Integrand size = 16, antiderivative size = 179 \[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=-\frac {b c (d+e x)^{2+m} \sqrt {1-\frac {d+e x}{d-\frac {e}{\sqrt {-c^2}}}} \sqrt {1-\frac {d+e x}{d+\frac {e}{\sqrt {-c^2}}}} \operatorname {AppellF1}\left (2+m,\frac {1}{2},\frac {1}{2},3+m,\frac {d+e x}{d-\frac {e}{\sqrt {-c^2}}},\frac {d+e x}{d+\frac {e}{\sqrt {-c^2}}}\right )}{e^2 (1+m) (2+m) \sqrt {1+c^2 x^2}}+\frac {(d+e x)^{1+m} (a+b \text {arcsinh}(c x))}{e (1+m)} \]
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Time = 0.08 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {5828, 774, 138} \[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=\frac {(d+e x)^{m+1} (a+b \text {arcsinh}(c x))}{e (m+1)}-\frac {b c \sqrt {1-\frac {d+e x}{d-\frac {e}{\sqrt {-c^2}}}} \sqrt {1-\frac {d+e x}{\frac {e}{\sqrt {-c^2}}+d}} (d+e x)^{m+2} \operatorname {AppellF1}\left (m+2,\frac {1}{2},\frac {1}{2},m+3,\frac {d+e x}{d-\frac {e}{\sqrt {-c^2}}},\frac {d+e x}{d+\frac {e}{\sqrt {-c^2}}}\right )}{e^2 (m+1) (m+2) \sqrt {c^2 x^2+1}} \]
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Rule 138
Rule 774
Rule 5828
Rubi steps \begin{align*} \text {integral}& = \frac {(d+e x)^{1+m} (a+b \text {arcsinh}(c x))}{e (1+m)}-\frac {(b c) \int \frac {(d+e x)^{1+m}}{\sqrt {1+c^2 x^2}} \, dx}{e (1+m)} \\ & = \frac {(d+e x)^{1+m} (a+b \text {arcsinh}(c x))}{e (1+m)}-\frac {\left (b c \sqrt {1-\frac {d+e x}{d-\frac {\sqrt {-c^2} e}{c^2}}} \sqrt {1-\frac {d+e x}{d+\frac {\sqrt {-c^2} e}{c^2}}}\right ) \text {Subst}\left (\int \frac {x^{1+m}}{\sqrt {1-\frac {x}{d-\frac {e}{\sqrt {-c^2}}}} \sqrt {1-\frac {x}{d+\frac {e}{\sqrt {-c^2}}}}} \, dx,x,d+e x\right )}{e^2 (1+m) \sqrt {1+c^2 x^2}} \\ & = -\frac {b c (d+e x)^{2+m} \sqrt {1-\frac {d+e x}{d-\frac {e}{\sqrt {-c^2}}}} \sqrt {1-\frac {d+e x}{d+\frac {e}{\sqrt {-c^2}}}} \operatorname {AppellF1}\left (2+m,\frac {1}{2},\frac {1}{2},3+m,\frac {d+e x}{d-\frac {e}{\sqrt {-c^2}}},\frac {d+e x}{d+\frac {e}{\sqrt {-c^2}}}\right )}{e^2 (1+m) (2+m) \sqrt {1+c^2 x^2}}+\frac {(d+e x)^{1+m} (a+b \text {arcsinh}(c x))}{e (1+m)} \\ \end{align*}
\[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=\int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx \]
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\[\int \left (e x +d \right )^{m} \left (a +b \,\operatorname {arcsinh}\left (c x \right )\right )d x\]
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\[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=\int { {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} {\left (e x + d\right )}^{m} \,d x } \]
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\[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=\int \left (a + b \operatorname {asinh}{\left (c x \right )}\right ) \left (d + e x\right )^{m}\, dx \]
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\[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=\int { {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} {\left (e x + d\right )}^{m} \,d x } \]
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\[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=\int { {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} {\left (e x + d\right )}^{m} \,d x } \]
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Timed out. \[ \int (d+e x)^m (a+b \text {arcsinh}(c x)) \, dx=\int \left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )\,{\left (d+e\,x\right )}^m \,d x \]
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