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Simp[x*(a + b*ArcSinh[c*x])^n, x] - Dist[b*c*n, In
t[x*((a + b*ArcSinh[c*x])^(n - 1)/Sqrt[1 + c^2*x^2]), x], x] /; FreeQ[{a, b, c}, x] && GtQ[n, 0]

Rule 5777

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)*((a + b*ArcSinh[c*x])^n/(
m + 1)), x] - Dist[b*c*(n/(m + 1)), Int[x^(m + 1)*((a + b*ArcSinh[c*x])^(n - 1)/Sqrt[1 + c^2*x^2]), x], x] /;
FreeQ[{a, b, c}, x] && IGtQ[m, 0] && GtQ[n, 0]

Rule 5798

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(d + e*x^2)^
(p + 1)*((a + b*ArcSinh[c*x])^n/(2*e*(p + 1))), x] - Dist[b*(n/(2*c*(p + 1)))*Simp[(d + e*x^2)^p/(1 + c^2*x^2)
^p], Int[(1 + c^2*x^2)^(p + 1/2)*(a + b*ArcSinh[c*x])^(n - 1), x], x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[e
, c^2*d] && GtQ[n, 0] && NeQ[p, -1]

Rule 5812

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(p_), x_Symbol] :> Simp[
f*(f*x)^(m - 1)*(d + e*x^2)^(p + 1)*((a + b*ArcSinh[c*x])^n/(e*(m + 2*p + 1))), x] + (-Dist[f^2*((m - 1)/(c^2*
(m + 2*p + 1))), Int[(f*x)^(m - 2)*(d + e*x^2)^p*(a + b*ArcSinh[c*x])^n, x], x] - Dist[b*f*(n/(c*(m + 2*p + 1)
))*Simp[(d + e*x^2)^p/(1 + c^2*x^2)^p], Int[(f*x)^(m - 1)*(1 + c^2*x^2)^(p + 1/2)*(a + b*ArcSinh[c*x])^(n - 1)
, x], x]) /; FreeQ[{a, b, c, d, e, f, p}, x] && EqQ[e, c^2*d] && GtQ[n, 0] && IGtQ[m, 1] && NeQ[m + 2*p + 1, 0
]

Rule 5819

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[(1/(b*
c^(m + 1)))*Simp[(d + e*x^2)^p/(1 + c^2*x^2)^p], Subst[Int[x^n*Sinh[-a/b + x/b]^m*Cosh[-a/b + x/b]^(2*p + 1),
x], x, a + b*ArcSinh[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[e, c^2*d] && IGtQ[2*p + 2, 0] && IGtQ[m,
0]

Rule 5859

Int[((a_.) + ArcSinh[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[1/d, Subst[
Int[((d*e - c*f)/d + f*(x/d))^m*(a + b*ArcSinh[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x
]

Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int e^4 x^4 (a+b \text {arcsinh}(x))^{5/2} \, dx,x,c+d x\right )}{d} \\ & = \frac {e^4 \text {Subst}\left (\int x^4 (a+b \text {arcsinh}(x))^{5/2} \, dx,x,c+d x\right )}{d} \\ & = \frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}-\frac {\left (b e^4\right ) \text {Subst}\left (\int \frac {x^5 (a+b \text {arcsinh}(x))^{3/2}}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{2 d} \\ & = -\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}+\frac {\left (2 b e^4\right ) \text {Subst}\left (\int \frac {x^3 (a+b \text {arcsinh}(x))^{3/2}}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{5 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int x^4 \sqrt {a+b \text {arcsinh}(x)} \, dx,x,c+d x\right )}{20 d} \\ & = \frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}-\frac {\left (4 b e^4\right ) \text {Subst}\left (\int \frac {x (a+b \text {arcsinh}(x))^{3/2}}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{15 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int x^2 \sqrt {a+b \text {arcsinh}(x)} \, dx,x,c+d x\right )}{5 d}-\frac {\left (3 b^3 e^4\right ) \text {Subst}\left (\int \frac {x^5}{\sqrt {1+x^2} \sqrt {a+b \text {arcsinh}(x)}} \, dx,x,c+d x\right )}{200 d} \\ & = -\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh ^5\left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{200 d}+\frac {\left (2 b^2 e^4\right ) \text {Subst}\left (\int \sqrt {a+b \text {arcsinh}(x)} \, dx,x,c+d x\right )}{5 d}+\frac {\left (b^3 e^4\right ) \text {Subst}\left (\int \frac {x^3}{\sqrt {1+x^2} \sqrt {a+b \text {arcsinh}(x)}} \, dx,x,c+d x\right )}{30 d} \\ & = \frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}-\frac {\left (3 i b^2 e^4\right ) \text {Subst}\left (\int \left (\frac {i \sinh \left (\frac {5 a}{b}-\frac {5 x}{b}\right )}{16 \sqrt {x}}-\frac {5 i \sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{16 \sqrt {x}}+\frac {5 i \sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{8 \sqrt {x}}\right ) \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{200 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh ^3\left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{30 d}-\frac {\left (b^3 e^4\right ) \text {Subst}\left (\int \frac {x}{\sqrt {1+x^2} \sqrt {a+b \text {arcsinh}(x)}} \, dx,x,c+d x\right )}{5 d} \\ & = \frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}-\frac {\left (i b^2 e^4\right ) \text {Subst}\left (\int \left (-\frac {i \sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{4 \sqrt {x}}+\frac {3 i \sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{4 \sqrt {x}}\right ) \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{30 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {5 a}{b}-\frac {5 x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{3200 d}-\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{640 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{320 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{5 d} \\ & = \frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{-i \left (\frac {5 i a}{b}-\frac {5 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{6400 d}-\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{i \left (\frac {5 i a}{b}-\frac {5 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{6400 d}-\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{-i \left (\frac {3 i a}{b}-\frac {3 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{1280 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{i \left (\frac {3 i a}{b}-\frac {3 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{1280 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{-i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{640 d}-\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{640 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{120 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{40 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{-i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{10 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{10 d} \\ & = \frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int e^{\frac {5 a}{b}-\frac {5 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{3200 d}-\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int e^{-\frac {5 a}{b}+\frac {5 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{3200 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{-i \left (\frac {3 i a}{b}-\frac {3 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{240 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{i \left (\frac {3 i a}{b}-\frac {3 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{240 d}-\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int e^{\frac {3 a}{b}-\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{640 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int e^{-\frac {3 a}{b}+\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{640 d}+\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{320 d}-\frac {\left (3 b^2 e^4\right ) \text {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{320 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{-i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{80 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int \frac {e^{i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{80 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{5 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{5 d} \\ & = \frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}+\frac {67 b^{5/2} e^4 e^{a/b} \sqrt {\pi } \text {erf}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{640 d}-\frac {b^{5/2} e^4 e^{\frac {3 a}{b}} \sqrt {3 \pi } \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}+\frac {3 b^{5/2} e^4 e^{\frac {5 a}{b}} \sqrt {\frac {\pi }{5}} \text {erf}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d}-\frac {67 b^{5/2} e^4 e^{-\frac {a}{b}} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{640 d}+\frac {b^{5/2} e^4 e^{-\frac {3 a}{b}} \sqrt {3 \pi } \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}-\frac {3 b^{5/2} e^4 e^{-\frac {5 a}{b}} \sqrt {\frac {\pi }{5}} \text {erfi}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int e^{\frac {3 a}{b}-\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{120 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int e^{-\frac {3 a}{b}+\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{120 d}+\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{40 d}-\frac {\left (b^2 e^4\right ) \text {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{40 d} \\ & = \frac {2 b^2 e^4 (c+d x) \sqrt {a+b \text {arcsinh}(c+d x)}}{5 d}-\frac {b^2 e^4 (c+d x)^3 \sqrt {a+b \text {arcsinh}(c+d x)}}{15 d}+\frac {3 b^2 e^4 (c+d x)^5 \sqrt {a+b \text {arcsinh}(c+d x)}}{100 d}-\frac {4 b e^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}+\frac {2 b e^4 (c+d x)^2 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{15 d}-\frac {b e^4 (c+d x)^4 \sqrt {1+(c+d x)^2} (a+b \text {arcsinh}(c+d x))^{3/2}}{10 d}+\frac {e^4 (c+d x)^5 (a+b \text {arcsinh}(c+d x))^{5/2}}{5 d}+\frac {15 b^{5/2} e^4 e^{a/b} \sqrt {\pi } \text {erf}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{128 d}-\frac {b^{5/2} e^4 e^{\frac {3 a}{b}} \sqrt {\frac {\pi }{3}} \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{240 d}-\frac {b^{5/2} e^4 e^{\frac {3 a}{b}} \sqrt {3 \pi } \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}+\frac {3 b^{5/2} e^4 e^{\frac {5 a}{b}} \sqrt {\frac {\pi }{5}} \text {erf}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d}-\frac {15 b^{5/2} e^4 e^{-\frac {a}{b}} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{128 d}+\frac {b^{5/2} e^4 e^{-\frac {3 a}{b}} \sqrt {\frac {\pi }{3}} \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{240 d}+\frac {b^{5/2} e^4 e^{-\frac {3 a}{b}} \sqrt {3 \pi } \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{1280 d}-\frac {3 b^{5/2} e^4 e^{-\frac {5 a}{b}} \sqrt {\frac {\pi }{5}} \text {erfi}\left (\frac {\sqrt {5} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{6400 d} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.37 (sec) , antiderivative size = 324, normalized size of antiderivative = 0.46 \[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=-\frac {b^3 e^4 e^{-\frac {5 a}{b}} \left (33750 e^{\frac {6 a}{b}} \sqrt {\frac {a}{b}+\text {arcsinh}(c+d x)} \Gamma \left (\frac {7}{2},\frac {a}{b}+\text {arcsinh}(c+d x)\right )+27 \sqrt {5} \sqrt {-\frac {a+b \text {arcsinh}(c+d x)}{b}} \Gamma \left (\frac {7}{2},-\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right )-625 \sqrt {3} e^{\frac {2 a}{b}} \sqrt {-\frac {a+b \text {arcsinh}(c+d x)}{b}} \Gamma \left (\frac {7}{2},-\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right )+33750 e^{\frac {4 a}{b}} \sqrt {-\frac {a+b \text {arcsinh}(c+d x)}{b}} \Gamma \left (\frac {7}{2},-\frac {a+b \text {arcsinh}(c+d x)}{b}\right )-625 \sqrt {3} e^{\frac {8 a}{b}} \sqrt {\frac {a}{b}+\text {arcsinh}(c+d x)} \Gamma \left (\frac {7}{2},\frac {3 (a+b \text {arcsinh}(c+d x))}{b}\right )+27 \sqrt {5} e^{\frac {10 a}{b}} \sqrt {\frac {a}{b}+\text {arcsinh}(c+d x)} \Gamma \left (\frac {7}{2},\frac {5 (a+b \text {arcsinh}(c+d x))}{b}\right )\right )}{540000 d \sqrt {a+b \text {arcsinh}(c+d x)}} \]

