Integrand size = 10, antiderivative size = 65 \[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\frac {\sqrt {\pi } \text {erfi}\left (\frac {1}{2} (-1+2 \text {arcsinh}(a+b x))\right )}{4 b \sqrt [4]{e}}+\frac {\sqrt {\pi } \text {erfi}\left (\frac {1}{2} (1+2 \text {arcsinh}(a+b x))\right )}{4 b \sqrt [4]{e}} \]
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Time = 0.04 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {5872, 5624, 2266, 2235} \[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\frac {\sqrt {\pi } \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)-1)\right )}{4 \sqrt [4]{e} b}+\frac {\sqrt {\pi } \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)+1)\right )}{4 \sqrt [4]{e} b} \]
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Rule 2235
Rule 2266
Rule 5624
Rule 5872
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int e^{x^2} \cosh (x) \, dx,x,\text {arcsinh}(a+b x)\right )}{b} \\ & = \frac {\text {Subst}\left (\int \left (\frac {1}{2} e^{-x+x^2}+\frac {e^{x+x^2}}{2}\right ) \, dx,x,\text {arcsinh}(a+b x)\right )}{b} \\ & = \frac {\text {Subst}\left (\int e^{-x+x^2} \, dx,x,\text {arcsinh}(a+b x)\right )}{2 b}+\frac {\text {Subst}\left (\int e^{x+x^2} \, dx,x,\text {arcsinh}(a+b x)\right )}{2 b} \\ & = \frac {\text {Subst}\left (\int e^{\frac {1}{4} (-1+2 x)^2} \, dx,x,\text {arcsinh}(a+b x)\right )}{2 b \sqrt [4]{e}}+\frac {\text {Subst}\left (\int e^{\frac {1}{4} (1+2 x)^2} \, dx,x,\text {arcsinh}(a+b x)\right )}{2 b \sqrt [4]{e}} \\ & = \frac {\sqrt {\pi } \text {erfi}\left (\frac {1}{2} (-1+2 \text {arcsinh}(a+b x))\right )}{4 b \sqrt [4]{e}}+\frac {\sqrt {\pi } \text {erfi}\left (\frac {1}{2} (1+2 \text {arcsinh}(a+b x))\right )}{4 b \sqrt [4]{e}} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.68 \[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\frac {\sqrt {\pi } \left (\text {erfi}\left (\frac {1}{2}+\text {arcsinh}(a+b x)\right )+\text {erfi}\left (\frac {1}{2} (-1+2 \text {arcsinh}(a+b x))\right )\right )}{4 b \sqrt [4]{e}} \]
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\[\int {\mathrm e}^{\operatorname {arcsinh}\left (b x +a \right )^{2}}d x\]
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\[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\int { e^{\left (\operatorname {arsinh}\left (b x + a\right )^{2}\right )} \,d x } \]
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\[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\int e^{\operatorname {asinh}^{2}{\left (a + b x \right )}}\, dx \]
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\[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\int { e^{\left (\operatorname {arsinh}\left (b x + a\right )^{2}\right )} \,d x } \]
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\[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\int { e^{\left (\operatorname {arsinh}\left (b x + a\right )^{2}\right )} \,d x } \]
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Timed out. \[ \int e^{\text {arcsinh}(a+b x)^2} \, dx=\int {\mathrm {e}}^{{\mathrm {asinh}\left (a+b\,x\right )}^2} \,d x \]
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