Integrand size = 23, antiderivative size = 252 \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=-\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}}-\frac {4 e}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {8 e (c+d x)^2}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {32 e (c+d x) \sqrt {1+(c+d x)^2}}{15 b^3 d \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {8 e e^{\frac {2 a}{b}} \sqrt {2 \pi } \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{15 b^{7/2} d}+\frac {8 e e^{-\frac {2 a}{b}} \sqrt {2 \pi } \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{15 b^{7/2} d} \]
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Time = 0.38 (sec) , antiderivative size = 252, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {5859, 12, 5779, 5818, 5778, 3388, 2211, 2236, 2235, 5783} \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=\frac {8 \sqrt {2 \pi } e e^{\frac {2 a}{b}} \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{15 b^{7/2} d}+\frac {8 \sqrt {2 \pi } e e^{-\frac {2 a}{b}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{15 b^{7/2} d}-\frac {32 e \sqrt {(c+d x)^2+1} (c+d x)}{15 b^3 d \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {8 e (c+d x)^2}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {4 e}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {2 e \sqrt {(c+d x)^2+1} (c+d x)}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}} \]
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Rule 12
Rule 2211
Rule 2235
Rule 2236
Rule 3388
Rule 5778
Rule 5779
Rule 5783
Rule 5818
Rule 5859
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {e x}{(a+b \text {arcsinh}(x))^{7/2}} \, dx,x,c+d x\right )}{d} \\ & = \frac {e \text {Subst}\left (\int \frac {x}{(a+b \text {arcsinh}(x))^{7/2}} \, dx,x,c+d x\right )}{d} \\ & = -\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}}+\frac {(2 e) \text {Subst}\left (\int \frac {1}{\sqrt {1+x^2} (a+b \text {arcsinh}(x))^{5/2}} \, dx,x,c+d x\right )}{5 b d}+\frac {(4 e) \text {Subst}\left (\int \frac {x^2}{\sqrt {1+x^2} (a+b \text {arcsinh}(x))^{5/2}} \, dx,x,c+d x\right )}{5 b d} \\ & = -\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}}-\frac {4 e}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {8 e (c+d x)^2}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}+\frac {(16 e) \text {Subst}\left (\int \frac {x}{(a+b \text {arcsinh}(x))^{3/2}} \, dx,x,c+d x\right )}{15 b^2 d} \\ & = -\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}}-\frac {4 e}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {8 e (c+d x)^2}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {32 e (c+d x) \sqrt {1+(c+d x)^2}}{15 b^3 d \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {(32 e) \text {Subst}\left (\int \frac {\cosh \left (\frac {2 a}{b}-\frac {2 x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{15 b^4 d} \\ & = -\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}}-\frac {4 e}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {8 e (c+d x)^2}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {32 e (c+d x) \sqrt {1+(c+d x)^2}}{15 b^3 d \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {(16 e) \text {Subst}\left (\int \frac {e^{-i \left (\frac {2 i a}{b}-\frac {2 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{15 b^4 d}+\frac {(16 e) \text {Subst}\left (\int \frac {e^{i \left (\frac {2 i a}{b}-\frac {2 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c+d x)\right )}{15 b^4 d} \\ & = -\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}}-\frac {4 e}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {8 e (c+d x)^2}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {32 e (c+d x) \sqrt {1+(c+d x)^2}}{15 b^3 d \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {(32 e) \text {Subst}\left (\int e^{\frac {2 a}{b}-\frac {2 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{15 b^4 d}+\frac {(32 e) \text {Subst}\left (\int e^{-\frac {2 a}{b}+\frac {2 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{15 b^4 d} \\ & = -\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{5 b d (a+b \text {arcsinh}(c+d x))^{5/2}}-\frac {4 e}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {8 e (c+d x)^2}{15 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {32 e (c+d x) \sqrt {1+(c+d x)^2}}{15 b^3 d \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {8 e e^{\frac {2 a}{b}} \sqrt {2 \pi } \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{15 b^{7/2} d}+\frac {8 e e^{-\frac {2 a}{b}} \sqrt {2 \pi } \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{15 b^{7/2} d} \\ \end{align*}
Time = 0.65 (sec) , antiderivative size = 235, normalized size of antiderivative = 0.93 \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=-\frac {e \left ((a+b \text {arcsinh}(c+d x)) \left (e^{-\frac {2 a}{b}} \left (2 e^{2 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )} (4 a+b+4 b \text {arcsinh}(c+d x))+8 \sqrt {2} b \left (-\frac {a+b \text {arcsinh}(c+d x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )\right )+e^{-2 \text {arcsinh}(c+d x)} \left (-8 a+2 b-8 b \text {arcsinh}(c+d x)+8 \sqrt {2} e^{2 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )} \sqrt {\frac {a}{b}+\text {arcsinh}(c+d x)} (a+b \text {arcsinh}(c+d x)) \Gamma \left (\frac {1}{2},\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )\right )\right )+3 b^2 \sinh (2 \text {arcsinh}(c+d x))\right )}{15 b^3 d (a+b \text {arcsinh}(c+d x))^{5/2}} \]
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\[\int \frac {d e x +c e}{\left (a +b \,\operatorname {arcsinh}\left (d x +c \right )\right )^{\frac {7}{2}}}d x\]
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Exception generated. \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=\text {Exception raised: TypeError} \]
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\[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=e \left (\int \frac {c}{a^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 3 a^{2} b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx + \int \frac {d x}{a^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 3 a^{2} b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx\right ) \]
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\[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=\int { \frac {d e x + c e}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {7}{2}}} \,d x } \]
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\[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=\int { \frac {d e x + c e}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {7}{2}}} \,d x } \]
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Timed out. \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{7/2}} \, dx=\int \frac {c\,e+d\,e\,x}{{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^{7/2}} \,d x \]
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