[In]

Integrate[(c*e + d*e*x)^4*(a + b*ArcSinh[c + d*x])^(5/2),x]

[Out]

-1/540000*(b^3*e^4*(33750*E^((6*a)/b)*Sqrt[a/b + ArcSinh[c + d*x]]*Gamma[7/2, a/b + ArcSinh[c + d*x]] + 27*Sqr
t[5]*Sqrt[-((a + b*ArcSinh[c + d*x])/b)]*Gamma[7/2, (-5*(a + b*ArcSinh[c + d*x]))/b] - 625*Sqrt[3]*E^((2*a)/b)
*Sqrt[-((a + b*ArcSinh[c + d*x])/b)]*Gamma[7/2, (-3*(a + b*ArcSinh[c + d*x]))/b] + 33750*E^((4*a)/b)*Sqrt[-((a
+ b*ArcSinh[c + d*x])/b)]*Gamma[7/2, -((a + b*ArcSinh[c + d*x])/b)] - 625*Sqrt[3]*E^((8*a)/b)*Sqrt[a/b + ArcS
inh[c + d*x]]*Gamma[7/2, (3*(a + b*ArcSinh[c + d*x]))/b] + 27*Sqrt[5]*E^((10*a)/b)*Sqrt[a/b + ArcSinh[c + d*x]
]*Gamma[7/2, (5*(a + b*ArcSinh[c + d*x]))/b]))/(d*E^((5*a)/b)*Sqrt[a + b*ArcSinh[c + d*x]])

Maple [F]

\[\int \left (d e x +c e \right )^{4} \left (a +b \,\operatorname {arcsinh}\left (d x +c \right )\right )^{\frac {5}{2}}d x\]

[In]

int((d*e*x+c*e)^4*(a+b*arcsinh(d*x+c))^(5/2),x)

[Out]

int((d*e*x+c*e)^4*(a+b*arcsinh(d*x+c))^(5/2),x)

Fricas [F(-2)]

Exception generated. \[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=\text {Exception raised: TypeError} \]

[In]

integrate((d*e*x+c*e)^4*(a+b*arcsinh(d*x+c))^(5/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

Sympy [F(-1)]

Timed out. \[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=\text {Timed out} \]

[In]

integrate((d*e*x+c*e)**4*(a+b*asinh(d*x+c))**(5/2),x)

[Out]

Timed out

Maxima [F]

\[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=\int { {\left (d e x + c e\right )}^{4} {\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {5}{2}} \,d x } \]

[In]

integrate((d*e*x+c*e)^4*(a+b*arcsinh(d*x+c))^(5/2),x, algorithm="maxima")

[Out]

integrate((d*e*x + c*e)^4*(b*arcsinh(d*x + c) + a)^(5/2), x)

Giac [F]

\[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=\int { {\left (d e x + c e\right )}^{4} {\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {5}{2}} \,d x } \]

[In]

integrate((d*e*x+c*e)^4*(a+b*arcsinh(d*x+c))^(5/2),x, algorithm="giac")

[Out]

integrate((d*e*x + c*e)^4*(b*arcsinh(d*x + c) + a)^(5/2), x)

Mupad [F(-1)]

Timed out. \[ \int (c e+d e x)^4 (a+b \text {arcsinh}(c+d x))^{5/2} \, dx=\int {\left (c\,e+d\,e\,x\right )}^4\,{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^{5/2} \,d x \]

[In]

int((c*e + d*e*x)^4*(a + b*asinh(c + d*x))^(5/2),x)

[Out]

int((c*e + d*e*x)^4*(a + b*asinh(c + d*x))^(5/2), x)