3.1.69 \(\int \frac {e^{\frac {1}{2} \tanh ^{-1}(a x)}}{x^6} \, dx\) [69]

Optimal. Leaf size=197 \[ -\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{960 x^2}-\frac {611 a^4 (1-a x)^{3/4} \sqrt [4]{1+a x}}{1920 x}-\frac {31}{128} a^5 \text {ArcTan}\left (\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )-\frac {31}{128} a^5 \tanh ^{-1}\left (\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right ) \]

[Out]

-1/5*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/x^5-9/40*a*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/x^4-11/48*a^2*(-a*x+1)^(3/4)*(a*x+1)
^(1/4)/x^3-269/960*a^3*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/x^2-611/1920*a^4*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/x-31/128*a^5
*arctan((a*x+1)^(1/4)/(-a*x+1)^(1/4))-31/128*a^5*arctanh((a*x+1)^(1/4)/(-a*x+1)^(1/4))

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Rubi [A]
time = 0.07, antiderivative size = 197, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 8, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.571, Rules used = {6261, 101, 156, 12, 95, 218, 212, 209} \begin {gather*} -\frac {31}{128} a^5 \text {ArcTan}\left (\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}\right )-\frac {31}{128} a^5 \tanh ^{-1}\left (\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}\right )-\frac {611 a^4 (1-a x)^{3/4} \sqrt [4]{a x+1}}{1920 x}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{a x+1}}{960 x^2}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{a x+1}}{48 x^3}-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{a x+1}}{40 x^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[E^(ArcTanh[a*x]/2)/x^6,x]

[Out]

-1/5*((1 - a*x)^(3/4)*(1 + a*x)^(1/4))/x^5 - (9*a*(1 - a*x)^(3/4)*(1 + a*x)^(1/4))/(40*x^4) - (11*a^2*(1 - a*x
)^(3/4)*(1 + a*x)^(1/4))/(48*x^3) - (269*a^3*(1 - a*x)^(3/4)*(1 + a*x)^(1/4))/(960*x^2) - (611*a^4*(1 - a*x)^(
3/4)*(1 + a*x)^(1/4))/(1920*x) - (31*a^5*ArcTan[(1 + a*x)^(1/4)/(1 - a*x)^(1/4)])/128 - (31*a^5*ArcTanh[(1 + a
*x)^(1/4)/(1 - a*x)^(1/4)])/128

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 95

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 101

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(a + b*
x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 1)*(b*e - a*f))), x] - Dist[1/((m + 1)*(b*e - a*f)), Int[(a +
b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[d*e*n + c*f*(m + p + 2) + d*f*(m + n + p + 2)*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 156

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f
))), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && ILtQ[m, -1]

Rule 209

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*ArcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 218

Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]},
Dist[r/(2*a), Int[1/(r - s*x^2), x], x] + Dist[r/(2*a), Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !Gt
Q[a/b, 0]

Rule 6261

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(x_)^(m_.), x_Symbol] :> Int[x^m*((1 + a*x)^(n/2)/(1 - a*x)^(n/2)), x] /; Fre
eQ[{a, m, n}, x] &&  !IntegerQ[(n - 1)/2]

