Integrand size = 6, antiderivative size = 162 \[ \int \text {arcsinh}\left (a x^2\right ) \, dx=-\frac {2 x \sqrt {1+a^2 x^4}}{1+a x^2}+x \text {arcsinh}\left (a x^2\right )+\frac {2 \left (1+a x^2\right ) \sqrt {\frac {1+a^2 x^4}{\left (1+a x^2\right )^2}} E\left (2 \arctan \left (\sqrt {a} x\right )|\frac {1}{2}\right )}{\sqrt {a} \sqrt {1+a^2 x^4}}-\frac {\left (1+a x^2\right ) \sqrt {\frac {1+a^2 x^4}{\left (1+a x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\sqrt {a} x\right ),\frac {1}{2}\right )}{\sqrt {a} \sqrt {1+a^2 x^4}} \]
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Time = 0.04 (sec) , antiderivative size = 162, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.833, Rules used = {5874, 12, 311, 226, 1210} \[ \int \text {arcsinh}\left (a x^2\right ) \, dx=-\frac {\left (a x^2+1\right ) \sqrt {\frac {a^2 x^4+1}{\left (a x^2+1\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\sqrt {a} x\right ),\frac {1}{2}\right )}{\sqrt {a} \sqrt {a^2 x^4+1}}+\frac {2 \left (a x^2+1\right ) \sqrt {\frac {a^2 x^4+1}{\left (a x^2+1\right )^2}} E\left (2 \arctan \left (\sqrt {a} x\right )|\frac {1}{2}\right )}{\sqrt {a} \sqrt {a^2 x^4+1}}-\frac {2 x \sqrt {a^2 x^4+1}}{a x^2+1}+x \text {arcsinh}\left (a x^2\right ) \]
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Rule 12
Rule 226
Rule 311
Rule 1210
Rule 5874
Rubi steps \begin{align*} \text {integral}& = x \text {arcsinh}\left (a x^2\right )-\int \frac {2 a x^2}{\sqrt {1+a^2 x^4}} \, dx \\ & = x \text {arcsinh}\left (a x^2\right )-(2 a) \int \frac {x^2}{\sqrt {1+a^2 x^4}} \, dx \\ & = x \text {arcsinh}\left (a x^2\right )-2 \int \frac {1}{\sqrt {1+a^2 x^4}} \, dx+2 \int \frac {1-a x^2}{\sqrt {1+a^2 x^4}} \, dx \\ & = -\frac {2 x \sqrt {1+a^2 x^4}}{1+a x^2}+x \text {arcsinh}\left (a x^2\right )+\frac {2 \left (1+a x^2\right ) \sqrt {\frac {1+a^2 x^4}{\left (1+a x^2\right )^2}} E\left (2 \arctan \left (\sqrt {a} x\right )|\frac {1}{2}\right )}{\sqrt {a} \sqrt {1+a^2 x^4}}-\frac {\left (1+a x^2\right ) \sqrt {\frac {1+a^2 x^4}{\left (1+a x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\sqrt {a} x\right ),\frac {1}{2}\right )}{\sqrt {a} \sqrt {1+a^2 x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.22 \[ \int \text {arcsinh}\left (a x^2\right ) \, dx=x \text {arcsinh}\left (a x^2\right )-\frac {2}{3} a x^3 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3}{4},\frac {7}{4},-a^2 x^4\right ) \]
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Result contains complex when optimal does not.
Time = 0.14 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.48
method | result | size |
default | \(x \,\operatorname {arcsinh}\left (a \,x^{2}\right )-\frac {2 i \sqrt {-i a \,x^{2}+1}\, \sqrt {i a \,x^{2}+1}\, \left (\operatorname {EllipticF}\left (x \sqrt {i a}, i\right )-\operatorname {EllipticE}\left (x \sqrt {i a}, i\right )\right )}{\sqrt {i a}\, \sqrt {a^{2} x^{4}+1}}\) | \(77\) |
parts | \(x \,\operatorname {arcsinh}\left (a \,x^{2}\right )-\frac {2 i \sqrt {-i a \,x^{2}+1}\, \sqrt {i a \,x^{2}+1}\, \left (\operatorname {EllipticF}\left (x \sqrt {i a}, i\right )-\operatorname {EllipticE}\left (x \sqrt {i a}, i\right )\right )}{\sqrt {i a}\, \sqrt {a^{2} x^{4}+1}}\) | \(77\) |
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none
Time = 0.11 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.58 \[ \int \text {arcsinh}\left (a x^2\right ) \, dx=\frac {a x^{2} \log \left (a x^{2} + \sqrt {a^{2} x^{4} + 1}\right ) - 2 \, a x \left (-\frac {1}{a^{2}}\right )^{\frac {3}{4}} E(\arcsin \left (\frac {\left (-\frac {1}{a^{2}}\right )^{\frac {1}{4}}}{x}\right )\,|\,-1) + 2 \, a x \left (-\frac {1}{a^{2}}\right )^{\frac {3}{4}} F(\arcsin \left (\frac {\left (-\frac {1}{a^{2}}\right )^{\frac {1}{4}}}{x}\right )\,|\,-1) - 2 \, \sqrt {a^{2} x^{4} + 1}}{a x} \]
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\[ \int \text {arcsinh}\left (a x^2\right ) \, dx=\int \operatorname {asinh}{\left (a x^{2} \right )}\, dx \]
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\[ \int \text {arcsinh}\left (a x^2\right ) \, dx=\int { \operatorname {arsinh}\left (a x^{2}\right ) \,d x } \]
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\[ \int \text {arcsinh}\left (a x^2\right ) \, dx=\int { \operatorname {arsinh}\left (a x^{2}\right ) \,d x } \]
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Timed out. \[ \int \text {arcsinh}\left (a x^2\right ) \, dx=\int \mathrm {asinh}\left (a\,x^2\right ) \,d x \]
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