Integrand size = 30, antiderivative size = 47 \[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\frac {\text {Chi}(2 \text {arcsinh}(a+b x))}{2 b}+\frac {\text {Chi}(4 \text {arcsinh}(a+b x))}{8 b}+\frac {3 \log (\text {arcsinh}(a+b x))}{8 b} \]
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Time = 0.12 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {5860, 5791, 3393, 3382} \[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\frac {\text {Chi}(2 \text {arcsinh}(a+b x))}{2 b}+\frac {\text {Chi}(4 \text {arcsinh}(a+b x))}{8 b}+\frac {3 \log (\text {arcsinh}(a+b x))}{8 b} \]
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Rule 3382
Rule 3393
Rule 5791
Rule 5860
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\left (1+x^2\right )^{3/2}}{\text {arcsinh}(x)} \, dx,x,a+b x\right )}{b} \\ & = \frac {\text {Subst}\left (\int \frac {\cosh ^4(x)}{x} \, dx,x,\text {arcsinh}(a+b x)\right )}{b} \\ & = \frac {\text {Subst}\left (\int \left (\frac {3}{8 x}+\frac {\cosh (2 x)}{2 x}+\frac {\cosh (4 x)}{8 x}\right ) \, dx,x,\text {arcsinh}(a+b x)\right )}{b} \\ & = \frac {3 \log (\text {arcsinh}(a+b x))}{8 b}+\frac {\text {Subst}\left (\int \frac {\cosh (4 x)}{x} \, dx,x,\text {arcsinh}(a+b x)\right )}{8 b}+\frac {\text {Subst}\left (\int \frac {\cosh (2 x)}{x} \, dx,x,\text {arcsinh}(a+b x)\right )}{2 b} \\ & = \frac {\text {Chi}(2 \text {arcsinh}(a+b x))}{2 b}+\frac {\text {Chi}(4 \text {arcsinh}(a+b x))}{8 b}+\frac {3 \log (\text {arcsinh}(a+b x))}{8 b} \\ \end{align*}
Time = 0.48 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.79 \[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\frac {4 \text {Chi}(2 \text {arcsinh}(a+b x))+\text {Chi}(4 \text {arcsinh}(a+b x))+3 \log (\text {arcsinh}(a+b x))}{8 b} \]
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Time = 0.74 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.77
method | result | size |
default | \(\frac {3 \ln \left (\operatorname {arcsinh}\left (b x +a \right )\right )+4 \,\operatorname {Chi}\left (2 \,\operatorname {arcsinh}\left (b x +a \right )\right )+\operatorname {Chi}\left (4 \,\operatorname {arcsinh}\left (b x +a \right )\right )}{8 b}\) | \(36\) |
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\[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\int { \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}}}{\operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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\[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\int \frac {\left (a^{2} + 2 a b x + b^{2} x^{2} + 1\right )^{\frac {3}{2}}}{\operatorname {asinh}{\left (a + b x \right )}}\, dx \]
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\[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\int { \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}}}{\operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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\[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\int { \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}}}{\operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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Timed out. \[ \int \frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{\text {arcsinh}(a+b x)} \, dx=\int \frac {{\left (a^2+2\,a\,b\,x+b^2\,x^2+1\right )}^{3/2}}{\mathrm {asinh}\left (a+b\,x\right )} \,d x \]
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