Integrand size = 20, antiderivative size = 3 \[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\text {Chi}(\text {arccosh}(x)) \]
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Time = 0.08 (sec) , antiderivative size = 3, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {5953, 3382} \[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\text {Chi}(\text {arccosh}(x)) \]
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Rule 3382
Rule 5953
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {\cosh (x)}{x} \, dx,x,\text {arccosh}(x)\right ) \\ & = \text {Chi}(\text {arccosh}(x)) \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 3, normalized size of antiderivative = 1.00 \[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\text {Chi}(\text {arccosh}(x)) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(44\) vs. \(2(3)=6\).
Time = 1.60 (sec) , antiderivative size = 45, normalized size of antiderivative = 15.00
method | result | size |
default | \(-\frac {\sqrt {2 x -2}\, \sqrt {2+2 x}\, \sqrt {x -1}\, \sqrt {1+x}\, \left (\operatorname {Ei}_{1}\left (\operatorname {arccosh}\left (x \right )\right )+\operatorname {Ei}_{1}\left (-\operatorname {arccosh}\left (x \right )\right )\right )}{4 \left (x^{2}-1\right )}\) | \(45\) |
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\[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\int { \frac {x}{\sqrt {x + 1} \sqrt {x - 1} \operatorname {arcosh}\left (x\right )} \,d x } \]
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\[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\int \frac {x}{\sqrt {x - 1} \sqrt {x + 1} \operatorname {acosh}{\left (x \right )}}\, dx \]
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\[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\int { \frac {x}{\sqrt {x + 1} \sqrt {x - 1} \operatorname {arcosh}\left (x\right )} \,d x } \]
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\[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\int { \frac {x}{\sqrt {x + 1} \sqrt {x - 1} \operatorname {arcosh}\left (x\right )} \,d x } \]
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Timed out. \[ \int \frac {x}{\sqrt {-1+x} \sqrt {1+x} \text {arccosh}(x)} \, dx=\int \frac {x}{\mathrm {acosh}\left (x\right )\,\sqrt {x-1}\,\sqrt {x+1}} \,d x \]
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