Integrand size = 16, antiderivative size = 116 \[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=\frac {d \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}-\frac {e \text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right ) \sinh \left (\frac {2 a}{b}\right )}{2 b c^2}-\frac {d \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}+\frac {e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{2 b c^2} \]
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Time = 0.25 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.438, Rules used = {5830, 6874, 3384, 3379, 3382, 5556, 12} \[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=-\frac {e \sinh \left (\frac {2 a}{b}\right ) \text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{2 b c^2}+\frac {e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{2 b c^2}+\frac {d \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}-\frac {d \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c} \]
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Rule 12
Rule 3379
Rule 3382
Rule 3384
Rule 5556
Rule 5830
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\cosh (x) (c d+e \sinh (x))}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{c^2} \\ & = \frac {\text {Subst}\left (\int \left (\frac {c d \cosh (x)}{a+b x}+\frac {e \cosh (x) \sinh (x)}{a+b x}\right ) \, dx,x,\text {arcsinh}(c x)\right )}{c^2} \\ & = \frac {d \text {Subst}\left (\int \frac {\cosh (x)}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{c}+\frac {e \text {Subst}\left (\int \frac {\cosh (x) \sinh (x)}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{c^2} \\ & = \frac {e \text {Subst}\left (\int \frac {\sinh (2 x)}{2 (a+b x)} \, dx,x,\text {arcsinh}(c x)\right )}{c^2}+\frac {\left (d \cosh \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cosh \left (\frac {a}{b}+x\right )}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{c}-\frac {\left (d \sinh \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}+x\right )}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{c} \\ & = \frac {d \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}-\frac {d \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}+\frac {e \text {Subst}\left (\int \frac {\sinh (2 x)}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{2 c^2} \\ & = \frac {d \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}-\frac {d \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}+\frac {\left (e \cosh \left (\frac {2 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sinh \left (\frac {2 a}{b}+2 x\right )}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{2 c^2}-\frac {\left (e \sinh \left (\frac {2 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cosh \left (\frac {2 a}{b}+2 x\right )}{a+b x} \, dx,x,\text {arcsinh}(c x)\right )}{2 c^2} \\ & = \frac {d \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}-\frac {e \text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right ) \sinh \left (\frac {2 a}{b}\right )}{2 b c^2}-\frac {d \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}+\frac {e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{2 b c^2} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.84 \[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=\frac {2 c d \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )-e \text {Chi}\left (2 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right ) \sinh \left (\frac {2 a}{b}\right )-2 c d \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )+e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (2 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right )}{2 b c^2} \]
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Time = 0.59 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.03
method | result | size |
derivativedivides | \(\frac {-\frac {{\mathrm e}^{\frac {a}{b}} \operatorname {Ei}_{1}\left (\operatorname {arcsinh}\left (c x \right )+\frac {a}{b}\right ) d}{2 b}-\frac {{\mathrm e}^{-\frac {a}{b}} \operatorname {Ei}_{1}\left (-\operatorname {arcsinh}\left (c x \right )-\frac {a}{b}\right ) d}{2 b}+\frac {e \,{\mathrm e}^{\frac {2 a}{b}} \operatorname {Ei}_{1}\left (2 \,\operatorname {arcsinh}\left (c x \right )+\frac {2 a}{b}\right )}{4 c b}-\frac {e \,{\mathrm e}^{-\frac {2 a}{b}} \operatorname {Ei}_{1}\left (-2 \,\operatorname {arcsinh}\left (c x \right )-\frac {2 a}{b}\right )}{4 c b}}{c}\) | \(120\) |
default | \(\frac {-\frac {{\mathrm e}^{\frac {a}{b}} \operatorname {Ei}_{1}\left (\operatorname {arcsinh}\left (c x \right )+\frac {a}{b}\right ) d}{2 b}-\frac {{\mathrm e}^{-\frac {a}{b}} \operatorname {Ei}_{1}\left (-\operatorname {arcsinh}\left (c x \right )-\frac {a}{b}\right ) d}{2 b}+\frac {e \,{\mathrm e}^{\frac {2 a}{b}} \operatorname {Ei}_{1}\left (2 \,\operatorname {arcsinh}\left (c x \right )+\frac {2 a}{b}\right )}{4 c b}-\frac {e \,{\mathrm e}^{-\frac {2 a}{b}} \operatorname {Ei}_{1}\left (-2 \,\operatorname {arcsinh}\left (c x \right )-\frac {2 a}{b}\right )}{4 c b}}{c}\) | \(120\) |
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\[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=\int { \frac {e x + d}{b \operatorname {arsinh}\left (c x\right ) + a} \,d x } \]
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\[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=\int \frac {d + e x}{a + b \operatorname {asinh}{\left (c x \right )}}\, dx \]
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\[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=\int { \frac {e x + d}{b \operatorname {arsinh}\left (c x\right ) + a} \,d x } \]
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\[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=\int { \frac {e x + d}{b \operatorname {arsinh}\left (c x\right ) + a} \,d x } \]
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Timed out. \[ \int \frac {d+e x}{a+b \text {arcsinh}(c x)} \, dx=\int \frac {d+e\,x}{a+b\,\mathrm {asinh}\left (c\,x\right )} \,d x \]
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