Integrand size = 30, antiderivative size = 11 \[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\frac {\log (\text {arcsinh}(a+b x))}{b} \]
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Time = 0.06 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {5860, 5782} \[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\frac {\log (\text {arcsinh}(a+b x))}{b} \]
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Rule 5782
Rule 5860
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{\sqrt {1+x^2} \text {arcsinh}(x)} \, dx,x,a+b x\right )}{b} \\ & = \frac {\log (\text {arcsinh}(a+b x))}{b} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.00 \[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\frac {\log (\text {arcsinh}(a+b x))}{b} \]
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Time = 0.72 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.09
method | result | size |
default | \(\frac {\ln \left (\operatorname {arcsinh}\left (b x +a \right )\right )}{b}\) | \(12\) |
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Leaf count of result is larger than twice the leaf count of optimal. 30 vs. \(2 (11) = 22\).
Time = 0.24 (sec) , antiderivative size = 30, normalized size of antiderivative = 2.73 \[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\frac {\log \left (\log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )\right )}{b} \]
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Leaf count of result is larger than twice the leaf count of optimal. 22 vs. \(2 (8) = 16\).
Time = 0.24 (sec) , antiderivative size = 22, normalized size of antiderivative = 2.00 \[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\begin {cases} \frac {\log {\left (\operatorname {asinh}{\left (a + b x \right )} \right )}}{b} & \text {for}\: b \neq 0 \\\frac {x}{\sqrt {a^{2} + 1} \operatorname {asinh}{\left (a \right )}} & \text {otherwise} \end {cases} \]
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\[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\int { \frac {1}{\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} \operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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\[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\int { \frac {1}{\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} \operatorname {arsinh}\left (b x + a\right )} \,d x } \]
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Time = 2.65 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.00 \[ \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \text {arcsinh}(a+b x)} \, dx=\frac {\ln \left (\mathrm {asinh}\left (a+b\,x\right )\right )}{b} \]
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