Integrand size = 40, antiderivative size = 40 \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=\text {Int}\left (\frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2},x\right ) \]
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Not integrable
Time = 0.03 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=\int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx \\ \end{align*}
Not integrable
Time = 1.13 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.05 \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=\int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx \]
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Not integrable
Time = 0.31 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.90
\[\int \frac {1}{\left (-c^{2} x^{2}+1\right ) \left (a +b \,\operatorname {arcsinh}\left (\frac {\sqrt {-c x +1}}{\sqrt {c x +1}}\right )\right )^{2}}d x\]
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Not integrable
Time = 0.27 (sec) , antiderivative size = 91, normalized size of antiderivative = 2.28 \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=\int { -\frac {1}{{\left (c^{2} x^{2} - 1\right )} {\left (b \operatorname {arsinh}\left (\frac {\sqrt {-c x + 1}}{\sqrt {c x + 1}}\right ) + a\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=\text {Timed out} \]
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Not integrable
Time = 0.59 (sec) , antiderivative size = 474, normalized size of antiderivative = 11.85 \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=\int { -\frac {1}{{\left (c^{2} x^{2} - 1\right )} {\left (b \operatorname {arsinh}\left (\frac {\sqrt {-c x + 1}}{\sqrt {c x + 1}}\right ) + a\right )}^{2}} \,d x } \]
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Not integrable
Time = 20.28 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.95 \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=\int { -\frac {1}{{\left (c^{2} x^{2} - 1\right )} {\left (b \operatorname {arsinh}\left (\frac {\sqrt {-c x + 1}}{\sqrt {c x + 1}}\right ) + a\right )}^{2}} \,d x } \]
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Not integrable
Time = 3.63 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.98 \[ \int \frac {1}{\left (1-c^2 x^2\right ) \left (a+b \text {arcsinh}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2} \, dx=-\int \frac {1}{{\left (a+b\,\mathrm {asinh}\left (\frac {\sqrt {1-c\,x}}{\sqrt {c\,x+1}}\right )\right )}^2\,\left (c^2\,x^2-1\right )} \,d x \]
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