Integrand size = 12, antiderivative size = 116 \[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=-\frac {a}{2 x^2}-\frac {b}{x}-\frac {\left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{2 \left (1+a^2\right ) x^2}-\frac {b^2 \text {arctanh}\left (\frac {1+a^2+a b x}{\sqrt {1+a^2} \sqrt {1+a^2+2 a b x+b^2 x^2}}\right )}{2 \left (1+a^2\right )^{3/2}} \]
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Time = 0.06 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {5878, 14, 734, 738, 212} \[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=-\frac {b^2 \text {arctanh}\left (\frac {a^2+a b x+1}{\sqrt {a^2+1} \sqrt {a^2+2 a b x+b^2 x^2+1}}\right )}{2 \left (a^2+1\right )^{3/2}}-\frac {\left (a^2+a b x+1\right ) \sqrt {a^2+2 a b x+b^2 x^2+1}}{2 \left (a^2+1\right ) x^2}-\frac {a}{2 x^2}-\frac {b}{x} \]
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Rule 14
Rule 212
Rule 734
Rule 738
Rule 5878
Rubi steps \begin{align*} \text {integral}& = \int \frac {a+b x+\sqrt {1+(a+b x)^2}}{x^3} \, dx \\ & = \int \left (\frac {a}{x^3}+\frac {b}{x^2}+\frac {\sqrt {1+a^2+2 a b x+b^2 x^2}}{x^3}\right ) \, dx \\ & = -\frac {a}{2 x^2}-\frac {b}{x}+\int \frac {\sqrt {1+a^2+2 a b x+b^2 x^2}}{x^3} \, dx \\ & = -\frac {a}{2 x^2}-\frac {b}{x}-\frac {\left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{2 \left (1+a^2\right ) x^2}+\frac {b^2 \int \frac {1}{x \sqrt {1+a^2+2 a b x+b^2 x^2}} \, dx}{2 \left (1+a^2\right )} \\ & = -\frac {a}{2 x^2}-\frac {b}{x}-\frac {\left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{2 \left (1+a^2\right ) x^2}-\frac {b^2 \text {Subst}\left (\int \frac {1}{4 \left (1+a^2\right )-x^2} \, dx,x,\frac {2 \left (1+a^2\right )+2 a b x}{\sqrt {1+a^2+2 a b x+b^2 x^2}}\right )}{1+a^2} \\ & = -\frac {a}{2 x^2}-\frac {b}{x}-\frac {\left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{2 \left (1+a^2\right ) x^2}-\frac {b^2 \text {arctanh}\left (\frac {1+a^2+a b x}{\sqrt {1+a^2} \sqrt {1+a^2+2 a b x+b^2 x^2}}\right )}{2 \left (1+a^2\right )^{3/2}} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.11 \[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=\frac {1}{2} \left (-\frac {a}{x^2}-\frac {2 b}{x}-\frac {\left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{\left (1+a^2\right ) x^2}+\frac {b^2 \log (x)}{\left (1+a^2\right )^{3/2}}-\frac {b^2 \log \left (1+a^2+a b x+\sqrt {1+a^2} \sqrt {1+a^2+2 a b x+b^2 x^2}\right )}{\left (1+a^2\right )^{3/2}}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(458\) vs. \(2(102)=204\).
Time = 0.75 (sec) , antiderivative size = 459, normalized size of antiderivative = 3.96
method | result | size |
default | \(-\frac {\left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{2 \left (a^{2}+1\right ) x^{2}}-\frac {a b \left (-\frac {\left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{\left (a^{2}+1\right ) x}+\frac {a b \left (\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}+\frac {a b \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{\sqrt {b^{2}}}-\sqrt {a^{2}+1}\, \ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )\right )}{a^{2}+1}+\frac {2 b^{2} \left (\frac {\left (2 b^{2} x +2 a b \right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{4 b^{2}}+\frac {\left (4 b^{2} \left (a^{2}+1\right )-4 a^{2} b^{2}\right ) \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{8 b^{2} \sqrt {b^{2}}}\right )}{a^{2}+1}\right )}{2 \left (a^{2}+1\right )}+\frac {b^{2} \left (\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}+\frac {a b \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{\sqrt {b^{2}}}-\sqrt {a^{2}+1}\, \ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )\right )}{2 a^{2}+2}-\frac {b}{x}-\frac {a}{2 x^{2}}\) | \(459\) |
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none
Time = 0.25 (sec) , antiderivative size = 181, normalized size of antiderivative = 1.56 \[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=\frac {\sqrt {a^{2} + 1} b^{2} x^{2} \log \left (-\frac {a^{2} b x + a^{3} + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} {\left (a^{2} - \sqrt {a^{2} + 1} a + 1\right )} - {\left (a b x + a^{2} + 1\right )} \sqrt {a^{2} + 1} + a}{x}\right ) - a^{5} - {\left (a^{3} + a\right )} b^{2} x^{2} - 2 \, a^{3} - 2 \, {\left (a^{4} + 2 \, a^{2} + 1\right )} b x - {\left (a^{4} + {\left (a^{3} + a\right )} b x + 2 \, a^{2} + 1\right )} \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} - a}{2 \, {\left (a^{4} + 2 \, a^{2} + 1\right )} x^{2}} \]
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\[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=\int \frac {a + b x + \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}{x^{3}}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 313 vs. \(2 (102) = 204\).
Time = 0.38 (sec) , antiderivative size = 313, normalized size of antiderivative = 2.70 \[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=\frac {a^{2} b^{2} \operatorname {arsinh}\left (\frac {2 \, a b x}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2 \, a^{2}}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}}\right )}{2 \, {\left (a^{2} + 1\right )}^{\frac {3}{2}}} - \frac {b^{2} \operatorname {arsinh}\left (\frac {2 \, a b x}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2 \, a^{2}}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}}\right )}{2 \, \sqrt {a^{2} + 1}} + \frac {\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} b^{2}}{2 \, {\left (a^{2} + 1\right )}} + \frac {\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} a b}{2 \, {\left (a^{2} + 1\right )} x} - \frac {b}{x} - \frac {a}{2 \, x^{2}} - \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}}}{2 \, {\left (a^{2} + 1\right )} x^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 384 vs. \(2 (102) = 204\).
Time = 0.34 (sec) , antiderivative size = 384, normalized size of antiderivative = 3.31 \[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=\frac {b^{2} \log \left (\frac {{\left | -2 \, x {\left | b \right |} + 2 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} - 2 \, \sqrt {a^{2} + 1} \right |}}{{\left | -2 \, x {\left | b \right |} + 2 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} + 2 \, \sqrt {a^{2} + 1} \right |}}\right )}{2 \, {\left (a^{2} + 1\right )}^{\frac {3}{2}}} - \frac {2 \, b x + a}{2 \, x^{2}} + \frac {2 \, {\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )}^{3} a^{2} b^{2} + 2 \, {\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )} a^{4} b^{2} + 4 \, {\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )}^{2} a^{3} b {\left | b \right |} + {\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )}^{3} b^{2} + 3 \, {\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )} a^{2} b^{2} + 4 \, {\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )}^{2} a b {\left | b \right |} + {\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )} b^{2}}{{\left ({\left (x {\left | b \right |} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )}^{2} - a^{2} - 1\right )}^{2} {\left (a^{2} + 1\right )}} \]
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Timed out. \[ \int \frac {e^{\text {arcsinh}(a+b x)}}{x^3} \, dx=\int \frac {a+\sqrt {{\left (a+b\,x\right )}^2+1}+b\,x}{x^3} \,d x \]
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