Rubi steps

\begin {align*} \int \frac {e^{\frac {1}{2} \tanh ^{-1}(a x)}}{x^6} \, dx &=\int \frac {\sqrt [4]{1+a x}}{x^6 \sqrt [4]{1-a x}} \, dx\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}+\frac {1}{5} \int \frac {\frac {9 a}{2}+4 a^2 x}{x^5 \sqrt [4]{1-a x} (1+a x)^{3/4}} \, dx\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {1}{20} \int \frac {-\frac {55 a^2}{4}-\frac {27 a^3 x}{2}}{x^4 \sqrt [4]{1-a x} (1+a x)^{3/4}} \, dx\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}+\frac {1}{60} \int \frac {\frac {269 a^3}{8}+\frac {55 a^4 x}{2}}{x^3 \sqrt [4]{1-a x} (1+a x)^{3/4}} \, dx\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{960 x^2}-\frac {1}{120} \int \frac {-\frac {611 a^4}{16}-\frac {269 a^5 x}{8}}{x^2 \sqrt [4]{1-a x} (1+a x)^{3/4}} \, dx\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{960 x^2}-\frac {611 a^4 (1-a x)^{3/4} \sqrt [4]{1+a x}}{1920 x}+\frac {1}{120} \int \frac {465 a^5}{32 x \sqrt [4]{1-a x} (1+a x)^{3/4}} \, dx\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{960 x^2}-\frac {611 a^4 (1-a x)^{3/4} \sqrt [4]{1+a x}}{1920 x}+\frac {1}{256} \left (31 a^5\right ) \int \frac {1}{x \sqrt [4]{1-a x} (1+a x)^{3/4}} \, dx\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{960 x^2}-\frac {611 a^4 (1-a x)^{3/4} \sqrt [4]{1+a x}}{1920 x}+\frac {1}{64} \left (31 a^5\right ) \text {Subst}\left (\int \frac {1}{-1+x^4} \, dx,x,\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{960 x^2}-\frac {611 a^4 (1-a x)^{3/4} \sqrt [4]{1+a x}}{1920 x}-\frac {1}{128} \left (31 a^5\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )-\frac {1}{128} \left (31 a^5\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )\\ &=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{5 x^5}-\frac {9 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{40 x^4}-\frac {11 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{48 x^3}-\frac {269 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{960 x^2}-\frac {611 a^4 (1-a x)^{3/4} \sqrt [4]{1+a x}}{1920 x}-\frac {31}{128} a^5 \tan ^{-1}\left (\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )-\frac {31}{128} a^5 \tanh ^{-1}\left (\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )\\ \end {align*}

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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
time = 0.04, size = 94, normalized size = 0.48 \begin {gather*} -\frac {(1-a x)^{3/4} \left (384+816 a x+872 a^2 x^2+978 a^3 x^3+1149 a^4 x^4+611 a^5 x^5+310 a^5 x^5 \, _2F_1\left (\frac {3}{4},1;\frac {7}{4};\frac {1-a x}{1+a x}\right )\right )}{1920 x^5 (1+a x)^{3/4}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[E^(ArcTanh[a*x]/2)/x^6,x]

[Out]

-1/1920*((1 - a*x)^(3/4)*(384 + 816*a*x + 872*a^2*x^2 + 978*a^3*x^3 + 1149*a^4*x^4 + 611*a^5*x^5 + 310*a^5*x^5
*Hypergeometric2F1[3/4, 1, 7/4, (1 - a*x)/(1 + a*x)]))/(x^5*(1 + a*x)^(3/4))

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {\sqrt {\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}}}{x^{6}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^6,x)

[Out]

int(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^6,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^6,x, algorithm="maxima")

[Out]

integrate(sqrt((a*x + 1)/sqrt(-a^2*x^2 + 1))/x^6, x)

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Fricas [A]
time = 0.35, size = 169, normalized size = 0.86 \begin {gather*} -\frac {930 \, a^{5} x^{5} \arctan \left (\sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}}\right ) + 465 \, a^{5} x^{5} \log \left (\sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} + 1\right ) - 465 \, a^{5} x^{5} \log \left (\sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} - 1\right ) - 2 \, {\left (611 \, a^{5} x^{5} - 73 \, a^{4} x^{4} - 98 \, a^{3} x^{3} - 8 \, a^{2} x^{2} - 48 \, a x - 384\right )} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}}}{3840 \, x^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^6,x, algorithm="fricas")

[Out]

-1/3840*(930*a^5*x^5*arctan(sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1))) + 465*a^5*x^5*log(sqrt(-sqrt(-a^2*x^2 + 1)/(a
*x - 1)) + 1) - 465*a^5*x^5*log(sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1)) - 1) - 2*(611*a^5*x^5 - 73*a^4*x^4 - 98*a^
3*x^3 - 8*a^2*x^2 - 48*a*x - 384)*sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1)))/x^5

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {\frac {a x + 1}{\sqrt {- a^{2} x^{2} + 1}}}}{x^{6}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a**2*x**2+1)**(1/2))**(1/2)/x**6,x)

[Out]

Integral(sqrt((a*x + 1)/sqrt(-a**2*x**2 + 1))/x**6, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^6,x, algorithm="giac")

[Out]

integrate(sqrt((a*x + 1)/sqrt(-a^2*x^2 + 1))/x^6, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\sqrt {\frac {a\,x+1}{\sqrt {1-a^2\,x^2}}}}{x^6} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a*x + 1)/(1 - a^2*x^2)^(1/2))^(1/2)/x^6,x)

[Out]

int(((a*x + 1)/(1 - a^2*x^2)^(1/2))^(1/2)/x^6, x)

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