Integrand size = 22, antiderivative size = 348 \[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=15 b^2 x \sqrt {a+i b \arcsin \left (1-i d x^2\right )}-\frac {5 b \sqrt {2 i d x^2+d^2 x^4} \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{3/2}}{d x}+x \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2}+\frac {15 b^2 \sqrt {\pi } x \operatorname {FresnelS}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right ) \left (\cosh \left (\frac {a}{2 b}\right )+i \sinh \left (\frac {a}{2 b}\right )\right )}{\sqrt {-\frac {i}{b}} \left (\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )\right )}-\frac {15 \sqrt {-\frac {i}{b}} b^3 \sqrt {\pi } x \operatorname {FresnelC}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right ) \left (i \cosh \left (\frac {a}{2 b}\right )+\sinh \left (\frac {a}{2 b}\right )\right )}{\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )} \]
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Time = 0.09 (sec) , antiderivative size = 348, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {4898, 4895} \[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=-\frac {15 \sqrt {\pi } \sqrt {-\frac {i}{b}} b^3 x \left (\sinh \left (\frac {a}{2 b}\right )+i \cosh \left (\frac {a}{2 b}\right )\right ) \operatorname {FresnelC}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right )}{\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )}+\frac {15 \sqrt {\pi } b^2 x \left (\cosh \left (\frac {a}{2 b}\right )+i \sinh \left (\frac {a}{2 b}\right )\right ) \operatorname {FresnelS}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right )}{\sqrt {-\frac {i}{b}} \left (\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )\right )}+15 b^2 x \sqrt {a+i b \arcsin \left (1-i d x^2\right )}-\frac {5 b \sqrt {d^2 x^4+2 i d x^2} \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{3/2}}{d x}+x \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \]
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Rule 4895
Rule 4898
Rubi steps \begin{align*} \text {integral}& = -\frac {5 b \sqrt {2 i d x^2+d^2 x^4} \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{3/2}}{d x}+x \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2}+\left (15 b^2\right ) \int \sqrt {a+i b \arcsin \left (1-i d x^2\right )} \, dx \\ & = 15 b^2 x \sqrt {a+i b \arcsin \left (1-i d x^2\right )}-\frac {5 b \sqrt {2 i d x^2+d^2 x^4} \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{3/2}}{d x}+x \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2}+\frac {15 b^2 \sqrt {\pi } x \operatorname {FresnelS}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right ) \left (\cosh \left (\frac {a}{2 b}\right )+i \sinh \left (\frac {a}{2 b}\right )\right )}{\sqrt {-\frac {i}{b}} \left (\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )\right )}-\frac {15 \sqrt {-\frac {i}{b}} b^3 \sqrt {\pi } x \operatorname {FresnelC}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right ) \left (i \cosh \left (\frac {a}{2 b}\right )+\sinh \left (\frac {a}{2 b}\right )\right )}{\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )} \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 337, normalized size of antiderivative = 0.97 \[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=-\frac {5 b \sqrt {d x^2 \left (2 i+d x^2\right )} \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{3/2}}{d x}+x \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2}+\frac {15 b^2 x \left (\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )} \left (\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )\right )-\sqrt {\pi } \operatorname {FresnelC}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right ) \left (\cosh \left (\frac {a}{2 b}\right )-i \sinh \left (\frac {a}{2 b}\right )\right )+\sqrt {\pi } \operatorname {FresnelS}\left (\frac {\sqrt {-\frac {i}{b}} \sqrt {a+i b \arcsin \left (1-i d x^2\right )}}{\sqrt {\pi }}\right ) \left (\cosh \left (\frac {a}{2 b}\right )+i \sinh \left (\frac {a}{2 b}\right )\right )\right )}{\sqrt {-\frac {i}{b}} \left (\cos \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )-\sin \left (\frac {1}{2} \arcsin \left (1-i d x^2\right )\right )\right )} \]
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\[\int {\left (a +b \,\operatorname {arcsinh}\left (d \,x^{2}+i\right )\right )}^{\frac {5}{2}}d x\]
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Exception generated. \[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=\text {Exception raised: TypeError} \]
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Exception generated. \[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=\text {Exception raised: TypeError} \]
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\[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=\int { {\left (b \operatorname {arsinh}\left (d x^{2} + i\right ) + a\right )}^{\frac {5}{2}} \,d x } \]
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Exception generated. \[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \left (a+i b \arcsin \left (1-i d x^2\right )\right )^{5/2} \, dx=\int {\left (a+b\,\mathrm {asinh}\left (d\,x^2+1{}\mathrm {i}\right )\right )}^{5/2} \,d x \]
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